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In Tutorial 4 you will be shown:
Do you remember getting somewhat "bogged down" in Tutorial 3, trying to always predict what will happen to an equilibrium when a change in temperature, volume, pressure etc. was made? In Tutorial 3, you figured out which rate (forward or reverse) was affected by the change, then you predicted what should happen. Tutorial 4 and LeChatelier's Principle will change all that! It gives you a simpler way to look at these concepts.
Let's look at LeChatelier's Principle first:
If a closed system at equilibrium is subjected to a change, processes will occur that tend to counteract that change.
Examples of Counteracting :
NOTE: When using LeChatelier's Principle, it is easier to have all reactions with "heat" in " Thermochemical Form ". eg.) The reaction: A + B C ∆H = -56 kJ is exothermic (∆H is negative), so heat is given off or written on the right. Thermochemical form: A + B C + 56 kJ The reaction: D + E F + G ∆H = 43 kJ is endothermic (∆H is positive), so heat is absorbed, or written on the left Thermochemical form: D + E + 43 kJ F + G
Okay, let's find out how LeChatelier's Principle applies here: Let's say we have an endothermic reaction: A + B + heat C + D If we increase the temperature of this system, we are adding heat. In order to counteract our change, the equilibrium will move in such a way as to use up heat.
Which means a new equilibrium will be established in which there is more C and D and less A and B than in the original equilibrium.
To summarize: When the temperature is increased , the equilibrium will shift away from the side with the heat term.
Now, if the temperature was decreased , the equilibrium would shift in such a way that would produce heat (to counteract the change). To do this, it would shift toward the side with the heat term. (in other words, produce heat)
To summarize: When the temperature is decreased , the equilibrium will shift toward the side with the heat term.
Here are a couple of questions:
Consider the equilibrium equation: H2(g)? + I2(g) 2HI(g) If we add some H 2 to a flask containing this mixture at equilibrium, [H 2 ] will immediately increase. In order to counteract this change, the equilibrium will shift to the right in order to "use up" some of the extra H 2. (In other words to decrease the [H 2 ]).
Consider the equilibrium equation: H2(g) ?+ I2(g) 2HI(g)
Let's say now that we somehow take away some I 2. [I 2 ] will immediately decrease. In order to counteract this change, the equilibrium will shift to the left in order to increase [I 2 ] again. If we were to add some HI , the [HI] would immediately _____________________crease. In order to counteract this change, the equilibrium would shift to the __________________. To answer the last question, adding HI will increase [HI]. In order to counteract this change the equilibrium will shift to the left. In shifting to the left, [H 2 ] and [I 2 ] will go up and [HI] will go down. We can summarize the effects of changing concentrations by saying:
If the concentration of a substance in an equilibrium system is increased by us, the equilibrium will shift toward the other side of the equation, in order to counteract the change.
or
If the concentration of a substance in an equilibrium system is decreased by us, the equilibrium will shift toward the side of the equation with that substance , in order to counteract the change.
Let's have you do some examples:
To review: A shift to the right in this case would mean that once the new equilibrium is established, the [NH 3 ] would be higher than before, the [N 2 ] and the [H 2 ] would be lower than before.
If the total pressure on this system is decreased , the equilibrium would shift to the left (the side with more moles of gas). This counteracts the imposed change by increasing the pressure. To see what happens when we change the total volume of the container we must remember that:
Increasing the volume of a closed system with gases will decrease the pressure. (the molecules have more room so they exert less pressure on the sides of the container)
So, given changes in volume of the container, just remember that the changes in pressure are just the opposite. For example: Given the equilibrium equation: N2(g) + 3H2(g) 2NH3(g)
1 + 3 = 4 moles ofgas on this side. 2moles of gas on thisside.
If the total volume of the container is increased , this means that the total pressure is decreased. The equilibrium will then shift to the side with more moles (to the left in this case), in order to counteract the change and try to increase the pressure again. If the total volume of the container is decreased , this means that the total pressure is increased. The equilibrium will then shift to the side with less moles (to the right in this case), in order to counteract the change and try to decrease the pressure again. Try the following:
Just a little note here about the difference between rate of reaction and the equilibrium shifting right or left! First of all, a " shift to the left “means that once the new equilibrium is reached, there will be more
For example, consider the reaction: A + B C + heat If the temperature of this system was increased , the equilibrium would shift to the left.
which has more A and B and less C. In fact, as we might recall from Unit 1, increasing the temperature always increases the rate of a reaction. (more molecules have the minimum energy necessary for an effective collision.) Increasing the temperature just causes equilibrium to be reached faster. Try these: