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Solutions to various utility function problems, including finding marginal utility, determining diminishing marginal utility, calculating the marginal rate of substitution, and graphing indifference curves. The examples use different utility functions and involve maximizing utility subject to a budget constraint.
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MU (^) X =
Marginal utility is constant for each good.
MRS (^) XY =
MRS is constant so indifference curves will have a constant slope (i.e., they are linear). For
x
y
50
(^020)
b. U ( X , Y ) = X 0.33 Y 0.
MUX =
45
46 Part 2 Consumption and Production
The marginal utility of X decreases as the quantity of X increases, holding the quantity of Y constant. Also, the marginal utility of Y decreases as the quantity of Y increases, holding the quantity of X constant. You can get this result by inspecting the marginal utilities or by checking the signs of the derivatives of these marginal utilities.
MRS (^) XY decreases as the consumer increases consumption of X along an indifference curve so the indifference curves are convex. For
x
y
100
(^0100)
c. U ( X , Y ) = 10 X 0.5^ + 5 Y
MU (^) X =
The marginal utility of good X decreases as more X is consumed. The marginal utility of good Y is constant:
MRS (^) XY =
- 0.
MRS decreases as the consumer increases consumption of X along an indifference curve so the indifference curves are convex. For
x
y
20
(^0100)
Note : This type of utility function is known as a “quasi-linear” utility function. The indifference curves for quasi- linear utility functions are parallel. In other words, the slopes of the indifference curve are the same, given a value of X.
48 Part 2 Consumption and Production
From the first two conditions,
λ = 0.25 x –^ 0.5 Y 0.5^ = 0.5 X 0.5 Y –^ 0.
Y = 2 X
Substituting into the third FOC, we get
100 – 2 X – 2 X = 0
X (^) A = 25
Then YA = 50. For B , max X , Y X^
0.8 Y 0.2 (^) s.t. 300 = 2 X + Y
max X , Y , λ ^ =^ X^
0.8 Y 0.2 (^) + λ (300 – 2 X – Y )
FOC:
= 0.8 X –^ 0.2 Y 0.2^ – 2 λ = 0
= 0.2 X 0.8 Y –^ 0.8^ – λ = 0
∂ λ
From the first two conditions,
λ = 0.4 X –^ 0.2 Y 0.2^ = 0.2 X 0.8 Y –^ 0.
y = 40.5 x
Substituting into the third FOC, we get
300 – 2 X – 40.5 X = 0
X (^) B = 120
Then YB = 60. b. The fi rst terms in the first two FOCs are MU (^) X and MU (^) Y , respectively. Therefore,
c. First, notice that A and B both have MRS equal to 2, even though their utility functions and their incomes are dif- ferent. C ’s MRS will be equal to 2, just like A and B. In fact, the MRS for all consumers will be equal to 2 as long as all consumers consume both goods (i.e., if they have an interior solution). This is because all consumers face the same prices and all consumers maximize their utilities where their MRS is equal to the price ratio.
max P , S , λ ^ =^3 PS^ +^6 P^ +^ λ (50^ –^ P^ –^^5 S^ )
Appendix: The Calculus of Utility Maximization and Expenditure Minimization Chapter 4 49
= 3 S + 6 – λ = 0
= 3 P – 5 λ = 0
∂ λ
From the fi rst two conditions,
λ = 3 S + 6 = 0.6 P
S = 0.2 P – 2
Substituting into the third FOC, we get
50 – P – 5 S = 50 – P – 5(0.2 P – 2) = 60 – 2 P = 0
P = 30
Then S = 4. b. We need to solve for the Lagrange multiplier λ. From above,
λ = 3 S + 6 = 0.6 P
Substituting for the optimal values of S or P gives λ = 18. Therefore, Katie’s level of utility would increase by 18 units if she receives an extra dollar to spend.
U ( X , Y ) = 10 X 0.5^ + 2 Y
The price of good X is $5 per unit and the price of good Y is $10 per unit. Suppose that the consumer must have 80 units of utility and wants to achieve this level of utility with the lowest possible expenditure. a. Write a statement of the constrained optimization problem. b. Use a Lagrangian to solve the expenditure-minimization problem.
min X , Y , λ ^ =^5 X^ +^10 Y^ +^ λ (80^ –^^10 X^
= 5 – 0.5 λ 10 X –^ 0.5^ = 5 – 5 λX –^ 0.5^ = 0
= 10 – 2 λ = 0
∂ λ
Solve for λ in the fi rst two conditions and set these two expressions equal to one another:
λ = X 0.5^ and λ = 5
X 0.5^ = 5
X = 25
Substituting 25 for X in the third constraint yields Y = 15. Then the minimum expenditure is $5(25) + $10(15) = $275.