Complex integration based on residual theorem , Exams of Complex analysis

Complex integration based on residual theorem

Typology: Exams

2017/2018

Uploaded on 02/04/2018

OSAMA-ALSATTARI
OSAMA-ALSATTARI 🇵🇸

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3 2z*7—2z+2 Exercise: “sat such that c:|z| = 3 Solution: z — 2 = 0 > z = 2 inside |z| = 3 lH 2) =li 2 = li Pere ence,res(f,2) = lim(z -—2)f@= lim(z — gaye “ res(f,2) =8 Th —— = 2ni 2)) = 167i us ars z= 2ni(res(f,2)) = 167i