Alternating Series Test, Thesis of Business Accounting

The Alternating Series Test and its three conditions. It provides an example of an infinite series and justifies that each condition is true for the series using algebra and calculus. The test is used to determine if an infinite series converges or diverges. mathematical equations and notation.

Typology: Thesis

2023/2024

Available from 01/17/2024

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Task #4: Alternating Series Test
Task #4: Alternating Series Test
j=1
(−1)j1
(j+c)
c= 2*birth month +5=2*6+5=17
j=1
(−1)j1
(j+17)
A) State thethreeconditions of the alternating series test.
1. The
Un
's
are all positive
2. The positive
Un
's
are (eventually) Nonincreasing
Un
U n+1
for all n
N
, for some
integer N.
3.
B) Justify thateachcondition of the alternating series test from part A is true for the infinite
series in the Assumptions section, using algebra or calculus or both.
1. The
Un
's
are all positive
-The numerator is positive 1 and so it will stay positive.
-The denominator is
j+17
and will always be greater than zero when j
1
. So the
denominator will positive. Since the numerator is positive and the denominator is positive
the
Un
's
are all positive.
2. We must determine if the function is nonincreaing and to do that we must show that
the derivative is negative.
f
(
j
)
=1
j+17
¿1
(
j+17
)
(1
2)
=
(
j+17
)
(1
2)
let u=(j+17)
Apply the chain rule:
d
du
(
u
1
2
)
(
d
dj
)
(j+17)
Apply the power rule and simplify:
(u¿¿1
21)=1
2u
3
2¿
=
1
2u
3
2
Apply the sum rule
d
dj
(
j+17
)
=1
pf2

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Task #4: Alternating Series Test

Task #4: Alternating Series Test

j = 1

j

√( j + c )

c= 2birth month +5=26+5=

j = 1

j

( j + 17 )

A) State the three conditions of the alternating series test.

  1. The U

n

'

s

are all positive

  1. The positive U

n

'

s are (eventually) Nonincreasing

U

n

≥ U

n + 1

for all n ≥ N , for some

integer N.

U

n

B) Justify that each condition of the alternating series test from part A is true for the infinite

series in the Assumptions section, using algebra or calculus or both.

  1. The U

n

'

s are all positive

-The numerator is positive 1 and so it will stay positive.

-The denominator is

j + 17

and will always be greater than zero when j 1. So the

denominator will positive. Since the numerator is positive and the denominator is positive

the U

n

'

s

are all positive.

  1. We must determine if the function is nonincreaing and to do that we must show that

the derivative is negative.

f

( j )

j + 17

j + 17

(

1

2

)

=

j + 17

(

− 1

2

)

let u=(j+17)

Apply the chain rule:

d

du

u

− 1

2

d

dj

( j + 17 )

Apply the power rule and simplify:

( u ¿

u

− 3

2

2 u

3

2

Apply the sum rule

d

dj

( j + 17 )= 1

=

2 u

3

2

*1 =

j + 17

3

2

=

2 √( j + 17 )

3

So the numerator is always negative, and

denominator is positive at j 1 and raising it to the

and multiplying it by 2 will still be

positive. So the numerator is negative and the denominator is positive so we can conclude

that the function is nonincreasing.

U

n

lim

j → ∞

lim

j → ∞

lim

j → ∞

j + 17 )

= As j goes to infinity

j + 17

will go to infinity (

=

= 0 So as j goes to infinity the series goes to zero.

C) Determine the convergence or divergence of the infinite series in the Assumptions section,

according to the results of the alternating series test.

-Since the series meets all conditions, therefore the series converges by the Alternating Series

Test.