Class Notes for Fundamental Mathematics | MATH 347, Study notes of Algebra

Material Type: Notes; Class: Fundamental Mathematics; Subject: Mathematics; University: University of Illinois - Urbana-Champaign; Term: Summer 2008;

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Pre 2010

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Mee Seong Im Introduction to Logic and Proofs Monday July 28, 2008
Problem 14.3. [page 287]. For each condition below, give examples of se-
quences <a>and <b>such that lim an= 0, lim bndoes not exist, and the
specified condition holds.
a) lim(anbn) = 0.
b) lim(anbn) = 1.
c) lim(anbn) does not exist.
a) Take an=1
nand bn= (โˆ’1)n.
b) Take an= (โˆ’1)n1
nand bn= (โˆ’1)nn.
c) Take an=1
nand bn= (โˆ’1)nn2. Then lim(anbn) = lim(โˆ’1)nndoes not
exist.
โ€”โ€”โ€”โ€”โ€”โ€”โ€”โ€”โ€”โ€”โ€”โ€”โ€”โ€”โ€”โ€”โ€”โ€”โ€”โ€”โ€”โ€“
Problem 14.5. Find a counterexample to the following false statement.
โ€If an< bnfor all nand Pbnconverges, then Panconverges.โ€
This is false. Here is the counterexample: for all ntake an=โˆ’1 and
bn= 0. Then an< bnfor every nand Pbn=P0=0<โˆž. However,
Pan=Pโˆ’1 = โˆ’โˆž.So Pandiverges.
QUESTION: What would you add to make the above statement true?
โ€”โ€”โ€”โ€”โ€”โ€”โ€”โ€”โ€”โ€”โ€”โ€”โ€”โ€”โ€”โ€”โ€”โ€”โ€”โ€”โ€”โ€“
For this exercise, determine whether the statement is true or false. If true,
provide a proof; if false, provide a counterexample.
Problem 14.8. Let < x > be a sequence of real numbers.
a) If < x > is unbounded, then < x > has no limit.
b) If < x > is not monotone, then < x > has no limit.
a) True. Pro of for a Contradiction.Suppose < x > has a limit. Then
limnโ†’โˆž xn=L < โˆž. Then given any ๎˜ > 0, there exists N=N(๎˜)>0
such that for all nโ‰ฅN|xnโˆ’L|< ๎˜. This implies that < x > is bounded.
Contradiction. ๎˜‚
b) False. Let xn= (โˆ’1)n1
n. Then < xn>is not monotone but lim xn= 0.
โ€”โ€”โ€”โ€”โ€”โ€”โ€”โ€”โ€”โ€”โ€”โ€”โ€”โ€”โ€”โ€”โ€”โ€”โ€”โ€”โ€”โ€“
Problem 14.15. Suppose that bโ‰คL+๎˜for all ๎˜ > 0.Prove that bโ‰คL.
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Mee Seong Im Introduction to Logic and Proofs Monday July 28, 2008

Problem 14.3. [page 287]. For each condition below, give examples of se- quences < a > and < b > such that lim an = 0, lim bn does not exist, and the specified condition holds. a) lim(anbn) = 0. b) lim(anbn) = 1. c) lim(anbn) does not exist.

a) Take an = (^) n^1 and bn = (โˆ’1)n. b) Take an = (โˆ’1)n^1 n and bn = (โˆ’1)nn. c) Take an = (^1) n and bn = (โˆ’1)nn^2. Then lim(anbn) = lim(โˆ’1)nn does not exist.

โ€”โ€”โ€”โ€”โ€”โ€”โ€”โ€”โ€”โ€”โ€”โ€”โ€”โ€”โ€”โ€”โ€”โ€”โ€”โ€”โ€”โ€“

Problem 14.5. Find a counterexample to the following false statement. โ€If an < bn for all n and

bn converges, then

an converges.โ€

This is false. Here is the counterexample: for all n take an = โˆ’1 and bn = 0. Then an < bn for every n and

bn =

โˆ‘ 0 = 0^ <^ โˆž.^ However, an =

โˆ’1 = โˆ’โˆž. So

an diverges. QUESTION: What would you add to make the above statement true?

โ€”โ€”โ€”โ€”โ€”โ€”โ€”โ€”โ€”โ€”โ€”โ€”โ€”โ€”โ€”โ€”โ€”โ€”โ€”โ€”โ€”โ€“

For this exercise, determine whether the statement is true or false. If true, provide a proof; if false, provide a counterexample. Problem 14.8. Let < x > be a sequence of real numbers. a) If < x > is unbounded, then < x > has no limit. b) If < x > is not monotone, then < x > has no limit.

a) True. Proof for a Contradiction. Suppose < x > has a limit. Then limnโ†’โˆž xn = L < โˆž. Then given any  > 0, there exists N = N () > 0 such that for all n โ‰ฅ N |xn โˆ’ L| < . This implies that < x > is bounded. Contradiction.  b) False. Let xn = (โˆ’1)n^1 n. Then < xn > is not monotone but lim xn = 0.

โ€”โ€”โ€”โ€”โ€”โ€”โ€”โ€”โ€”โ€”โ€”โ€”โ€”โ€”โ€”โ€”โ€”โ€”โ€”โ€”โ€”โ€“

Problem 14.15. Suppose that b โ‰ค L +  for all  > 0. Prove that b โ‰ค L.