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UNIVERSITY OF ILLINOIS AT URBANA-CHAMPAIGN. Department of Electrical and Computer ... EXAM 1. Wednesday, September 28, 2022. • This is a CLOSED BOOK exam.
Typology: Exams
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on Gradescope at exactly 1:00pm; you will need to photograph and upload your answers by exactly
2:00pm.
accordingly.
Name:
NetID:
Phasors
A cos(2πf t + θ) = <
Ae
jθ e
j 2 πf t
e
−jθ e
−j 2 πf t
e
jθ e
j 2 πf t
Spectrum
Scaling: y(t) = Gx(t) =
N ∑
k=−N
(Gak) e
j 2 πfk t
Add a Constant: y(t) = x(t) + C = (a 0
k 6 =
a k
e
j 2 πfk t
Add Signals: If fk = f
′
n
= f
′′
m
then ak = a
′
n
′′
m
Time Shift: y(t) = x(t − τ ) =
N ∑
k=−N
ake
−j 2 πf k
τ
e
j 2 πf k
t
Frequency Shift: y(t) = x(t)e
j 2 πF t
=
N ∑
k=−N
ake
j 2 π(fk +F )t
Differentiation: y(t) =
dx
dt
N ∑
k=−N
(j 2 πfkak) e
j 2 πfk t
Fourier Series
Analysis: X k
T 0
0
x(t)e
−j 2 πkt/T 0 dt
Synthesis: x(t) =
∞ ∑
k=−∞
Xke
j 2 πkt/T 0
Sampling and Interpolation:
x[n] = x
t =
n
s
f a
= min (f mod F s
, −f mod F s
z a
z f mod Fs < −f mod Fs
z
∗ f mod F s
−f mod F s
y(t) =
∞ ∑
n=−∞
y[n]p(t − nT s
x(t) =
1 0 < t < 0. 001
0 0. 001 < t < 0. 005
− 1 0. 005 < t < 0. 006
0 0. 006 < t < 0. 01
(a) What are the Fourier series coefficients X k
for k 6 = 0? Your answer should contain no variables
other than k, but you don’t need to simplify.
(b) Suppose that y(t) is a signal such that x(t) =
dy
dt
. Express the Fourier series coefficients Yk in terms
of the Fourier series coefficients Xk. Note that you don’t need to solve part (a) in order to solve
this part of the problem.
(b)
x(t) = 3 cos
2 π 12 , 000 t +
π
What is z(t)?
x[n] = sin
πn
1 n is odd, and
n− 1
2
is even
− 1 n is odd, and
n− 1
2
is odd
0 otherwise
You would like to generate a continuous-time audio signal, y(t), using the interpolation formula
y(t) =
∞ ∑
n=−∞
x[n]g (t − n)
In each of the following cases, specify the value of y(t) over the range 0 ≤ t ≤ 4. You may specify y(t)
by drawing a plot of the function (if your plot clearly shows the value at each point in time in the range
0 ≤ t ≤ 4), or by using an equation or a set of cases.
(a) What is y(t) if
g(t) =
1
2
≤ t ≤
1
2
0 otherwise