Chemistry OCR Revision, Exercises of Chemistry

Chem OCR Practice questions from multiple topics.

Typology: Exercises

2025/2026

Uploaded on 06/17/2026

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Page 1 — Group 2 overview and electronic structure
What are Group 2 elements?
Group 2 elements (alkaline earth metals) include Be, Mg, Ca, Sr, Ba.
They are metals, and in reactions they tend to lose two electrons to form ions.
Why do they form 2+ ions?
Group 2 atoms have an outer electron configuration of ns².
Example:
Mg: 1s² 2s² 2p 3s²
Ca: 1s² 2s² 2p 3s² 3p 4s²
They form ions by losing the two outer electrons:
Mg→Mg2++2e−\text{Mg} \rightarrow \text{Mg}^{2+} + 2e^-Mg→Mg2++2e−
Reasoning OCR wants:
Losing the two outer electrons gives a stable noble gas configuration.
Forming is energetically and chemically favourable compared with trying to form
M (which is still reactive and not the common stable ion).
Trends down Group 2: atomic radius
Trend: atomic radius increases down the group.
Reasoning chain:
Each element down the group has an extra electron shell.
Outer electrons are in a higher energy level further from the nucleus.
Increased shells increase shielding, so outer electrons feel less effective nuclear
attraction.
Therefore the atom is larger.
Trend down Group 2: first ionisation energy
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Page 1 — Group 2 overview and electronic structure

What are Group 2 elements?

Group 2 elements (alkaline earth metals) include Be, Mg, Ca, Sr, Ba. They are metals, and in reactions they tend to lose two electrons to form ions.

Why do they form 2+ ions?

Group 2 atoms have an outer electron configuration of ns².

Example:

● Mg: 1s² 2s² 2p3s²

● Ca: 1s² 2s² 2p3s² 3p4s²

They form ions by losing the two outer electrons:

Mg→Mg2++2e−\text{Mg} \rightarrow \text{Mg}^{2+} + 2e^-Mg→Mg2++2e−

Reasoning OCR wants:

● Losing the two outer electrons gives a stable noble gas configuration.

● Forming ⁺ is energetically and chemically favourable compared with trying to form M⁺ (which is still reactive and not the common stable ion).

Trends down Group 2: atomic radius

Trend: atomic radius increases down the group.

Reasoning chain:

● Each element down the group has an extra electron shell.

● Outer electrons are in a higher energy level further from the nucleus.

● Increased shells increase shielding , so outer electrons feel less effective nuclear attraction.

● Therefore the atom is larger.

Trend down Group 2: first ionisation energy

Trend: first ionisation energy decreases down the group.

OCR-style explanation:

● Down the group, outer electrons are in shells further from the nucleus → greater atomic radius.

● More shells means more shielding by inner electrons.

● So there is weaker electrostatic attraction between nucleus and outer electrons.

● Therefore less energy is needed to remove one electron.

Write ionisation energy equation correctly:

Mg(g)→Mg+(g)+e−\text{Mg(g)} \rightarrow \text{Mg}^+\text{(g)} + e^-Mg(g)→Mg+(g)+e−

Big jump between 2nd and 3rd ionisation energies (classic OCR

explanation)

For Mg, after removing 2 electrons, Mg²⁺ has a noble gas structure. Removing a 3rd electron would mean removing a core electron from an inner shell.

Reasoning chain:

● The 3rd electron is closer to the nucleus (smaller distance).

● Much less shielding.

● Much stronger attraction to nucleus.

● So a very large energy is required → big jump.