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An exam for the Combinatorics course at Carnegie Mellon University. It includes three problems with their respective solutions. The exam is closed book and students are not allowed to consult their notes, textbooks, other students or electronic equipment during the exam. The solutions require students to justify their answers and use known series expansions for functions without proof as long as they state what they are using. The exam covers topics such as subsets, edge colouring, and mono-coloured cliques.
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Exam 2 - 3rd March 2015
Name:
This is a closed book exam, you may not consult your notes, textbooks, other students or electronic equipment during the exam. You may use known series expansions for functions with- out proof as long as you state what you are using. If you make use of something we proved during lectures, be very explicit in doing so by stating exactly what results or properties you are using and why they apply. You may not cite without proof theorems you proved on homework/review sheet or read in the book/the internet/elsewhere. You must justify your answers.
Problem Points Score 1 30 2 35 3 35 Total: 100
(a) Prove that (for 1 < k < n), ( n k
(n k
)k .
Solution ( n k
n(n โ 1)... (n โ k + 1) k(k โ 1)... 2 ร 1
n k
n โ 1 k โ 1
n โ 2 k โ 2
n โ k + 1 k โ k + 1
For 1 โค i โค k โ 1 we have that nkโโii > nk. This follows since the following are equivalent statements, n โ i k โ i
n k nk โ ik > nk โ in in > ik n > k,
and we know the final statement is true. This gives us that ( n k
(n k
) (n k
(n k
(n k
)k .
(b) Prove that 2 n n + 1
n bn/ 2 c
โค 2 n.
Solution
(n k
is the number of ways of choosing a subset of size k from a set of size n. We know that the number of ways of choosing a subset of any size from n elements is 2 n^ since each element of [n] can be either in or out of the subset. Therefore for all k,
(n k
< 2 n.
2 ร
The expected number of committees with all members of one team is therefore 30ร 321. Since this is clearly less than 1, and the number of committees with all members on one team can only take integer values, there must be a greater than 0 probability that this value is 0. This tells us that there must exist at least one assignment of students to teams such that the number of committees with all members on one team is 0 and this is the assignment we require.
(n k
cliques of size k and each clique contains
(k 2
edges. The probability that a clique is mono-coloured is 2ร(1/2)(
k 2 ) , since there are two choices of colour for the mono-coloured clique to be and the probability that all of the edges are that colour is (1/2)(
k 2 ) . The expected number of mono-coloured cliques is therefore ( n k
n k
k(k 2 โ1)
n k
k(kโ1) 2
โคnk 2 โ^
k(k 2 โ1)
n 2 โ^
(kโ 2 1)^ )k
n^22 โ(kโ1)
)k 2 .
The third line follows from noting that,
n k
n(n โ 1)... (n โ k + 1) k(k โ 1)... 3 ร 2 ร 1
= n(n โ 1)... (n โ k + 1) k(k โ 1)... 3 ร 1
โค nk.