Techniques of Integration: Integration by Substitution and Integration by Parts, Lecture notes of Statistics

This chapter covers two techniques for finding indefinite integrals: integration by substitution and integration by parts. The former is used when the integral can be transformed into the derivative of a known function, while the latter is used when the integral can be expressed as the product of two functions. Examples and solutions for each technique.

Typology: Lecture notes

2021/2022

Uploaded on 01/28/2022

tmkgomotso
tmkgomotso 🇧🇼

4.8

(19)

68 documents

1 / 2

Toggle sidebar

This page cannot be seen from the preview

Don't miss anything!

bg1
Chapter 6 - Techniques of Integration
6.1 Integration by Substitution
We know that the derivative of a function is obtained by the Chain rule:
, that is let , then
. Therefore, if we have a function of the form , then the
indefinite integral (anti-derivative) is , that is
.
Example 6.1.1
Find .
Solution 6.1.1
Put . Therefore, this implies that
.
Example 6.1.2
(i) Evaluate (i) and (ii) .
Solution 6.1.2
(i) Put . Therefore, this implies that
= .
(ii)
Example 6.1.3
pf2

Partial preview of the text

Download Techniques of Integration: Integration by Substitution and Integration by Parts and more Lecture notes Statistics in PDF only on Docsity!

Chapter 6 - Techniques of Integration

6.1 Integration by Substitution

We know that the derivative of a function is obtained by the Chain rule: , that is let , then

. Therefore, if we have a function of the form , then the indefinite integral (anti-derivative) is , that is . Example 6.1. Find. Solution 6.1. Put. Therefore, this implies that . Example 6.1. (i) Evaluate (i) and (ii). Solution 6.1. (i) Put. Therefore, this implies that =. (ii) Example 6.1.

, put. This implies that . Example 6.1. Evaluate , put. We know that when

. This implies that .

6.2 Integration by parts

Suppose and are functions of , that is and , then . Example 6.2. Evaluate i) ii) Solution 6.2.