CHM012 ASSIGNMENT 01, Assignments of Chemistry

Chemistry for Engineers Assignment

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2019/2020

Uploaded on 05/28/2022

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Abigail E. Sasuman
BS Civil Engineering, 1st Year
CHM012-B3
Assignment 1
1. In what ways are microwave and ultraviolet radiation the same? In what ways are
they
different?
-Microwave and ultraviolet radiation may differ in terms of production processes and
could be detected in specific ways, but both are fundamentally the sameboth are
parts of the electromagnetic spectrum which means they share common properties,
such as having streams of photons which travels in a wave-like pattern at the speed
of light. They’re also aren’t visible to the naked eyes.
-Radiations are classified according to the amount of energy found in their photons.
The higher the frequency of the photon, the higher energy it also contains.
According to the Electromagnetic Spectrum, Ultraviolet has shorter amount of
wavelength compared to Microwave, which also means it has greater frequency.
With greater frequency, we could say photons in ultraviolet contain higher energy
than photons in microwave.
2. Consider the following types of electromagnetic radiation: (1) Microwave (2)
Ultraviolet
(3) Radio waves (4) Infrared (5) X-ray (6) Visible
(a) Arrange them in order of increasing wavelength.
(b) Arrange them in order of increasing frequency.
(c) Arrange them in order of increasing energy
Answers:
(a)Arrange them in order of increasing wavelength.
X-Ray, Ultraviolet, Visible, Infrared, Microwave, Radio waves
(b)Arrange them in order of increasing frequency.
Radio waves, Microwave, Infrared, Visible, Ultraviolet, X-Ray
(c) Arrange them in order of increasing energy.
Radio waves, Microwave, Infrared, Visible, Ultraviolet, X-Ray
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Abigail E. Sasuman BS Civil Engineering, 1st Year CHM012-B Assignment 1

  1. In what ways are microwave and ultraviolet radiation the same? In what ways are they different? -Microwave and ultraviolet radiation may differ in terms of production processes and could be detected in specific ways, but both are fundamentally the same—both are parts of the electromagnetic spectrum which means they share common properties, such as having streams of photons which travels in a wave-like pattern at the speed of light. They’re also aren’t visible to the naked eyes. -Radiations are classified according to the amount of energy found in their photons. The higher the frequency of the photon, the higher energy it also contains. According to the Electromagnetic Spectrum, Ultraviolet has shorter amount of wavelength compared to Microwave, which also means it has greater frequency. With greater frequency, we could say photons in ultraviolet contain higher energy than photons in microwave.
  2. Consider the following types of electromagnetic radiation: (1) Microwave (2) Ultraviolet (3) Radio waves (4) Infrared (5) X-ray (6) Visible (a) Arrange them in order of increasing wavelength. (b) Arrange them in order of increasing frequency. (c) Arrange them in order of increasing energy Answers: (a)Arrange them in order of increasing wavelength. X-Ray, Ultraviolet, Visible, Infrared, Microwave, Radio waves (b)Arrange them in order of increasing frequency. Radio waves, Microwave, Infrared, Visible, Ultraviolet, X-Ray (c) Arrange them in order of increasing energy. Radio waves, Microwave, Infrared, Visible, Ultraviolet, X-Ray

Assignment 2 Portions of electromagnetic waves A, B, and C are represented by the following (not drawn to scale): Rank them in order of (a) increasing frequency; (b) increasing energy; (c) increasing amplitude. (d) If wave B just barely fails to cause a current when shining on a metal, is wave A or C more likely to do so? (e) If wave B represents visible radiation, is wave A or C more likely to be IR radiation? Answers: (a)increasing frequency C, B, A (b)increasing energy C, B, A (c) increasing amplitude C, B, A (d)If wave B just barely fails to cause a current when shining on a metal, is wave A or C more likely to do so? No. According to the observations in photoelectric effect, the ability of light to eject an electron depends on its frequency, not on the intensity. Since wave C has longer wavelength than waves A and B, this means it has the lowest energy out of all the waves, since longer wavelength means lower frequency, and lower frequency means lower energy. If wave B barely fails (succeeded but come really close to failing) to cause a current, this means its frequency hits the threshold frequency (frequency needed to eject an electron), even if it comes close to failing, as long as it succeeded in causing a current when shined on a metal at the end. With wave C having the lowest frequency, it is expected for the wave to completely fail, and with wave A having the highest frequency, it is expected to successfully cause a current when shined on a metal.