Complex Roots in Trigonometry, Lecture notes of Trigonometry

How to find complex roots of a given complex number in polar form. It defines complex nth roots and provides a formula to find n distinct complex nth roots of a given complex number. The document also includes an example to find the three complex cube roots of a given complex number in polar form.

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2022/2023

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Trigonometry
Ch6Sec6Day3 1 1/26/2019
Section 6.6 Complex Numbers in Polar Form Day 3
Objective:
3) Given complex numbers in polar form, find roots.
Complex Roots
Let w be a given complex number, and let
2n
denote a positive integer. Any complex number z that satisfies the
equation
wzn
is called a complex nth root of w. So, solutions of
wz2
are called the complex square roots of w
and solutions of
wz3
are called the complex cube roots of w.
Theorem Finding Complex Roots
Let
)sincos(rw i
be a complex number. If
,0w
there are n distinct complex nth roots of w,
given by the formula
,
n
k360
n
sin
n
k360
n
cosrz n
k
i
where
.1n,,2,1,0k
Example 9: Find the three complex cube roots of
.31 i
rectangular coordinates
)3,1()y,x(
Quadrant IV
22 yxr
22 )3()1(
31
4
2
Find the reference angle
:
ref
x
y
tan 1
ref
1
3
tan 1
3tan 1
3tan 1
60
is in Quadrant IV, thus,
ref
360
60360
300
Thus, the polar form of
is
)sincos(r31 ii
)300sin300cos(2 i
pf2

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Trigonometry

Ch6Sec6Day3 1 1/26/

Section 6.6 – Complex Numbers in Polar Form – Day 3

Objective:

  1. Given complex numbers in polar form, find roots.

Complex Roots

Let w be a given complex number, and let n  2 denote a positive integer. Any complex number z that satisfies the equation zn^ wis called a complex nth^ root of w. So, solutions of z^2 ware called the complex square roots of w and solutions of (^) z^3 ware called the complex cube roots of w.

Theorem – Finding Complex Roots

Let w  r(cosisin) be a complex number. If w  0 ,there are n distinct complex nth^ roots of w,

given by the formula , n

360 k n

sin n

360 k n

z (^) k n r cos 

  i wherek  0 , 1 , 2 ,,n 1.

Example 9: Find the three complex cube roots of 1  3 i.

1  3 i :^ rectangular coordinates^ (x,y) ( 1 , 3 ) Quadrant^ IV

r  x^2 y^2  ( 1 )^2 ( 3 )^2  1  3  4  2

Find the reference angleref: x

tan 1 y ref  

 tan ^1 ^3

 tan ^1  3 tan ^1  3   60 

 is in Quadrant IV, thus,  360 ref  360   60   300 

Thus, the polar form of 1  3 iis 1  3 ir(cosisin)  2 ( cos 300 ^ isin 300 )

Trigonometry

Ch6Sec6Day3 2 1/26/

Section 6.6 – Complex Numbers in Polar Form – Day 3 (continued)

From the complex root theorem, the three complex cube roots of 1  3 i are

z (^) k 3 2 cos^30033603 k sin^30033603 k , k 0 , 1 , 2 

   

i

 3 2  cos 100  120 k isin 100  120 k , k 0 , 1 , 2

So,

z 0 ^32  cos( 100 ^ )isin( 100 )

z 1  3 2  cos( 100 ^  120 )isin( 100  120 )

z 2 ^32  cos( 100 ^  2 ( 120 ))isin( 100  2 ( 120 ))

^3 2  cos( 100 ^  240 )isin( 100  240 )

Thus the three complex cube roots of 1  3 i are

z 0 ^32  cos( 100 ^ )isin( 100 )

z 1 ^32  cos( 220 ^ )isin( 220 )

z 2 ^32  cos( 340 ^ )isin( 340 )