

Study with the several resources on Docsity
Earn points by helping other students or get them with a premium plan
Prepare for your exams
Study with the several resources on Docsity
Earn points to download
Earn points by helping other students or get them with a premium plan
Material Type: Assignment; Class: Calculus 2; Subject: Mathematics; University: Millersville University of Pennsylvania; Term: Spring 2006;
Typology: Assignments
1 / 2
This page cannot be seen from the preview
Don't miss anything!


Millersville University Name Answer Key
Department of Mathematics
MATH 211, Homework 10
April 7, 2006
(a) Use a Taylor polynomial of degree 4 to approximate ln(0.9).
Suppose f
โฒ (x) =
1 x , then we can express this function as a Taylor series centered at c = 1.
f
โฒ (x) =
x
1 + x โ 1
1 โ (1 โ x)
โ โ
k=
(1 โ x)
k
โ โ
k=
k (x โ 1)
k
which converges absolutely if |x โ 1 | < 1. Since
d dx (ln x) = f
โฒ (x), then
f (x) = ln x =
โ โ
k=
k
k + 1
(x โ 1)
k+ .
The Taylor polynomial of degree 4 will be denoted P 4 (x) with
P 4 (x) = (x โ 1) โ
(x โ 1)
2
(x โ 1)
3 โ
(x โ 1)
4 .
Thus ln(0.9) โ P 4 (0.9) โ โ 0 .105358.
(b) Estimate the error in the approximation.
The maximum error in the approximation is described by the maximum magnitude of the Taylor
remainder when n = 4.
f
(5) (z)
5
z 5
5
5 z 5
5
where 0. 9 < z < 1. The magnitude of the error is maximized when z = 0.9 and thus the error is no
more than
5
5
โ 6 .
(c) Estimate the number of terms needed in a Taylor polynomial to guarantee an accuracy of 10
โ 10 .
In general the Taylor remainder has the form
Rn(0.9) =
f
(n+1) (z)
(n + 1)!
n+
(n + 1)z n+
n+
with 0. 9 < z < 1. The magnitude of the error is maximized when z = 0.9 and thus the error is no
more than
|Rn(0.9)| โค
(n + 1)(0.9) n+
n+
By trial and error we can see that when n โฅ 9 then |Rn(0.9)| < 10
โ 10 .
Use a Taylor polynomial with n = 5 nonzero terms to approximate the value of the integral
1
0
tan
โ 1 x dx.
We know that the Maclaurin series for tan
โ 1 x can be expressed as
tan
โ 1 x =
โ โ
k=
k
2 k + 1
x
2 k+ .
Thus the Maclaurin polynomial of degree 5 is
P 5(x) = x โ
x 3
x 5
x 7
x 9
Thus
0
tan
โ 1 x dx โ
0
x โ
x
3
x
5
x
7
x
9
dx
x
2
x
4
x
6
x
8
x
10
1
0
Note that the exact value of the original integral is
1
0
tan
โ 1 x dx =
(ฯ โ ln 4) โ 0. 438825.