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Computer Organization and Assembly Language: Assignment 1 Solution, Assignments of Computer Architecture and Organization

University of Arid Agriculture Rawalpindi (UAAR)Computer Architecture and Organization

it assignmnet about computer architecture for details about cpu performance equation and amdal's law example solved

Typology: Assignments

2019/2020

Uploaded on 06/16/2020

mosin92
mosin92 🇵🇰

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CS-530: Computer Organization and Assembly Language @ ARID-UIIT, Assignment 1 Solution
Prepared by [email protected]
1
Solution: (3 Marks)
Ic = 100,000
Effective/Overall CPI = 45,000 × 1 + 32,000 × 2 + 15,000 × 2 + 8,000 × 2
100,000
CPI = 1.55
f = 40 MHz = 40 × 106 Hz
MIPS = 40 × 106
1.55 × 106
MIPS ≈ 25.81
𝜏 = 1
𝑓= 1
40 × 106 s
Execution Time, T = 100,000 × 1.55× 1
40 × 106 s
T = 3.875 ms
pf3

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Prepared by [email protected] Solution: (3 Marks) Ic = 100, Effective/Overall CPI =

45 , 000 × 1 + 32 , 000 × 2 + 15 , 000 × 2 + 8 , 000 × 2

CPI = 1.

f = 40 MHz = 40 × 106 Hz MIPS =

40 × 106

1. 55 × 106

MIPS ≈ 25.8 1

40 × 10

6 s

Execution Time, T = 100,000 × 1.55×

40 × 106

s T = 3.875 ms

Prepared by [email protected] Solution: (7 Marks) a. (6 Marks) CPIA = 40/18 ≈ 2. MIPSA ≈ 90 Execution_TimeA = 18 × 106 × 40/18 × 1 / (200 × 106 ) s = 0.2 s CPIB = 46/24 ≈ 1. MIPSB ≈ 104. Execution_TimeB = 24 × 106 × 46/24 × 1 / (200 × 106 ) s = 0.23s b. (1 Mark) Although machine B has a higher MIPS than machine A, yet it requires a longer CPU time to execute the same set of benchmark programs.