Rotational Motion: Problem Solving and Concepts - Prof. Simon C. Capstick, Study notes of Physics

Problem-solving examples and concepts related to rotational motion, including conservation of energy and momentum in collisions, angular velocity and acceleration, and rotational kinetic energy. Students will learn how to calculate angular velocity, angular acceleration, and moment of inertia, as well as understand the relationship between linear and rotational motion.

Typology: Study notes

Pre 2010

Uploaded on 08/26/2009

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An example: Problem 97 (Off center
collision in 2D)
zBreak up into x and y components
zMomentum is conserved if there are no external forces
zHow do we know if energy is conserved? Work it out for
homework
°+°=
°+°=
=
60cos30cos
or
60cos30cos
or
21
21
xfxi
vvv
mvmvmv
pp
°°=
°°=
=
60sin30sin0
or
60sin30sin0
or
21
21
yfyi
vv
mvmv
pp
X-direction Y-direction
2 equations, 2 unknowns – solve for one, substitute into the other:
m/s00.1andm/s73.1 21 == vv
x
y
pf3
pf4
pf5
pf8
pf9
pfa
pfd
pfe
pff

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An example: Problem 97 (Off centercollision in 2D) z

Break up into x and y components

z

Momentum is conserved if there are no external forces

z

How do we know if energy is conserved? Work it out forhomework

°

°

=

°

°

= =

60

cos

30 cos

or

60

cos

30

cos

or

2

1

2

xf^1

xi

v

v

v

mv

mv

mv

p

p

°

− °

=

°

− °

=

=

60 sin

30 sin

or 0

60 sin

30 sin

or 0

2

1

2

yf 1

yi

v

v

mv

mv

p

p

X-direction

Y-direction

2 equations, 2 unknowns – solve for one, substitute into the other:

m/s

and

m/s

2

1

v

v

x

y

Problem 97

z

How do we know if the collisionis elastic or not?

z

KE

i^

= KE

f

z

Calculate this (homework)!

z

Note that the angle after thecollision between the twoobjects is 90 degrees. Thisonly works for elastic collisions.

z

You can show this by looking atm

v

1i

= m

v

1f

+ m

v

2f

z

Or…

v

1i

v

1f

v

2f

z

Also, from KE: ½ mv

1i

2

m

v1f

2

+ ½ mv

2f

2

z

So… v

1i

2

= v

1f

2

+ v

2f

2

z

Draw a right triangle – anglebetween v

1f

and v

2f

is 90

o

By Pythagorean theorem, this must be a right triangle

Rotational motion z

Let’s look at a particle movingon a rotating disk

z

We first need to define theconcept of an

angle

,^

θ

and

angular displacement

Δθ

z

Rotational motion describeshow this angle changes (notdistance) as a function of time

z

Convention:

θ

> 0

counterclockwise,

θ

< 0,

clockwise

z

Units: Radians. 1 revolution =360 degrees = 2

π

radians

z

In SI units, we usually just dropthe “radians” units (so forexample an angle of 180degrees can be expressed as π

radians or just

π

).

θ

Positive direction

If I rotate from point A to point B, my angular displacement

would be positive

B^

  • θ
)A
A
B

Axis of rotation

radius

(Δθ

θ

final

θ

initial

Rotational motion z

The

angular velocity

is the

rate of change of the angle

z

Units: rad/s, degrees/s,revolutions per minute (rpm),etc.

z

The time rate of change ofangular velocity is the

angular

acceleration

z

Units: rad/s

2

d^ θ^ dt

ω =

2 2 d^ dt

Be careful about sign conventions!

Constant angular acceleration z

Demonstration of a rotating object with aconstant angular acceleration

z

What should the angle, angular velocity,and angular acceleration curves look likeas a function of time?

What about tangential motion? z

Every point on a rotating object alsohas a tangential velocity andacceleration.

z

How are these related to angularvelocity and angular acceleration?

z

The “tangential velocity” is v

t^

= dx/dt

z

We can define x in terms of the arclength: x = r

θ

, or dx = r d

θ

(constant

r)

z

Therefore, v

t^

= rd

θ

/dt = r

ω

z

There is also a tangentialacceleration a

t^

= dv

/dt = rdt^

ω

/dt = r

α

z

Similarly, each particle has acentripetal acceleration towards thecenter which is a

C

= v

2 /r

z

By substitution, we then have that thecentripetal acceleration is

z

a

C

= (r

ω

/r = r

ω

2

θ

A
B

Axis of rotation

Tangential velocity at

Point A

Centripetal acceleration

at point A

a

C

v

t

a

t^

  • how fast v

is changing with timet^

a

t

Rotational motion PRS

Rotational motion PRS

An example: Problem 29 z

(A)

z

(B)

t Δ

=

α

ω

ω

t Δ

=

α

ω

Starts from rest

ω

0

At t = 5 s :

(

)

(^

)

(^

)

rad/s

s 5

rad/s 8

s 5

2

=

=

ω

α r

a

= t

(

)

(

)

(^

)

2

2

t

m/s

(^960). 0

rad/s 8

m

s 5

= =

a

Tangential acceleration: Centripetal acceleration:

2

c

ω

r

a

(^

)^

(^

)(

)

2

2

c

m/s

rad/s

m

s

a

Rotational Kinetic Energy

z

What is the kinetic energy of a rotating object?

z

If you had a system of particles rotating about acommon axis with the same angular velocity, then thekinetic energy of the i

th

particle is:

z

We can simplify this to get

z

The moment of inertia, I, of a system for a particularaxis of rotation is:

2

i i

i^

v

m

K

i^

i^

i

ii

ii

i i^

r m r m v m K

2

2

2 2

2

ω

ω

i

i ri m

I^

2

This depends on the axis ofrotation, and the mass distribution