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All questions has been answered with computation. OBJECTIVES • To carry out basic calorimetry experiments. • To compute the specific heat of an unknown metal using calorimetry results. • Calorimetry measurements were used to determine the heat of reaction (H).
Typology: Lab Reports
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Material Heat, q (experimental) Specific heat, c (experimental) Specific heat, c (theoretical) %Error Copper (Metal 1)
(q)water = (-q)metal To get the (q)uarter, use this formula: (q)warter = [(m)water][(c)water)[(∆T)water]
= - 58,391,175 J/57.99g(201.85 K) (∆T)metal = - 71.3 °C = - 58,391,175 J/11,705,29 g(K) (q)metal = - 58,391,175 J (c)metal = - 4,988,447J/g(K) Solution for Metal 2(Zinc) (q)water = (-q)metal (q)water = [(m)water][(c)water][(∆T)water) = (50 g)[4,182 J/g(K)](279.55 K) (q)water = 58,453,905 J Thus, (q)metal would be - 58,453,905 J Formula for finding the (c)metal: (c)metal = (q)metal/(m∆T) = - 58,453,905 J/57.97 g(202.15 K/) = - 58,453,905 J/11,718.636 g/K (c)metal = - 4,988.115 J/g(K) Finding the (%)Error: Formula: (%)Error = Theoretical Experimental/Theoretical(100) = 0.387 J/g(K) - (-4,988.115 J/g(K)/0.387. J/g(K) = 4,988.502 J/g(K)/.387. J/g(K) = 12,890.186(100) (%)Error = 1,289,018. Solution for Metal 3(Tin) (q)water = (-q)metal (q)water = [(m)water][(c)water][(∆T)water) = (50 g)[4,182 J/g(K)](277.55 K) (q)water = 58,035,705 J - Thus, (q)metal would be - 58,035,705 J