






Study with the several resources on Docsity
Earn points by helping other students or get them with a premium plan
Prepare for your exams
Study with the several resources on Docsity
Earn points to download
Earn points by helping other students or get them with a premium plan
A set of lecture notes from rice university's elec 303 course, taught by farinaz koushanfar in fall'08. The notes cover the topic of conditional probability, including definitions, examples, and applications. Students will learn about the multiplication rule, total probability theorem, and bayes rule, as well as how to calculate conditional probabilities using these theorems.
Typology: Study notes
1 / 11
This page cannot be seen from the preview
Don't miss anything!







ELEC 303, Koushanfar, Fall’
Farinaz Koushanfar ECE Dept., Rice University Aug 28, 2008
ELEC 303, Koushanfar, Fall’
ELEC 303, Koushanfar, Fall’
ELEC 303, Koushanfar, Fall’
ELEC 303, Koushanfar, Fall’
P(A|B) = P(A∩B) / P(B)
P(A∩B) = P(B).P(A|B) = P(A).P(B|A)
Ω A B
ELEC 303, Koushanfar, Fall’
ELEC 303, Koushanfar, Fall’
Slide courtesy of Prof. Dahleh, MIT
ELEC 303, Koushanfar, Fall’
P(A)=0.
P(Ac)=0.
Multiplication rule: Assuming that all of the conditioning events have positive probability,
... ( | )
( ) ( ) ( | ) ( | )... (^11)
1 1 2 1 3 1 2 n ni i
ni i PA A
P A PA PA A PA A A =^ −
= = ∩ I
I
ELEC 303, Koushanfar, Fall’
P(B) = P(A 1 ∩B) + P(A 2 ∩B) + P(A 3 ∩B) = P(A 1 )P(B|A 1 )+P(A 2 )P(B|A 2 )+P(A 3 )P(B|A 3 )
A 1 A 2 A 3
B
B
B
Bc
Bc
Bc
A 1 ∩B
A 2 ∩B
A 3 ∩B (^) Figure courtesy of Bertsekas&Tsitsiklis, Introduction to Probability, 2008
ELEC 303, Koushanfar, Fall’
Example courtesy of Prof. Dahleh, MIT
ELEC 303, Koushanfar, Fall’
Example courtesy of Prof. Dahleh, MIT
ELEC 303, Koushanfar, Fall’
{Absent and decision is present}
Example courtesy of Prof. Dahleh, MIT
ELEC 303, Koushanfar, Fall’
Example courtesy of Prof. Dahleh, MIT
ELEC 303, Koushanfar, Fall’
Example courtesy of Prof. Dahleh, MIT
ELEC 303, Koushanfar, Fall’
Let A 1 ,A 2 ,…,An be disjoint events that form a partition of the sample space, and assume that P(Ai) > 0, for all i. Then, for any event B such that P(B)>0, we have
( ) ( | ) ... ( ) ( | )
( ) ( | ) ( )
( | ) ( ) ( | ) 1 1 n n
i i i i i P A P B A P A PB A
P A P B A P B
P A B P A P B A
= =