calc homework answerkey 2.2, Exercises of Mathematics

calc homework answerkey 2.2 math

Typology: Exercises

2021/2022

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AP#Calculus# # Name:## #
Derivative#at#a#Point#Practice#Date:!! !
The#function#๐’‰(๐’™)#is#differentiable#for#all#values#of#๐’™,#and#selected#values#of#๐’‰#and#๐’‰โ€ฒ#are#
given#in#the#table#below.#
๐’™#
-4!
-1!
2!
5!
๐’‰ ๐’™ #
1!
-2!
0!
7!
๐’‰โ€ฒ ๐’™ #
-7!
3!
2!
0!
1. Write!the!equation!of!the!line!tangent!to!โ„Ž(๐‘ฅ)!at!๐‘ฅ = 2.!
!
!
2. Write!the!equation!of!the!line!to!โ„Ž(๐‘ฅ)!at!๐‘ฅ โˆ’ 4.!
!
!
3. Write!the!equation!of!the!line!tangent!to!โ„Ž(๐‘ฅ)!at!๐‘ฅ = โˆ’1.!
!
!
4. Write!the!equation!of!the!line!normal!to!โ„Ž(๐‘ฅ)!at!๐‘ฅ = 5.!
!
!
For#each#function#๐’‡#and#value#๐’„,#find#๐’‡โ€ฒ(๐’„).#
5.!๐‘“ ๐‘ฅ = 5๐‘ฅ5โˆ’ ๐‘ฅ!,!๐‘ = 2!
6.!๐‘“ ๐‘ฅ = 7๐‘ฅ โˆ’ 6!,!๐‘ = 8!
7.!๐‘“ ๐‘ฅ = 2 + 9๐‘ฅ โˆ’ ๐‘ฅ5!,!๐‘ = 4!
8.!๐‘“ ๐‘ฅ = ;
<=><!,!๐‘ = โˆ’1!
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AP Calculus Name: Derivative at a Point Practice Date: The function ๐’‰(๐’™) is differentiable for all values of ๐’™ , and selected values of ๐’‰ and ๐’‰โ€ฒ are given in the table below. ๐’™ - 4 - 1 2 5 ๐’‰ ๐’™ 1 - 2 0 7 ๐’‰โ€ฒ ๐’™ - 7 3 2 0

  1. Write the equation of the line tangent to โ„Ž(๐‘ฅ) at ๐‘ฅ = 2.
  2. Write the equation of the line to โ„Ž(๐‘ฅ) at ๐‘ฅ โˆ’ 4.
  3. Write the equation of the line tangent to โ„Ž(๐‘ฅ) at ๐‘ฅ = โˆ’ 1.
  4. Write the equation of the line normal to โ„Ž(๐‘ฅ) at ๐‘ฅ = 5. For each function ๐’‡ and value ๐’„ , find ๐’‡โ€ฒ(๐’„).
  5. ๐‘“ ๐‘ฅ = 5 ๐‘ฅ^5 โˆ’ ๐‘ฅ , ๐‘ = (^2) 6. ๐‘“ ๐‘ฅ = 7 ๐‘ฅ โˆ’ 6 , ๐‘ = 8
  6. ๐‘“ ๐‘ฅ = 2 + 9 ๐‘ฅ โˆ’ ๐‘ฅ^5 , ๐‘ = (^4) 8. ๐‘“ ๐‘ฅ = ; <=><

For the following, find the equation of the line tangent to the function at the given point.

  1. ๐‘“ ๐‘ฅ = 6 ๐‘ฅ^5 , ๐‘ = โˆ’ 2 10. ๐‘š 1 = 2 ๐‘š@^1 = โˆ’ 8
  2. โ„Ž โˆ’ 3 = โˆ’ 5 โ„Ž@^ โˆ’ 3 = 7
    1. ๐‘˜ ๐‘ฅ = ๐‘ฅ sin ๐‘ฅ ๐‘˜@^ ๐‘ฅ = sin ๐‘ฅ + ๐‘ฅ cos ๐‘ฅ ๐‘ฅ = ๐œ‹
  3. ๐‘” ๐‘ฅ = 4 ๐‘ฅ + 9 , ๐‘ = 10 14.^ ๐‘ ^ ๐‘ฅ^ =^ tan(^2 ๐‘ฅ) ๐‘ @^ ๐‘ฅ = 2 sec^5 ( 2 ๐‘ฅ) ๐‘ฅ =