Arshiya
sah
quiz
3
iimf(x
+
h)
-
(x)
f(x)
=
2
X
-
3/5
_
n
co
1)
Find
derivative
using
limit
definition
of
the
derivative
x+)-2x-4)
=
y2*
f(x)
=
12
2)
Find
derivative
using
limit
definition
of
the
derivative
f(x)
=
3x2
-
3x
+
7
f(x
+
h)
-
f(x)
I
n
so
C
S(xt)"
-
3(x+)
+7
-
(x23x
+
7)36xn+h25x-3h7-
545
liM
n
A
↳
↳
(A)6x+
h
-
3)
=
6xh
+
2
34
lim
(X
+
h)(X
+
n)
=
n
so
6xth-3
3(x2
+
2x4
+
2)
H
f(x)
=
6
x
-
3
=
3x
6xh
+
2
3)
Find
derivative
using
limit
definition
of
the
derivative
(Xr)/2
-(x
+
n)
f(x)
=
(x
+
1)
lim
G(x+h)
-
f(x)
(X+)H
_
(X
+)
((X
+
n)
+
1)(2
-
x)
2
x
-
x2
x4
+
2
-x-h
12
-
x)
n
I
12
-(X
+)
12
-x)
2x+2h
+
2
-x2
xh
-x
=
-
x
+
xrz-xh
-h
n
so
=
-
x
+
x
+
2
-
xh
+
2h
-34
-
h
=
3
*
**-
XhrCh
+
x-2hth
12
-
(x
+
h)/2
-
x))
(1
-
cxm)12-x))
·
=
1
-
x+31-x))
-34
3
3
lim
12
-(x
+
h)(2
-
x))
h
-
02
-(x
+
0)12
-
x)
=
12
-
x)2
4)
Find
the
equation
or
a
line
tangent
to
the
function
y
=
x-3x+2
9
(3,2)
f(x
+
h)
-
f(x)
>(Xt)"
3(X+h)
+2
-(x
3
-
3x
+
2)
(Xth)
(X+)
1IM
n
U
(x
rxh
+
2)(X+h)
n
so
x3
+
2x2
+
2x2
xh+
2x3
=
A
+
3x2h
+
4x2
+
3
-
5x
-
3h+2
-
x3
+
5x
-
im
(n23
x
2
4xh-
)
slope
of
X
=
3
↳
h3+3x2h
+
4x2-
34
-
3x
2
-
3
-
3(X21)
=
f1(3)
=
240Spoint
(3,2)
-k(n2
+
3
x
2
+
4xn
-3)/A
+(3)
=
(im
+13+h)-f
(3)
essentially
just
I
equations-the
"Gala?
IX-n)
=
a
represent
te
we
use
when
solving
k
plug
in
3
X-Valu e
aua
f(a)
same
as
f(x)
slope
point
5)
Find
the
equation
or
a
line
tangent
to
the
function
y
=
-4x+7x29xH2
9
(1,6)
in
slope
-
intercept
form
11m
f(x+h)
-
f(x)
-
-
Y(Xth)
+
f(X
+
h)
-
q(X
+
h)
+
12
-
(
-
4x3
+
7x
2
9x
+
2)
n
so
n
·
4x
-
xhotx2
x
e
(x
+
h)(Xth)
>
lim-12x2
14
x
(x2
xhrn2)
(Xth)
A
->
f((1)
=
-12
+14
-
9
x
rxh+xh2
+
x2
h
+
2x42
73
i
next
hindb)
=
-
F
-(3xh
+
3x
nY).
4)
y
=
mx
+
b
-
6
=
-
f())
+
b
-
=
13
-
4x3-12x2h-12x42-443
y
=
13
-
7X