chemistry notes i think, Cheat Sheet of Chemistry

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2023/2024

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carbon dioxide subliming high entropy
NaCl=most E,E of surr is less than in hands when ice melts
SF6(g)->SF(l) =low temps
Zno+Ca->Zn+CO=Smelting, Pd2H, W2N, 2 7 is not magic, NO2 is not weak ligland, (FE(H2 O)6)=4, (Co(NH3 )5NO2 )=0, square planar= X2-y^2, V2 O3 =ox 3, bidentate= ethelene diamine, Sod iumtetrachloronnicellate 2=Na2(NiCl4)
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carbon dioxide subliming high entropy NaCl=most E,E of surr is less than in hands when ice melts SF6(g)->SF(l) =low tempsZno+Ca->Zn+CO=Smelting, Pd2H, W2N, 27 is not magic, NO2 is not weak ligland, (FE(H2O)6)=4, (Co(NH3)5NO2)=0, square planar= X2-y^2, V2O3 =ox 3, bidentate= ethelene diamine, Sodiumtetrachloronnicellate 2=Na2(NiCl4)

Chemistry I (CHEM1100/1110)

N A = 6.022 × 10^23 R = 8.314 J·mol–^1 ·K–^1 or R = 0.08206 L·atm·mol–^1 ·K–^1

1 atm = 760 mmHg = 760 torr = 1.01325 bar = 1.01325 × 10^5 Pa = 14.7 psi

PV = nRT P A = χA P Total RT

PM

= d = M

RT u 3 rms =

A

B A

B M

M d

d B

A = = effusionrate( )

effusionrate() V nb nRT V

na P (^)  − = 

  • 2 ( (^) meas )

2 meas

Boltzmann Constant: k B = R / N A 1 D = 3.34 ×10–^30 C • m 1 ev = 1.602 × 10−19^ J

m e = 9.10939 × 10–^31 kg c = 2.998 × 10^8 m/sec h = 6.626 × 10–^34 J·s

  

   

 = − 2 2

2 1

1 1 1 n n

RH

R H = 1.096776 × 10^7 m–^1

Zeff = Z − S S^ # valence^ e s (^0.^35 ) # core e s (^0.^85 )

= -^  + - 

E = hν c = νλ  

= −  −^18

2. 18 10 J

n

(^) En (Hydrogen Atom)

Momentum: p = mu m

mu p KE 2 2

2 2 (^) = = (note: u = velocity, ν = frequency)

mu

h p

h

= = = q ( r ) (electron)^1.^610 C

q =  −^19

KE electron = – Ф or if atom or molecule KE electron = IE (Ionization Energy)

q = C Δ T C = heat capacity = m (specific heat)

Δ E = q + w w = – P Δ V H = Δ E + P Δ V

C = heat capacity = m (specific heat) = n C m m = sample mass n = moles of sample

C m = molar heat capacity

 ^ =   −   H rxn mH f(products) nH f(reactants)

pH = – log[H+] pOH = – log[OH–] pH + pOH = 14.

K a × K b = K w K w = 1.0 × 10–^14 (at 25°C) [HA]

[H][A ]

a

  • K = [B]

[BH][OH]

b

  • K =

Quadratic equation: ax^2 + bx + c = 0 a

b b ac x 2

− ^2 − 4

Chemistry II (CHEM1200)

1 amu = 1.66054 × 10–^27 kg = 931.5 MeV 1 eV = 1.6022 × 10–^19 J m electron = 9.10938262 × 10–^31 kg m proton = 1.67262171 × 10–^27 kg m neutron = 1.67492728 × 10–^27 kg

C s, ice = 2.09 J/g•˚C C s, water = 4.18 J/g•˚C 1  = 96 , 485. 340 C/mol e

1 2 1

ln 2 1 1 R T T

H

P

P (^) vap R

S

R T

H

K

vap

^ 

ln

q = n  Hfusion q = mC s T n  = 2 d sin

S gas = kHPgas^ ( T^ is constant)

2

2 1

1

P

S

P

S

 H sol " n = Hsolute + Hsolvent + Hmix  H hydration = Hsolvent + Hmix

Psolution = XsolventPsolvent Psolution = XAPA ^ + XBPB 

 P = Psolvent − Psolution = XsolutePsolvent

  T K m

 f = f  Tb = Kbm = MRT

dt

d Rate

[X]

rate = k [A] n [B] m

n m

k

k rate

rate  

1

2 1

2 1

2 [B ]

[B]

[A]

[A]

[A ] t = − kt +[A] 0 ln[A ] t = − kt +ln[A] 0

[A] 0

[A]

= kt +

t k

t

ln 2 1 / 2 =

EaRT k Ae − / =

1 2 1

ln 2 1 1

R T T

E

k

k a

c

[ ][ ]

[ ][ ]

K

D E

F G

d e

f g

K = K ( RT ) ng P c

pH = – log[H 3 O+] pH + pOH = p K w = 14 p K a + p K b = p K w K a × K b = K w

[HA]

[H][A]

a

  • K = [B]

[BH][OH]

b

  • K = [HA]

[A]

pH p a log

− = K + [B]

[BH]

pOH p b log

= K +

a a 1 a 2 2

2 2

[HA ]

[ H][A ]

= K = K  K

  • −  H = E + ngasRTG^ = HTS

G = G + RT ln QG =− RT ln KG =− nE q = It = n

ln K c

n

RT

Ecell

 = Q

n

RT

E cell Ecell ln

E = mc^2

hc E = kN t

N

Activity = 

2 1

2 2 2

1 d

d I

I

l r

l r

l r

FCC: 2 2

BCC:

SC: 2

Isothermal compression, 4, 0.43,ph=11.13 ,6.4x10^-3, Heterogeneous catalyst, ph=1.50, electrons=4, E2=the one with Br reactant,. E1=H3O product, flourine 18, Z^

2448,-32.88, 710,delt Grxn=0 at equillibrium,1.17*10^41, glass transition is not first oirder,28.9kj,11.2j/k,Sys<0,Surr>0= spontaneous, 1.24x10^-8,znso4=4, 183g/mol,0.5M FeCl3, 0.05m NaCl,, C6H14, Br2 are homogeneous, CO2 bubbles, 0.005M CO2, 3.4x10^-2,0.0028Ms^-1, 4.1x10^-4M/a,

kA2BC3=6th order

kA2B3=M-4S-1,3 half lives,51300J, (k1/k-1)(NO2)(Br2), R-,acidic,H20 and PCl are lewis bases,.1M HNO2 and .1NaNO2 is buffer, 2.34,HCHo<NaCHO,HC7H5O2, Ka=6.5x10^-5, 6.6g,8.42x10^-5, OX # is +7 for HCLO

3S+6H2O->3SO2+12H+1212e, salt bridge = NaCl, spontaneous, 1.32 V,,1.01=pOH, Li++e- -> Li E=-3.05,, 0.250 A,(CH3)2CHOH favors the reactionss, E2=strong base,,(CH3)3CCL=fastest at SN1,3 carbocation,.E1=

first order