Physics Exercise: Buoyancy and Density Calculations - Prof. Kevin Lee, Study notes of Physics

A physics class exercise focusing on buoyancy and density concepts. Students are asked to calculate the volume, mass, weight, and buoyancy force of an iron cube suspended in water, as well as the pressure and force acting on its top and bottom surfaces. Additionally, they are asked to determine the depth at which a lead hockey puck floats in mercury. Various formulas and values for given variables.

Typology: Study notes

Pre 2010

Uploaded on 08/30/2009

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Physics 151 Class Exercise: Buoyancy - KEY
1. A cube of iron 0.300 m on a side is suspended (in equilibrium) from a large spring scale (which
reads in Newtons) held over a giant tank of water. The center of the cube is 30.00 m below the
surface of the water.
(a) What is the volume of the cube?
(b) What is the mass of the cube?
(c) What is the weight of the water displaced by the cube?
(d) What is the magnitude of the force of buoyancy on the cube?
(e) What is the reading on the spring scale ?
(f) What is the pressure on the top surface of the cube?
(g) What is the pressure on the bottom surface of the cube?
(h) What is the force on the top surface of the cube?
(i) What is the force on the bottom surface of the cube?
(j) What is the difference between the force on the bottom and the force on the top?
(
)
3
33
0.300 0.0270Vl m m== =
()
3
3
7860 0.0270 212
Fe
kg
M
Vmkg
m
ρ
⎛⎞
== =
⎜⎟
⎝⎠
()
3
32
1000 0.0270 9.81 265
Fe
kg m
WVg m N
ms
ρ
⎛⎞
== =
⎜⎟
⎝⎠
265
B
F
N
=
()
2
212 9.81 265 1810
B
m
TmgF kg N N
s
⎛⎞
=−= =
⎜⎟
⎝⎠
()
()
5 5
32
1.013 10 1000 9.81 29.85 3.941 10
a
kg m
PP gh Pa m Pa
ms
ρ
⎛⎞
=+ = × + = ×
⎜⎟
⎝⎠
()
()
5 5
32
1.013 10 1000 9.81 30.15 3.971 10
a
kg m
PP gh Pa m Pa
ms
ρ
⎛⎞
=+ = × + = ×
⎜⎟
⎝⎠
()
()
2
5
3.941 10 0.3 35470FPA Pa m N== × =
()
()
2
5
3.971 10 0.3 35740FPA Pa m N== × =
12
35740 35470 270FFF N N N∆= = =
pf2

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Physics 151 Class Exercise: Buoyancy - KEY

  1. A cube of iron 0.300 m on a side is suspended (in equilibrium) from a large spring scale (which

reads in Newtons) held over a giant tank of water. The center of the cube is 30.00 m below the

surface of the water.

(a) What is the volume of the cube?

(b) What is the mass of the cube?

(c) What is the weight of the water displaced by the cube?

(d) What is the magnitude of the force of buoyancy on the cube?

(e) What is the reading on the spring scale?

(f) What is the pressure on the top surface of the cube?

(g) What is the pressure on the bottom surface of the cube?

(h) What is the force on the top surface of the cube?

(i) What is the force on the bottom surface of the cube?

(j) What is the difference between the force on the bottom and the force on the top?

3 3 3 V = l = 0.300 m =0.0270 m

3 3 Fe^7860 0.0270^212

kg M V m kg m

ρ

3 3 2 Fe^1000 0.0270^ 9.81^265

kg m W Vg m N m s

ρ

FB = 265 N

B^ (^212 )^ 9.81^2265

m T mg F kg N N s

( ) (^ )

5 5 3 2 a 1.013^10 1000 9.81^ 29.85^ 3.941^10

kg m P P gh Pa m Pa m s

ρ

= + = × + = ×

( ) (^ )

5 5 3 2 a 1.013^10 1000 9.81^ 30.15^ 3.971^10

kg m P P gh Pa m Pa m s

ρ

= + = × + ⎜ ⎟ ⎜ ⎟ = ×

( )(^ )

5 2 F = PA = 3.941 10× Pa 0.3 m = 35470 N

( )(^ )

5 2 F = PA = 3.971 10× Pa 0.3 m = 35740 N

∆ F = F 1 − F 2 = 35740 N − 35470 N = 270 N

  1. A piece of lead has the shape of a hockey puck, with a diameter of 7.5 cm and a height of 2.

cm. If the puck is placed in a mercury bath it floats. How deep below the surface of the mercury is

the bottom of the lead puck?

Note that the cross-sectional area cancels out. Another example of the advantages of using

variables.

3

3

b

Hg submerged

Hg submerged lead

(^2 ) submerged

Hg lead

lead submerged

Hg

3 kg

m

3 kg

m

(0.025 m)

2.1cm

F W

V g mg

V V

D h D h

h h

ρ

ρ ρ

π π

ρ ρ

ρ

ρ

⎜ ⎟ ⎜^ ⎟

⎝ ⎠ ⎝^ ⎠

×

×