Conic Sections: Circles, Study notes of Advanced Calculus

Find the center and radius of the circle with equation (x – 1)2 + (y + 3)2 = 196. Then graph the circle. Rewrite the equation as (x – 1)2 + [y – (–3)]2 = 142. ...

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Conic Sections: Circles
Example 1 Write an Equation Given the Center and Radius
Write an equation for the circle with center at (5, 3) and radius 11.
(x h)2 + (y k)2 = r2 Equation of a circle
(x 5)2 + [y (3)]2 = 112 (h, k) = (5, 3), r = 11
(x 5)2 + (y + 3)2 = 121 Simplify.
The equation is (x 5)2 + (y + 3)2 = 121.
Example 2 Write an Equation Given a Diameter
Write an equation for a circle if the endpoints of a diameter are at (3, 7) and (2, 2).
First, find the center of the circle.
(h, k) =
x1 x2
2, y1 y2
2
Midpoint Formula
=
3 2
2, 7 2
2
(x1, y1) = (3, 7), (x2, y2) = (2, 2)
=
1
2, 5
2
Simplify.
Now find the radius.
r =
(x2 x1)2 (y2 y1)2
Distance Formula
=
1
2 (3)2 5
2 (7)2
(x1, y1) = (3, 7), (x2, y2) =
15
,
22
=
5
2
2 9
2
2
Subtract.
=
106
4
Simplify.
The radius of the circle is
106
4
units, so r2 =
or
53
2
. An equation of the circle is
2
1
2
x
+
2
5
2
y
=
53
2
.
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Conic Sections: Circles

Example 1 Write an Equation Given the Center and Radius

Write an equation for the circle with center at (5, – 3) and radius 11.

( xh )^2 + ( yk )^2 = r^2 Equation of a circle ( x – 5)^2 + [ y – (–3)]^2 = 11^2 ( h , k ) = (5, – 3), r = 11 ( x – 5)^2 + ( y + 3)^2 = 121 Simplify.

The equation is ( x – 5)^2 + ( y + 3)^2 = 121.

Example 2 Write an Equation Given a Diameter

Write an equation for a circle if the endpoints of a diameter are at (–3, – 7) and (2, 2).

First, find the center of the circle.

( h , k ) =

x 1 x 2 2

,

y 1 y 2 2

Midpoint Formula

  • 3 2 2

,

  • 7 2 2

( x 1 , y 1 ) = (–3, – 7), ( x 2 , y 2 ) = (2, 2)

1 2

, –

5 2

Simplify.

Now find the radius.

r = ( x 2 –^ x 1 )^2 ( y 2 –^ y 1 )^2 Distance Formula

= –^

1 2

  • (– 3 )

2

5 2

  • (– 7 )

2 ( x 1 , y 1 ) = (–3, – 7), ( x 2 , y 2 ) =

1 5

  • , – 2 2

5 2

(^2 )

2

2 Subtract.

106 4

Simplify.

The radius of the circle is

106 4

units, so r^2 =

106 4

or

53 2

. An equation of the circle is

2

x +

2

y =

53 2

Example 3 Graph an Equation in Standard Form Find the center and radius of the circle with equation ( x – 1)^2 + ( y + 3)^2 = 196. Then graph the circle.

Rewrite the equation as ( x – 1)^2 + [ y – (–3)]^2 = 14^2. The center of the circle is (1, – 3) and the radius is

The table lists some integer values for x and y that satisfy the equation.

x y 1 11 1 – 17 15 – 3

  • 13 – 3

Graph all of these points and draw the circle that passes through them.

Example 4 Graph an Equation not in Standard Form Find the center and radius of the circle with equation x^2 + y^2 + 2 x – 4 y – 11 = 0. Then graph the circle.

Complete the square.

x^2 + y^2 + 2 x – 4 y – 11 = 0 x^2 + 2 x + • + y^2 – 4 y + • = 11 + • + • x^2 + 2 x + 1 + y^2 – 4 y + 4 = 11 + 1 + 4 ( x + 1)^2 + ( y – 2)^2 = 16

The center of the circle is at (–1, 2), and the radius is 4. Locate the center and then find several points located 4 units from the center. Draw the circle that passes through them.

( x + 1)^2 + ( y - 2)^2 = 16