

Study with the several resources on Docsity
Earn points by helping other students or get them with a premium plan
Prepare for your exams
Study with the several resources on Docsity
Earn points to download
Earn points by helping other students or get them with a premium plan
A physics class exercise focusing on buoyancy and density concepts. Students are asked to calculate the volume, mass, weight, and buoyancy force of an iron cube suspended in water, as well as the pressure and force acting on its top and bottom surfaces. Additionally, they are asked to determine the depth at which a lead hockey puck floats in mercury. Various formulas and values for given variables.
Typology: Study notes
1 / 2
This page cannot be seen from the preview
Don't miss anything!


Physics 151 Class Exercise: Buoyancy - KEY
reads in Newtons) held over a giant tank of water. The center of the cube is 30.00 m below the
surface of the water.
(a) What is the volume of the cube?
(b) What is the mass of the cube?
(c) What is the weight of the water displaced by the cube?
(d) What is the magnitude of the force of buoyancy on the cube?
(e) What is the reading on the spring scale?
(f) What is the pressure on the top surface of the cube?
(g) What is the pressure on the bottom surface of the cube?
(h) What is the force on the top surface of the cube?
(i) What is the force on the bottom surface of the cube?
(j) What is the difference between the force on the bottom and the force on the top?
3 3 3 V = l = 0.300 m =0.0270 m
3 3 Fe^7860 0.0270^212
kg M V m kg m
ρ
3 3 2 Fe^1000 0.0270^ 9.81^265
kg m W Vg m N m s
ρ
m T mg F kg N N s
5 5 3 2 a 1.013^10 1000 9.81^ 29.85^ 3.941^10
kg m P P gh Pa m Pa m s
ρ
5 5 3 2 a 1.013^10 1000 9.81^ 30.15^ 3.971^10
kg m P P gh Pa m Pa m s
ρ
5 2 F = PA = 3.941 10× Pa 0.3 m = 35470 N
5 2 F = PA = 3.971 10× Pa 0.3 m = 35740 N
cm. If the puck is placed in a mercury bath it floats. How deep below the surface of the mercury is
the bottom of the lead puck?
Note that the cross-sectional area cancels out. Another example of the advantages of using
variables.
3
3
b
Hg submerged
Hg submerged lead
(^2 ) submerged
Hg lead
lead submerged
Hg
3 kg
m
3 kg
m
ρ
ρ ρ
π π
ρ ρ
ρ
ρ