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Group 2 elements (alkaline earth metals) include Be, Mg, Ca, Sr, Ba. They are metals, and in reactions they tend to lose two electrons to form M² ⁺ ions.
Group 2 atoms have an outer electron configuration of ns².
Example:
● Mg: 1s² 2s² 2p ⁶ 3s²
● Ca: 1s² 2s² 2p ⁶ 3s² 3p ⁶ 4s²
They form ions by losing the two outer electrons:
Mg→Mg2++2e−\text{Mg} \rightarrow \text{Mg}^{2+} + 2e^-Mg→Mg2++2e−
Reasoning OCR wants:
● Losing the two outer electrons gives a stable noble gas configuration.
● Forming M² ⁺ is energetically and chemically favourable compared with trying to form M⁺ (which is still reactive and not the common stable ion).
Trend: atomic radius increases down the group.
Reasoning chain:
● Each element down the group has an extra electron shell.
● Outer electrons are in a higher energy level further from the nucleus.
● Increased shells increase shielding , so outer electrons feel less effective nuclear attraction.
● Therefore the atom is larger.
Trend: first ionisation energy decreases down the group.
OCR-style explanation:
● Down the group, outer electrons are in shells further from the nucleus → greater atomic radius.
● More shells means more shielding by inner electrons.
● So there is weaker electrostatic attraction between nucleus and outer electrons.
● Therefore less energy is needed to remove one electron.
Write ionisation energy equation correctly:
Mg(g)→Mg+(g)+e−\text{Mg(g)} \rightarrow \text{Mg}^+\text{(g)} + e^-Mg(g)→Mg+(g)+e−
For Mg, after removing 2 electrons, Mg²⁺ has a noble gas structure. Removing a 3rd electron would mean removing a core electron from an inner shell.
Reasoning chain:
● The 3rd electron is closer to the nucleus (smaller distance).
● Much less shielding.
● Much stronger attraction to nucleus.
● So a very large energy is required → big jump.