Ch. 9 Chemistry Practice Questions: Hybridization and Bonding, Lecture notes of Chemistry

Practice questions on the topics of hybridization and bonding in chemistry. Students can use these questions to test their understanding of sp, sp2, and sp3 hybridization, pi and sigma bonds, and molecular orbital theory.

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Ch. 9 Practice Questions
1. The hybridization of the
carbon
atom in the cation
C
H
3+
is:
A) sp
2
B) sp
3
C) dsp
D) sp
E) none of these
2. In the molecule C
2
H
4
the valence orbitals of the carbon atoms are assumed to be
A) not hybridized
B) sp hybridized
C) sp
2
hybridized
D) sp
3
hybridized
E) dsp hybridized
3. The hybridization of the central atom in I
3
is:
A) sp
B) sp
2
C) sp
3
D) dsp
3
E) d
2
sp
3
4. Consider the following Lewis structure:
Which statement about the molecule is false?
A) There are 10 sigma and 2 pi bonds.
B) C-2 is sp
2
hybridized with bond angles of 120°.
C) Oxygen is sp
3
hybridized.
D) This molecule contains 28 valence electrons.
E) There are some H–C–H bond angles of about 109° in the molecule.
5. The hybridization of the central atom, Al, in AlBr
3
is
A) sp
B) sp
2
C) sp
3
D) dsp
3
E) d
2
sp
3
pf3
pf4
pf5
pf8
pf9
pfa
pfd
pfe

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Ch. 9 Practice Questions

  1. The hybridization of the carbon atom in the cation CH 3 +^ is: A) sp^2 B) sp^3 C) dsp D) sp E) none of these
  2. In the molecule C 2 H 4 the valence orbitals of the carbon atoms are assumed to be A) not hybridized B) sp hybridized C) sp^2 hybridized D) sp^3 hybridized E) dsp hybridized
  3. The hybridization of the central atom in I 3 –^ is: A) sp B) sp^2 C) sp^3 D) dsp^3 E) d^2 sp^3
  4. Consider the following Lewis structure:

Which statement about the molecule is false? A) There are 10 sigma and 2 pi bonds. B) C-2 is sp^2 hybridized with bond angles of 120°. C) Oxygen is sp^3 hybridized. D) This molecule contains 28 valence electrons. E) There are some H–C–H bond angles of about 109° in the molecule.

  1. The hybridization of the central atom, Al, in AlBr 3 is A) sp B) sp^2 C) sp^3 D) dsp^3 E) d^2 sp^3
  1. In which of the compounds below is there more than one kind of hybridization ( sp , sp^2 , sp^3 ) for carbon? I. CH 3 CH 2 CH 2 CH 3 II. CH 3 CH = CHCH 3 III. CH 2 = CH – CH = CH 2 IV. H – C ≡ C – H

A) II and III B) II only C) III and IV D) I, II, and III E) III only

  1. A π (pi) bond is the result of the A) overlap of two s orbitals B) overlap of an s orbital and a p orbital C) overlap of two p orbitals along their axes D) sidewise overlap of two parallel p orbitals E) sidewise overlap of two s orbitals

Consider the skeletal structure shown below: N—C—C—N Draw the Lewis structure and answer the following:

  1. How many of the atoms are sp hybridized? A) 0 B) 1 C) 2 D) 3 E) 4
  2. How many pi bonds does the molecule contain? A) 0 B) 2 C) 4 D) 6 E) 7
  3. Which of the following molecules contains the shortest C–C bond? A) C 2 H 2 B) C 2 H 4 C) C 2 H 6 D) C 2 Cl 4 E) b and d
  1. Which of the following species is paramagnetic? A) C 2 B) O 2 C) F 2 D) Li 2 E) none of these
  2. Which of the following species has the largest dissociation energy? A) O 2 B) O 2 – C) O 2 2– D) O 2 + E) O 2 2+
  3. Which of the following diatomic molecules has a bond order of 2? A) B 2 B) C 2 C) P 2 D) F 2 E) Li 2
  4. Consider the molecular orbital energy level diagrams for O 2 and NO. Which of the following is true? I. Both molecules are paramagnetic. II. The bond strength of O 2 is greater than the bond strength of NO. III. NO is an example of a homonuclear diatomic molecule. IV. The ionization energy of NO is smaller than the ionization energy of NO+.

A) I only B) I and II C) I and IV D) II and III E) I, II, and IV

  1. The hybridization of the lead atom in PbCl 4 is

A) dsp^2 B) sp^2 C) d^2 sp^3 D) dsp^3 E) none of these

ID: A

Ch. 9 Practice Questions

Answer Section

1. ANS: A REF: 9.

KEY: Chemistry | general chemistry | bonding | bonding theories | hybridization

  1. ANS: C REF: 9. KEY: Chemistry | general chemistry | bonding | bonding theories | hybridization
  2. ANS: D REF: 9. KEY: Chemistry | general chemistry | bonding | bonding theories | hybridization
  3. ANS: C REF: 9. KEY: Chemistry | general chemistry | bonding | bonding theories
  4. ANS: B REF: 9. KEY: Chemistry | general chemistry | bonding | bonding theories | hybridization
  5. ANS: B REF: 9. KEY: Chemistry | general chemistry | bonding | bonding theories | hybridization
  6. ANS: D REF: 9. KEY: Chemistry | general chemistry | bonding | bonding theories | multiple bonding
  7. ANS: E REF: 9. KEY: Chemistry | general chemistry | bonding | bonding theories | hybridization
  8. ANS: C REF: 9. KEY: Chemistry | general chemistry | bonding | bonding theories | multiple bonding
  9. ANS: A REF: 9. KEY: Chemistry | general chemistry | bonding | bonding theories | molecular orbital theory | bond order
  10. ANS: D REF: 9. KEY: Chemistry | general chemistry | bonding | bonding theories | molecular orbital theory | bond order
  11. ANS: B REF: 9. KEY: Chemistry | general chemistry | bonding | bonding theories | molecular orbital theory | bond order
  12. ANS: C REF: 9. KEY: Chemistry | general chemistry | bonding | bonding theories | molecular orbital theory
  13. ANS: C REF: 9. KEY: Chemistry | general chemistry | bonding | bonding theories | diatomic molecule
  14. ANS: C REF: 9. KEY: Chemistry | general chemistry | bonding | bonding theories | diatomic molecule
  15. ANS: B REF: 9. KEY: Chemistry | general chemistry | bonding | bonding theories | diatomic molecule
  16. ANS: E REF: 9. KEY: Chemistry | general chemistry | bonding | bonding theories | molecular orbital theory | bond order
  17. ANS: B REF: 9. KEY: Chemistry | general chemistry | bonding | bonding theories | diatomic molecule
  18. ANS: C REF: 9. KEY: Chemistry | general chemistry | bonding | bonding theories | diatomic molecule
  19. ANS: E REF: 9. KEY: Chemistry | general chemistry | bonding | bonding theories | hybridization