Calculus formula for engineers, Exams of Calculus for Engineers

calculus formula........................................................................

Typology: Exams

2019/2020

Uploaded on 05/14/2020

emir-imran-tan-bin-amir-tan
emir-imran-tan-bin-amir-tan 🇲🇾

1 document

1 / 5

Toggle sidebar

This page cannot be seen from the preview

Don't miss anything!

bg1
MATH1020 Calculus for Engineers Formulae page 1 of 5
LOGARITHMS & EXPONENTIALS
logax=y ay=x, loga(xy) = logax+ logay, logax
y= logaxlogay
loga(xr) = rloga(x),loga(ax) = x, alogax=x
(ab)c=abc, abac=ab+c, ab=1
ab
TRIG & HYPERBOLIC IDENTITIES
sin2θ+ cos2θ= 1, tan2θ+ 1 = sec2θ, 1 + cot2θ= csc2θ
sin2θ=1
2(1 cos 2θ), cos2θ=1
2(1 + cos 2θ)
sin 2θ= 2 sin θcos θ, cos 2θ= cos2θsin2θ, tan 2θ=2 tan θ
1tan2θ
sin Acos B=1
2[sin(A+B) + sin(AB)]
cos Acos B=1
2[cos(A+B) + cos(AB)]
sin Asin B=1
2[cos(AB)cos(A+B)]
sin A+ sin B= 2 sin 1
2(A+B) cos 1
2(AB)
sin Asin B= 2 cos 1
2(A+B) sin 1
2(AB)
cos A+ cos B= 2 cos 1
2(A+B) cos 1
2(AB)
cos Acos B= 2 sin 1
2(A+B) sin 1
2(BA)
sin(A±B) = sin Acos B±cos Asin B
cos(A±B) = cos Acos Bsin Asin B
tan(A±B) = tan A±tan B
1tan Atan B
cosh2xsinh2x= 1, tanh2x= 1 sech 2x, coth2x= 1 + csch 2x
cosh2x=1
2(cosh 2x+ 1), sinh2x=1
2(cosh 2x1)
sinh 2x= 2 sinh xcosh x, cosh 2x= cosh2x+ sinh2x
1
pf3
pf4
pf5

Partial preview of the text

Download Calculus formula for engineers and more Exams Calculus for Engineers in PDF only on Docsity!

LOGARITHMS & EXPONENTIALS

loga x = y ⇐⇒ ay^ = x, loga(xy) = loga x + loga y, loga

x y

= loga x − loga y

loga(xr) = r loga(x), loga(ax) = x, aloga^ x^ = x

(ab)c^ = abc, abac^ = ab+c, a−b^ =

ab

TRIG & HYPERBOLIC IDENTITIES

sin^2 θ + cos^2 θ = 1, tan^2 θ + 1 = sec^2 θ, 1 + cot^2 θ = csc^2 θ

sin^2 θ = 12 (1 − cos 2θ), cos^2 θ = 12 (1 + cos 2θ)

sin 2θ = 2 sin θ cos θ, cos 2θ = cos^2 θ − sin^2 θ, tan 2θ = 2 tan θ 1 − tan^2 θ sin A cos B = 12 [sin(A + B) + sin(A − B)]

cos A cos B = 12 [cos(A + B) + cos(A − B)]

sin A sin B = 12 [cos(A − B) − cos(A + B)]

sin A + sin B = 2 sin 12 (A + B) cos 12 (A − B)

sin A − sin B = 2 cos 12 (A + B) sin 12 (A − B)

cos A + cos B = 2 cos 12 (A + B) cos 12 (A − B)

cos A − cos B = 2 sin 12 (A + B) sin 12 (B − A)

sin(A ± B) = sin A cos B ± cos A sin B

cos(A ± B) = cos A cos B ∓ sin A sin B

tan(A ± B) = tan A ± tan B 1 ∓ tan A tan B cosh^2 x − sinh^2 x = 1, tanh^2 x = 1 − sech 2 x, coth^2 x = 1 + csch 2 x

cosh^2 x = 12 (cosh 2x + 1), sinh^2 x = 12 (cosh 2x − 1)

sinh 2x = 2 sinh x cosh x, cosh 2x = cosh^2 x + sinh^2 x

HYPERBOLIC FUNCTIONS

sinh x = ex^ − e−x 2 , cosh x = ex^ + e−x 2 , tanh x = sinh x cosh x csch x =

sinh x , sech x =

cosh x , coth x = cosh x sinh x

sinh−^1 x = ln(x +

x^2 + 1), cosh−^1 x = ln(x +

x^2 − 1), tanh−^1 x =

ln

1 + x 1 − x

STANDARD ANGLES

θ (rad) 0

π 6

π 4

π 3

π 2 sin θ 0

√^1

cos θ 1

INVERSE TRIGONOMETRIC FUNCTIONS

sin−^1 (sin x) = x, for all x ∈

[

−π 2 , π 2

]

sin(sin−^1 x) = x, for all x ∈ [− 1 , 1]

cos−^1 (cos x) = x, for all x ∈ [0, π]

cos(cos−^1 x) = x, for all x ∈ [− 1 , 1]

tan−^1 (tan x) = x, for all x ∈

−π 2 , π 2

tan(tan−^1 x) = x, for all x

csc−^1 (csc x) = x, for all x ∈

0 , π 2

]

π, 32 π

]

csc(csc−^1 x) = x, for all |x| ≥ 1

sec−^1 (sec x) = x, for all x ∈

[

0 , π 2

[

π, 32 π

sec(sec−^1 x) = x, for all |x| ≥ 1

cot−^1 (cot x) = x, for all x ∈ (0, π)

cot(cot−^1 x) = x, for all x ∈ R

STANDARD DERIVATIVES

d dx (uv) = v du dx

  • u dv dx

d dx

(u v

v dudx − u dvdx v^2

dy dx

dy du

du dx d dx (sin x) = cos x, d dx (cos x) = − sin x, d dx (tan x) = sec^2 x d dx (sec x) = sec x tan x, d dx (csc x) = − csc x cot x, d dx (cot x) = − csc^2 x d dx

(sin−^1 x) =

1 − x^2

d dx

(cos−^1 x) = −

1 − x^2

d dx

(tan−^1 x) =

1 + x^2 d dx (sec−^1 x) =

x

x^2 − 1

d dx (csc−^1 x) = −

x

x^2 − 1

d dx (cot−^1 x) = −

1 + x^2 d dx (sinh x) = cosh x, d dx (cosh x) = sinh x, d dx (tanh x) = sech 2 x d dx (sech x) = −sech x tanh x, d dx (csch x) = −csch x coth x, d dx (coth x) = −csch 2 x d dx (sinh−^1 x) =

1 + x^2

d dx (cosh−^1 x) =

x^2 − 1

d dx (tanh−^1 x) =

1 − x^2 d dx (sech −^1 x) = −

x

1 − x^2

d dx (csch −^1 x) = −

|x|

x^2 + 1

d dx (coth−^1 x) =

1 − x^2

TAYLOR SERIES

f (x) =

∑^ ∞

n=

f (n)(a) n!

(x − a)n^ = f (a) + f ′(a)(x − a) + f ′′(a) 2!

(x − a)^2 + f ′′′(a) 3!

(x − a)^3 +...

Pn(x) = f (a) + f ′(a)(x − a) + f ′′(a) 2! (x − a)^2 + f ′′′(a) 3! (x − a)^3 +... + f (n)(a) n! (x − a)n

f (x) = Pn(x) + Rn(x), Rn(x) = f (n+1)(c) (n + 1)! (x − a)n+1, c ∈ (a, x)

NUMERICAL INTEGRATION

T =

h 2

(y 0 + 2y 1 + 2y 2 +... + 2yn− 1 + yn), | ET |≤ (b − a) 12

h^2 M

S =

h 3

(y 0 + 4y 1 + 2y 2 + 4y 3 +... + 2yn− 2 + 4yn− 1 + yn), | ES |≤ (b − a) 180 h^4 M

NUMERICAL ROOT FINDING ALGORITHMS

Bisection method ([a,b] contains root): error ≤ b − a 2 n Newton’s Method: xn+1 = xn − f (xn) f ′(xn)

STANDARD INTEGRALS

u dv = uv −

v du,

∫ (^) b

a

f (u(x)) du dx dx =

∫ (^) u(b)

u(a)

f (u) du ∫ f ′(u) f (u) du = ln |f (u)| + C,

(f (u))n^ f ′(u) du =

(f (u))n+ n + 1

+ C

sin u du = − cos u + C,

cos u du = sin u + C,

sec^2 u du = tan u + C ∫ tan u du = ln | sec u| + C,

tanh u du = ln(cosh u) + C ∫ cot u du = ln | sin u| + C,

coth u du = ln | sinh u| + C ∫ sec u du = ln | sec u + tan u| + C,

sech u du = tan−^1 | sinh u| + C ∫ csc u du = ln | csc u − cot u| + C,

csch u du = ln | tanh u 2 | + C ∫ du a^2 − u^2

2 a ln

∣∣^ u^ +^ a u − a

∣∣ + C,

du u^2 − a^2

2 a ln

∣∣^ u^ −^ a u + a

∣∣ + C

∫ (^) du √ a^2 − u^2

= sin−^1

(u a

+ C,

du a^2 + u^2

a

tan−^1

(u a

+ C

∫ (^) du

u

u^2 − a^2

a sec−^1

(u a

+ C

∫ (^) du √ u^2 + a^2

= sinh−^1

(u a

  • C = ln |u +

u^2 + a^2 | + C ∫ (^) du √ u^2 − a^2

= cosh−^1

(u a

  • C = ln |u +

u^2 − a^2 | + C ∫ (^) du

u

a^2 − u^2

a sech −^1

(u a

+ C = −

a ln

∣∣^ a^ +^

a^2 − u^2 u

∣∣ + C

LENGTHS OF CURVES AND SURFACES OF

REVOLUTION

L =

∫ (^) b

a

dy dx

dx =

∫ (^) d

c

dx dy

dy =

ds

rotation around x-axis: S =

∫ (^) b

a

2 πy

dy dx

dx =

∫ (^) d

c

2 πy

dx dy

dy

rotation around y-axis: S =

∫ (^) d

c

2 πx

dx dy

dy =

∫ (^) b

a

2 πx

dy dx

dx