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Find the center and radius of the circle with equation (x – 1)2 + (y + 3)2 = 196. Then graph the circle. Rewrite the equation as (x – 1)2 + [y – (–3)]2 = 142. ...
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Write an equation for the circle with center at (5, – 3) and radius 11.
( x – h )^2 + ( y – k )^2 = r^2 Equation of a circle ( x – 5)^2 + [ y – (–3)]^2 = 11^2 ( h , k ) = (5, – 3), r = 11 ( x – 5)^2 + ( y + 3)^2 = 121 Simplify.
The equation is ( x – 5)^2 + ( y + 3)^2 = 121.
Write an equation for a circle if the endpoints of a diameter are at (–3, – 7) and (2, 2).
First, find the center of the circle.
( h , k ) =
x 1 x 2 2
,
y 1 y 2 2
Midpoint Formula
,
( x 1 , y 1 ) = (–3, – 7), ( x 2 , y 2 ) = (2, 2)
1 2
, –
5 2
Simplify.
Now find the radius.
1 2
2
5 2
2 ( x 1 , y 1 ) = (–3, – 7), ( x 2 , y 2 ) =
1 5
5 2
(^2 )
2
2 Subtract.
106 4
Simplify.
The radius of the circle is
106 4
units, so r^2 =
106 4
or
53 2
. An equation of the circle is
2
2
53 2
Example 3 Graph an Equation in Standard Form Find the center and radius of the circle with equation ( x – 1)^2 + ( y + 3)^2 = 196. Then graph the circle.
Rewrite the equation as ( x – 1)^2 + [ y – (–3)]^2 = 14^2. The center of the circle is (1, – 3) and the radius is
The table lists some integer values for x and y that satisfy the equation.
x y 1 11 1 – 17 15 – 3
Graph all of these points and draw the circle that passes through them.
Example 4 Graph an Equation not in Standard Form Find the center and radius of the circle with equation x^2 + y^2 + 2 x – 4 y – 11 = 0. Then graph the circle.
Complete the square.
x^2 + y^2 + 2 x – 4 y – 11 = 0 x^2 + 2 x + • + y^2 – 4 y + • = 11 + • + • x^2 + 2 x + 1 + y^2 – 4 y + 4 = 11 + 1 + 4 ( x + 1)^2 + ( y – 2)^2 = 16
The center of the circle is at (–1, 2), and the radius is 4. Locate the center and then find several points located 4 units from the center. Draw the circle that passes through them.
( x + 1)^2 + ( y - 2)^2 = 16