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This packet provides an organized, step-by-step approach for these problems. If you follow this system and complete work each day as it is assigned, ...
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We are about to start on a unit of chemical calculations called “stoichiometry”. Stoichiometry is how we calculate the relationships between the amounts of reactants and the amounts of products. For example, if we know the amount of reactants we have, we can use stoichiometry to calculate how many products the chemical reaction will produce.
This packet provides an organized, step-by-step approach for these problems. If you follow this system and complete work each day as it is assigned, this will not be a difficult unit. That is good, because stoichiometry is one of the most central and important concepts in chemistry. It is essential that you understand this unit in order to move forward in chemistry. In short: do not fall behind or you will be lost.
These problems involve numbers but no difficult mathematics. All you will ever have to do is add, multiply or divide. You will be expected to have a functioning calculator with you for every chemistry class. As we solve these problems we will apply the factor-label (dimensional analysis) method you mastered early in the class, and we will frequently use scientific notation. Remember chapter 3 you followed the procedure:
what you are = what you are X a fraction or series of fractions where the = looking for given numerator is equivalent to the denominator
The only new concept we will introduce in this unit is the idea of a mole. A mole is a quantity of matter that we use for conversion purposes. We can convert from grams to moles, liters to moles (for gases), and atoms or molecules to moles. If you can convert any of these things to moles (and therefore moles to any of these things) we can convert grams to liters or molecules, liters to grams of molecules, and molecules to liters or grams.
Molar Mass (# grams) Atomic Weight (for elements) or Gram Formula/Molecular Weight (for compounds)
6.02 X 10^23 ATOMS (for elements) or 6.02 X 10^23 MOLECULES ( for compounds)
MOLES
22.4 LITERS OF A GAS AT STP (standard temperature and pressure)
Define the term molar mass (worksheet #1): _______________________________________________________ Now that you know how to find the mass of one mole of a substance (molar mass) you can easily find the mass of several moles or the mass of a fraction of a mole using the factor-label technique.
EXAMPLE: What is the mass of 5.00 moles of water(H 2 0)? 2 H = 2 x( 1.01) = 2.02 # grams H 2 0 = 5.00 moles H 2 0 x 18.02 g H 2 0 = 90.10 g H 2 O O = 1 x(16.00) = 16.00 1 mole H 20
H 2 0 = 18.02 g
NOW YOU TRY ONE: What is the mass of 0.50 moles of calcium carbonate(CaCO 3 )? Ca = #g CaCO 3 = C = 3O =
CaCO 3 =
USE A SEPARATE SHEET OF PAPER TO SOLVE THE FOLLOWING PROBLEMS. SHOW YOUR WORK. ROUND MOLAR MASSES TO TWO PLACES AFTER THE DECIMAL. ADD UNITS.
Now that you know how to find the mass of one mole of a substance you can easily find the number of moles there are in a given mass of the substance.
EXAMPLE: How many moles of calcium chloride are there in 333 grams of calcium chloride (CaCl 2 )?
Ca = 1 x(40.08)= 40.08 # moles CaCl 2 = 333 grams CaCl 2 x 1 mole CaCl 2 = 3.00 mole CaCl 2 2 Cl = 2 x(35.45)= 70.90 110.98 g CaCl 2 CaCl 2 = 110.98 g
USE THE SAME PAPER AS THE ABOVE PROBLEMS TO SOLVE THE FOLLOWING. SHOW YOUR WORK AND PUT UNITS ON EACH ANSWER!
#1-5: You are given the number of moles and asked to find the grams (mass)
MOLS GRAMS
#6-10: You are given the grams (mass) and asked to find the number of mols
GRAMS MOLS
Now that you know two definitions of a mole (a gram formula weight and an Avogadro’s number of particles) you can combine these two definitions into one problem.
EXAMPLE: How many molecules are there in 90.1 grams of water?
2 H = 2 x(1.01) = 2. O = 1 x (16.00) = 16. H 2 O = 18.02 g
18.02 g H 2 O 1 mole H 2 O
EXAMPLE: What would be the mass of 3.01 x 10^23 molecules of ammonia (NH 3 )?
N = 1 x (14.01) = 14. 3 H = 3 x (1.01) = 3. NH 3 = 17.04 g
6.02 x 10^23 molecules NH 3 1 mole NH 3
Extra Challenge:
We have learned that a mole is a mass of material and number of particles. A mole can also be a measure of volume when we are talking about gases. You may remember from previous science classes that all gases behave basically the same as far as the physical properties of temperature, pressure and volume. AVOGADRO’S HYPOTHESIS SAYS THAT EQUAL VOLUMES OF GASES AT THE SAME TEMPERATURE AND PRESSURE CONTAIN EQUAL NUMBERS OF MOLECULES. Avogadro’s statement makes sense and is possible because gases are mainly empty space—only about one thousandth of the space is actually filled with molecules. The molecules “fill” the remaining space by moving rapidly through it. So the difference in size between large molecules and small molecules is insignificant compared to the total volume the gas occupies. At standard temperature and presssure (STP = OoCelcius and 1.00 atm pressure) one mole of any gas will have a volume of 22.4 liters. In other words, THE MOLAR VOLUME OF ANY GAS IS 22.4 LITERS AT STP. Once we know this we can convert from moles to liters or liters to moles for any gas at STP.
EXAMPLE: What is the volume, in liters, of a 2.00 mole sample of methane (CH 4 ) at STP?
1 mole CH 4
EXAMPLE: How many moles of ethane (C 2 H 6 ) are there in 5.60 liters of ethane?
22.4 L C 2 H 6
Extra Challenge
10 CHEMISTRY WORKSHEET # 7: GENERAL REVIEW OF MOLE PROBLEMS
Now we have studied the idea of moles and learned three interpretations of a mole: (1) A gram formula weight. (2) An Avogadro’s number of particles. (3) 22.4 liters of gas at STP.
Solve the following problems involving the mole concept. (If you are having difficulty go back and review mole worksheets 1-6.)
Problems 1-2: moles to grams AND grams to moles
Problems 3-4: moles to molecules AND molecules to moles
Problems 5-6: grams to moles to molecules AND molecules to moles to grams
MOLAR MASS (G/MOL)
MOLE
22.4 LITERS OF GAS AT STP
6.02 X 10^23 PARTICLES (ATOMS OR MOLECULES)
11
Problems 7-8: moles to liters AND liters to moles
Problems 9-10: grams to moles to liters AND liters to moles to grams
Problems 11-12: molecules to moles to liters AND liters to moles to molecules
Problems 13-16: Mixed Problems- Think about what type of conversion you are doing!