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CHEM219/ CHEM 219 Module 7 – Principles of Organic Chemistry with Lab | Portage Learning | Updated 2026–2027 | Complete Questions & Verified Answers | Grade A
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2026 / 2027 Academic Year
Answer cyclic organic molecules in which one or more carbon atoms are replaced by heteroatoms (elements other than carbon or hydrogen)
Answer oxygen, nitrogen, and sulfur
Answer More than one heteroatom can be present, and the heteroatoms can be the same or different
have chains or branched chains of carbons attached to them. The rings may be of a variety of sizes. Answer True
Answer True
heterocyclic rings. Answer True
Answer Aromatic and aliphatic (non-aromatic) Example of non-aromatic heterocycles include molecules like cyclic ethers (epoxides) and sugars like glucose (a cyclic hemiacetal) Non-aromatic heterocycles behave very similarly to their acyclic counterparts.
hybrid orbital that is NOT orientated in the same plane of the atoms in the ring (like the hydrogens that project from each carbon atom). Answer False - they are orientated in the same plane of the atoms in the ring.
Answer 139 pm are intermediate between normal C-to-C sigma and pi bonds.
evidenced by the C-C bond length? Answer True
Answer The delocalization of the pi electrons within the six-membered ring.
Answer Substitution reactions because addition reactions would destroy the aromaticity.
Answer True; unlike benzene This is due to the substitution of the N atom in the ring which changes many of the properties of the molecules. Pyridine is also miscible in most organic solvents.
Answer
Answer B.P. of pyridine is 35 degrees higher than that of benzene, even though the molecular weight is negligible between the two compounds. Dipole-Dipole attractive forces between the pyridine molecules raises the B.P. as compared to benzene.
Answer C3 position This position is preferred as the positive charge that forms on the C during the reaction is the one position that does not put the positive charge on the electronegative N via resonance.
(NAS) than EAS? Answer True In NAS, a nucleophile displaces a hydride (H-) ion or halide ion (on a substituted pyridine) from the aromatic ring. Due to the presence of the N heteroatom, the ring is partially positive and therefore is more attractive to nucleophiles, rather than electrophiles. i.e. Strong nucleophiles like alkoxide ions (RO-) and amide ions (NH2-) help to facilitate the reaction. Azines Answer heterocyclic six-membered rings with two or more N atoms present as part of the ring system
Diazines Answer contain two N atoms and can exist in three different constitutional isomeric forms; pyrimidines are the most important because derivatives of pyrimidines are important bases in the nucleic acids DNA and RNA namely cytosine, thymine, and uracil. True or False: Tri- and tetrazines are also known, but no others with higher degrees of N substitution (5 or 6 N atoms) are known. Answer True What are the most important heterocyclic molecules with five-membered rings? Answer Furan (oxygen-based) Pyrrole (nitrogen-based) Thiophene (sulfur-based) These molecules each contain a carbon ring with a single heteroatom substitution. What are some similarities and differences between five-membered rings and benzene (six- membered ring)? Answer Similarities: aromatic undergo EAS rather than other modes, like addition planar (flat) differences: the heteroatom of a five-membered ring contributes two electrons (one lone pair) to the
True or False: Furan, pyrrole, and thiophene are all more reactive than benzene in EAS reactions. True Each molecule reacts with electrophiles to substitute (for a hydrogen) at the C-2 position. Why is substitution preferred at the C-2 position on five-membered heterocycles? The carbocation intermediate that forms during the reaction is delocalized over more atoms (and hence, more stable) when substitution occurs at this position. Azoles It is possible to introduce more than one heteroatom into a five-membered heterocycle. Of the many available structural possibilities, the most important heterocycles are formed by introducing a N atom in place of C-3 in furan, pyrrole, and thiophene. The resulting molecules are known as azoles. The inclusion of the N at position C-3 results in a "pyridine-like" N, which is involved in a pi bond. Imidazole A very good base, as the positive charge obtained from protonation of the N at position C- 3 can be delocalized via resonance over both N atoms. Imidazole is present in the amino acid histidine and is important in the reactions of many enzymes. Thiazole occurs naturally in thiamin (vitamin B1), a coenzyme required for many biochemical processes essential to human life
Why do heterocycles form the largest class of organic compounds known? Structural diversity in terms of their ring size and the number and identity of heteroatom substitutions. Another reason, is the possibility of fused ring systems. Fused ring system Two (or more) rings are fused together to form a larger molecule; to be fused means that each ring shares two (or more) common atoms as a part of the structure of each ring. Purines Another biologically important class of fused-ring heterocyclic compounds. Purines contain a pyrimidine ring fused to an imidazole ring. Uric acid , caffeine, and theobromine (found in chocolate) are all based on the structure of purine. Biochemically, the structures of adenine and guanine, two of the nitrogenous bases present in DNA and RNA are both purines. Indole a bicyclic, fused-ring compound formed by fusing a benzene ring to the C2-C3 bond of pyrrole Indole is a component in many biologically active compounds including the amino acid tryptophan. Heterocycles cyclic organic molecule where one or more carbon atoms are replaced by heteroatoms Heteroatoms Atoms in an organic compound other than carbon and hydrogen
an apolar compound overall. BP of pyridine vs benzene? why?
A substitution reaction in which an aromatic ring is attacked by a nucleophile, which replaces a leaving group.
Is pyridine or the 3 5-membered heterocycles more reactive in EAS reactions? Furan, Thiophene, and pyrrole are more reactive in EAS reactions than pyridine what atom number is preferred for EAS substitution on 5-membered heterocycles? substitution at C carbocation intermediate that is formed during EAS is delocalized over more atoms and thus more stable when at C Azole more than one heteroatom in a 5-membered heterocycle oxazole oxygen at 1, nitrogen at 3 Imidazole nitrogen at 1, nitrogen at 3 Thiazole sulfur at 1, nitrogen at 3 What does the additional Nitrogen on azoles allow for? lone pair on new nitrgoen means there is availability for the molecule to bond to an acidic proton Why is Imidazole a good base? positive charge obtained from the protonation of nitrogen on position 3 can be localized via
resonance over both of the nitrogens Imidazole is found in: histidine (amino acid) thiazole is found in: Thiamine (B1 vitamin) fused-ring system a molecule in which two or more rings share two adjacent carbon atoms indole benzene + pyrrole found in amino acid tryptophan purine pyrimidine ring fused to imidazole ring