Buffer Solutions - Lecture Slides | CHEM 112, Study notes of Chemistry

Material Type: Notes; Professor: Hardy; Class: Gen Chem-Sci; Subject: Chemistry; University: University of Massachusetts - Amherst; Term: Unknown 2009;

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We have completed chapter 17 and are moving on to
chapter 18
chapter
18
.
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2
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If we add the same amount of HCl
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which will have the lower pH?
A. Water
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B. Blood
C. They will both be the same
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We have completed chapter 17 and are moving on to chapter 18chapter 18.

  • 6 6 6 662 ... ^1

If we add the same amount of HCl

tto 1 L of water or to 1 L of blood, 1 L f t t 1 L f bl d

which will have the lower pH?

A. Water

2

B. Blood

C. They will both be the same

QUESTION: What is the effect on the pH of addingQUESTION: What is the effect on the pH of adding NHNH 44 Cl to 0.25 M NHCl to 0.25 M NH 33 ((aqaq)?)?

The Common Ion EffectThe Common Ion Effect

NHNH 33 ((aqaq) + H) + H 22 OO โ†”โ†” NHNH 44 ++((aqaq) + OH) + OH--^ ((aqaq))

TheThe pH will gopH will go up (1), down (2), no change (3up (1), down (2), no change (3).).

  • 6 6 6 662 ... ^3

QUESTION: What is the effect on the pH ofQUESTION: What is the effect on the pH of addingadding 0.1M NH0.1M NH 44 ClCl to 0.25 M NHto 0.25 M NH 33 ((aqaq)?)? NHNH 33 ((aqaq) + H) + H 22 OO โ†”โ†” NHNH 44 ++((aqaq)) ++ OHOH--^ ((aqaq))

ConsiderConsider HOAcHOAc//OAcOAc - -^ to see how buffers workto see how buffers work ACIDACID REACTS WITH ADDEDREACTS WITH ADDED OHOH--

Buffer SolutionsBuffer Solutions

OAcOAc - -^ + H+ H 22 OO โ†”โ†” HOAcHOAc ++ OHOH--^ KKbb = 5.6 x= 5.6 x 10 10 - -10^10

Therefore, theTherefore, the reverse reactionreverse reaction of the WEAK ACIDof the WEAK ACID with added OHwith added OH - -

7

withwith added OH added OH hashas KKreversereverse = 1/ K= 1/ Kbb == 1.8 x 101.8 x 10 99 KKreversereverse is VERY LARGE, sois VERY LARGE, so HOAcHOAc completelycompletely consumes _______consumes _______ !!!!!!!!

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ConsiderConsider HOAcHOAc//OAcOAc - -^ to see how buffers workto see how buffers work CONJ. BASECONJ. BASE ADDEDADDED HH++

Buffer SolutionsBuffer Solutions

________________________________

HOAcHOAc + H+ H 22 OO โ†”โ†” OAcOAc - -^ ++ HH 33 OO++^ KKaa == 1.8 x1.8 x 10 10 - -5^5

Therefore, theTherefore, the reverse reactionreverse reaction of the WEAK BASEof the WEAK BASE with added Hwith added H ++ hashas KK = 1/ K= 1/ K == 5 6 x 105 6 x 10 44

8

hashas KKreversereverse = 1/ K= 1/ Kaa == 5.6 x 105.6 x 10 44 KKreversereverse is VERY LARGE, sois VERY LARGE, so OAcOAc - -^ completelycompletely consumesconsumes _______!_______!

Problem:Problem: What is the pH of a buffer that hasWhat is the pH of a buffer that has [[HOAcHOAc] = 0.700 M and [] = 0.700 M and [OAcOAc - -^ ] = 0.600 M?] = 0.600 M? HOAHOAHOAcHOAc + H + HHH O 22 O OO โ†”โ†” OAOAOAOAc c - -^ + H+ HHH O 33 O OO++++ KKaa = 1.8 x 10= 1.8 x 10 - -5^5 0.700 M HOAc has pH = 2. The pH of the buffer will have

9

  1. pH < 2.
  2. pH > 2.
  3. pH = 2.
    • 6 6 6 662 ... 

Problem:Problem: What is the pH of a buffer that hasWhat is the pH of a buffer that has [[HOAcHOAc] = 0.700 M and [] = 0.700 M and [OAcOAc - -^ ] = 0.600 M] = 0.600 M??

HOAcHOAc + H+ H 22 OO โ†”โ†” OAcOAc - -^ ++ HH 33 OO++^ KKaa = 1.8 x 10= 1.8 x 10 - -5^5

Adding an Acid to a BufferAdding an Acid to a Buffer

Problem:Problem: What is the pH when 1.00What is the pH when 1.00 mLmL of 1.00 Mof 1.00 M HClHCl isis added toadded to a)a) 1.00 L of pure water (before1.00 L of pure water (before HClHCl, pH = 7.00), pH = 7.00) b)b) 1.00 L of buffer that has [1.00 L of buffer that has [HOAcHOAc] = 0.700 M and [] = 0.700 M and [OAcOAc--]] = 0.600 M= 0.600 M (pH = 4.68(pH = 4.68))

  • 6 6 6 662 ... ^13

Preparing a BufferPreparing a Buffer

You want to buffer a solution at pH = 4.30.You want to buffer a solution at pH = 4.30. This means [HThis means [H 33 OO++] = 10] = 10 - -pHpH^ == __________________________

Choose anChoose an acid such that [Hacid such that [H 33 OO++] is about equal] is about equal to____(to____(or pHor pH โ‰ˆโ‰ˆ _____)._____). GetGet the exact [Hthe exact [H 33 OO++] by adjusting the ratio of] by adjusting the ratio of acid to conjugate base.acid to conjugate base.

14

j gj g

[H 3 O +^ ] =

[Acid]

[Conj. base]

- K (^) a

You want to buffer a solution at pH = 4.30 orYou want to buffer a solution at pH = 4.30 or [H[H 33 OO++] = 5.0 x 10] = 5.0 x 10 - -5^5 MM

Preparing a BufferPreparing a Buffer

POSSIBLE ACIDSPOSSIBLE ACIDS KKaa HSOHSO 44 - -^ / SO/ SO 442 2--^ 1.2 x 101.2 x 10 - -2^2 HOAcHOAc // OAcOAc - -^ 1.8 x 101.8 x 10 - -5^5 HCN / CNHCN / CN--^ 4 0 x4 0 x 10 10 - -10^10

15

HCNHCN / CN / CN 4.0 x4.0 x 10 10 1010

  • 6 6 6 662 ... 

You want to buffer a solution at pH = 4.30 orYou want to buffer a solution at pH = 4.30 or [H[H 33 OO++] = 5.0 x 10] = 5.0 x 10 - -5^5 MM

Preparing a BufferPreparing a Buffer