Calculus 2 - Assignment 10 with Solution | MATH 211, Assignments of Calculus

Material Type: Assignment; Class: Calculus 2; Subject: Mathematics; University: Millersville University of Pennsylvania; Term: Spring 2006;

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Millersville University Name Answer Key
Department of Mathematics
MATH 211, Homework 10
April 7, 2006
Page 694, Exercise 34
(a) Use a Taylor polynomial of degree 4 to approximate ln(0.9).
Suppose f0(x) = 1
x, then we can express this function as a Taylor series centered at c= 1.
f0(x) = 1
x
=1
1 + xโˆ’1
=1
1โˆ’(1 โˆ’x)
=
โˆž
X
k=0
(1 โˆ’x)k
=
โˆž
X
k=0
(โˆ’1)k(xโˆ’1)k
which converges absolutely if |xโˆ’1|<1. Since d
dx (ln x) = f0(x), then
f(x) = ln x=
โˆž
X
k=0
(โˆ’1)k
k+ 1 (xโˆ’1)k+1 .
The Taylor polynomial of degree 4 will be denoted P4(x) with
P4(x) = (xโˆ’1) โˆ’1
2(xโˆ’1)2+1
3(xโˆ’1)3โˆ’1
4(xโˆ’1)4.
Thus ln(0.9) โ‰ˆP4(0.9) โ‰ˆ โˆ’0.105358.
(b) Estimate the error in the approximation.
The maximum error in the approximation is described by the maximum magnitude of the Taylor
remainder when n= 4.
R4(0.9) = f(5)(z)
5! (0.9โˆ’1)5
=24
z5ยท1
120(โˆ’0.1)5
=1
5z5(โˆ’0.1)5
where 0.9<z<1. The magnitude of the error is maximized when z= 0.9 and thus the error is no
more than
|R4(0.9)| โ‰ค ๎˜Œ
๎˜Œ
๎˜Œ
๎˜Œ
1
5(0.9)5(โˆ’0.1)5๎˜Œ
๎˜Œ
๎˜Œ
๎˜Œ
โ‰ˆ3.38702 ร—10โˆ’6.
(c) Estimate the number of terms needed in a Taylor polynomial to guarantee an accuracy of 10โˆ’10.
pf2

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Millersville University Name Answer Key

Department of Mathematics

MATH 211, Homework 10

April 7, 2006

Page 694, Exercise 34

(a) Use a Taylor polynomial of degree 4 to approximate ln(0.9).

Suppose f

โ€ฒ (x) =

1 x , then we can express this function as a Taylor series centered at c = 1.

f

โ€ฒ (x) =

x

1 + x โˆ’ 1

1 โˆ’ (1 โˆ’ x)

โˆž โˆ‘

k=

(1 โˆ’ x)

k

โˆž โˆ‘

k=

k (x โˆ’ 1)

k

which converges absolutely if |x โˆ’ 1 | < 1. Since

d dx (ln x) = f

โ€ฒ (x), then

f (x) = ln x =

โˆž โˆ‘

k=

k

k + 1

(x โˆ’ 1)

k+ .

The Taylor polynomial of degree 4 will be denoted P 4 (x) with

P 4 (x) = (x โˆ’ 1) โˆ’

(x โˆ’ 1)

2

(x โˆ’ 1)

3 โˆ’

(x โˆ’ 1)

4 .

Thus ln(0.9) โ‰ˆ P 4 (0.9) โ‰ˆ โˆ’ 0 .105358.

(b) Estimate the error in the approximation.

The maximum error in the approximation is described by the maximum magnitude of the Taylor

remainder when n = 4.

R 4 (0.9) =

f

(5) (z)

5

z 5

5

5 z 5

5

where 0. 9 < z < 1. The magnitude of the error is maximized when z = 0.9 and thus the error is no

more than

|R 4 (0.9)| โ‰ค

5

5

โ‰ˆ 3. 38702 ร— 10

โˆ’ 6 .

(c) Estimate the number of terms needed in a Taylor polynomial to guarantee an accuracy of 10

โˆ’ 10 .

In general the Taylor remainder has the form

Rn(0.9) =

f

(n+1) (z)

(n + 1)!

n+

n+

(n + 1)z n+

n+

with 0. 9 < z < 1. The magnitude of the error is maximized when z = 0.9 and thus the error is no

more than

|Rn(0.9)| โ‰ค

(n + 1)(0.9) n+

n+

By trial and error we can see that when n โ‰ฅ 9 then |Rn(0.9)| < 10

โˆ’ 10 .

Page 702, Exercise 20

Use a Taylor polynomial with n = 5 nonzero terms to approximate the value of the integral

1

0

tan

โˆ’ 1 x dx.

We know that the Maclaurin series for tan

โˆ’ 1 x can be expressed as

tan

โˆ’ 1 x =

โˆž โˆ‘

k=

k

2 k + 1

x

2 k+ .

Thus the Maclaurin polynomial of degree 5 is

P 5(x) = x โˆ’

x 3

x 5

x 7

x 9

Thus

0

tan

โˆ’ 1 x dx โ‰ˆ

0

x โˆ’

x

3

x

5

x

7

x

9

dx

x

2

x

4

x

6

x

8

x

10

1

0

Note that the exact value of the original integral is

1

0

tan

โˆ’ 1 x dx =

(ฯ€ โˆ’ ln 4) โ‰ˆ 0. 438825.