Computer programing lab 12, Exercises of Advanced Computer Programming

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BAHRIA UNIVERSITY LAHORE CAMPUS

LAB JOURNAL 1 2

MUHAMMAD HAMID AZEEM

BSIT 1A

SUBMITTED TO (SIR ZIA UR REHMAN)

COMPUTER PROGRAMING LAB

TASK 1

A phone number, such as (212) 767-8900, can be thought of as having three parts: the

area code (212), the exchange (767), and the number (8900). Write a program that

uses a structure to store these three parts of a phone number separately. Call the

structure phone. Create two structure variables of type phone. Initialize one, and have

the user input a number for the other one. Then display both numbers. The

interchange might look like this: Enter your area code, exchange, and number: 415

555 1212 My number is (212) 76 7 - 8900 Your number is (415) 555- 1212.

CODE: #include #include using namespace std; struct phone { string area; string exchange; string number; }; int main() { cout << "\n\t\t\t\t##########################################################"; cout << "\n\t\t\t\t\t Programme Usning Structure For Phone Number: " << endl; cout << "\t\t\t\t##########################################################"<< endl; phone p1 = { "212","767","8900" }; phone p2; cout << "\n\t\t\t\tEnter your area code, exchange, and number: "; cin >> p2.area >> p2.exchange >> p2.number; cout << "\n\t\t\t\t========================================================="; cout << "\n\t\t\t\tMy number is(" << p1.area << ") "<< p1.exchange<<"-" <<p1.number<<endl; cout << "\n\t\t\t\tYour number is(" << p2.area << ") "<<p2.exchange<<"- "<<p2.number<<endl; return 0; }

TASK 2

A record contains name of cricketer, his age, number of test matches that he has

played and the average runs that he has scored in each test match. Create an array

of structure to hold records of 20 such cricketer and then write a program to read

these records

CODE: #include #include using namespace std; typedef int (compfn)(const void, const void); int comp(struct cricketer, struct cricketer); struct cricketer { char name[10]; int age, tottest, avgrun; }player[20]; int main() { cout << "\n\t\t#################################"; cout << "\n\t\t Record of Cricketers" << endl; cout << "\t\t#################################" << endl; int i, n; cout << "\t\tEnter numbers of Players : "; cin >> n; for (i = 0; i < n; ++i) { cout << "\t\tName : "; cin >> player[i].name; cout << "\t\tAge : "; cin >> player[i].age; cout << "\t\tTotal Test Matches : "; cin >> player[i].tottest; cout << "\t\tAvg Run : "; cin >> player[i].avgrun; } qsort((void)&player, n, sizeof(struct cricketer), (compfn)comp); // Printing cout << "\t\t" << "Name" << "\t" << "Age" << "\t" << "Tests" << "\t" << "Avg"; for (i = 0; i < n; ++i) { cout << endl << "\t\t" << player[i].name << "\t" << player[i].age << "\t" << player[i].tottest << setw(8) << player[i].avgrun; } return 0; } int comp(struct cricketer* a1, struct cricketer* a2) { if (a1->avgrun < a2->avgrun) return - 1; if (a1->avgrun > a2->avgrun)

return 1; else return 0; } OUTPUT:

cout << endl; } } cout << endl; }

OUTPUT:

THANK YOU ☺