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These mole ratios are used to solve problems such as how many moles of carbon dioxide, CO2, would be produced from 6.25 moles of oxygen gas? Solution: 6.25 ...
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Stoichiometry (STOY-key-OM-etry) problems are based on quantitative relationships between the different substances involved in a chemical reaction.
The coefficients in a balanced equation given the moles of each substance in that equation. For the combination reaction of hydrogen gas and nitrogen gas to produce ammonia, the coefficients give us valuable information about the reaction:
For every 1 molecule of nitrogen that reacts, it needs three molecules of hydrogen to react with it. Together, they produce 2 molecules of ammonia, NH 3.
We can also say for every 1 mole of N 2 that reacts, 3 moles of H 2 reacts with it to produce 2 moles of NH 3.
These are mole-to-mole relationships/ratios. o Given a balanced equations; any two compounds can be compared using mole-to-mole relationships or mole ratios.
The mole ratios would be:
3 mol CO 2
1 mol C 3 H 8
3 mol CO 2
5 mol O 2
5 mol O 2
3 mol CO 2
These mole ratios are used to solve problems such as how many moles of carbon dioxide, CO 2 , would be produced from 6.25 moles of oxygen gas?
3 mol CO 2
YouTube Video: Solving Stoichiometry Problems by weiner STOP at 7:25 until you have read through the next three sections.
Steps:
Important to include units & formulas for all substances- units cancel except wanted units.
Example: Calculate the mass of H 2 required to react with 8.75 g of O 2 according to the following balanced equations: O 2 (g) + 2 H 2 (g) 2 H 2 O(g)
1 mol O 2
2 mol H 2
2.02 g H 2
(In your calculator: 8.75 ÷ 32.00 × 2 × 2.02 =)
Recall: Avogadro’s Molar Volume is 22.4 L/mol for a gas only at STP
Steps:
Example: How many liters of oxygen gas are needed to react with 0.234 grams of SO 2 gas at STP? 2 SO 2 (g) + O 2 (g) (^) 3 (g)
1 mol SO 2
1 mol O 2
22.4 L O 2
(In your calculator: 0.234 ÷ 64.07 ÷ 2 × 22.4 =)
Molar
Mass
Mole-Mole
Ratio
Molar
Mass
Grams of Given
Moles of Given
Moles of Unknown
Grams of Unknown
Molar
Mass
Mole-Mole
Ratio
Molar
Volume gas @ STP
Grams of Given
Moles of Given
Moles of Unknown
Liters of Unknown
Molar
Mass
Mole-Mole
Ratio
Molar
Volume gas @ STP
Liters of Given
Moles of Given
Moles of Unknown
Mass of Unknown
Example 1 : N 2 (g) + 3 H 2 (g) 2 NH 3 (g)
A. How many moles of N 2 are needed to completely react with 6.75 moles of H 2.
B. How many moles of NH 3 form when 3.25 moles of N 2 react?
C. How many moles of H 2 are required to produce 4.50 moles of NH 3?
Example 2: Consider the following reaction to produce iron, Fe (s):
Fe 2 O 3 (s) + 3 CO (g) 2 Fe (s) + 3 CO 2 (g)
A. Calculate the mass of CO needed to react completely with 50.0 g of Fe 2 O 3.
B. Calculate the mass of iron produced when 125 g of CO reacts completely.
C. Calculate the mass of CO 2 produced when 75.0 g of iron is produced.
Example 3 : Calculate the volume (in liters) of oxygen gas required to react with 50.0 g of aluminum at STP.
4 Al (s) + 3 O 2 2 Al 2 O 3 (s)
Example 4 : An automobile airbag inflates when N 2 gas results from the explosive decomposition of sodium azide (NaN 3 ),
2 NaN 3 (s) 2 Na (s) + 3 N 2 (g) Calculate the mass of NaN 3 required to produce 50.0 L of N 2 gas at STP.
Example 1 A
2
2 2 3 molH
6.75molesH^1 molN 2.25 mol N 2
2
2 3 1 molN
3.25molesN^2 molNH 6.50 mol NH 3
3
3 2 2 molNH
4.50molesNH^3 molH 6.75 mol H 2
Example 2 A
1 mole CO
28.01gCO 1 moleFeO
3 moleCO 159.70gFeO
50.0gFeO^1 moleFeO 2 3 2 3
2 3 2 3 = 26.3 g CO
1 mole Fe
55.85gFe 3 moleCO
2 moleFe 28.01gCO
125 gCO^1 moleCO = 166 g Fe
2
2 2 1 mole CO
44.01gCO 2 moleFe
3 moleCO 55.85gFe
75.0gFe^1 moleFe = 88.7 g CO 2
Example 3
2
2 2 1 mole O
22.4LO 4 moleAl
3 moleO 2 gAl
50.0g Al^1 moleAl 6_._ 98
Example 4
3
3 2
3 2
2 2 1 molNaN
65.02gNaN 3 molN
2 molNaN 22.4LN
50.0LN molN 96.8 g NaN 3