Conjugate Pairs Practice #1, Study notes of Logic

Key Skill: Labeling the Acid and Base. Tie lines allow us to figure out if the substance was an acid or a base. We can do this by determining if the reactant ...

Typology: Study notes

2022/2023

Uploaded on 02/28/2023

rubytuesday
rubytuesday 🇺🇸

4.4

(38)

273 documents

1 / 6

Toggle sidebar

This page cannot be seen from the preview

Don't miss anything!

bg1
Name: KEY
Conjugate Pairs Practice #1
Key Skill: Learning to Draw Tie Lines
Look at each example drawn below. Sets of partners (called conjugates) are matched
with “tie lines”.
HNO3 + OH- NO3- + H2O
CH3NH2 + H2O CH3NH3+ + OH-
HCl + H2O H3O+ + Cl-
Note that conjugates are the same compound that has either gained or lost an H+. One
of the reactants is always matched with one of the __products__ (reactants or products)
Draw tie lines for each of these reactions:
(a) OH- + HPO4-2 PO4-3 + H2O
(b) NH3 + HBr NH4+ + Br-
(c) HC2H3O2 + H2O H3O+ + C2H3O2
pf3
pf4
pf5

Partial preview of the text

Download Conjugate Pairs Practice #1 and more Study notes Logic in PDF only on Docsity!

Name: KEY

Conjugate Pairs Practice

Key Skill: Learning to Draw Tie Lines

Look at each example drawn below. Sets of partners (called conjugates) are matched with “tie lines”.

HNO 3 + OH-^  NO 3 -^ +^ H 2 O

CH 3 NH 2 + H 2 O  CH 3 NH 3 +^ + OH-

HCl + H 2 O  H 3 O+^ + Cl-

Note that conjugates are the same compound that has either gained or lost an H+. One of the reactants is always matched with one of the products (reactants or products)

Draw tie lines for each of these reactions:

(a) OH-^ + HPO 4 -2^  PO 4 -3^ + H 2 O

(b) NH 3 + HBr  NH 4 +^ + Br-

(c) HC 2 H 3 O 2 + H 2 O  H 3 O+^ + C 2 H 3 O 2 

Gained H+

Gained H+

Gained H+ Lost H+

Lost H+

Lost H+

Key Skill: Labeling the Acid and Base.

Tie lines allow us to figure out if the substance was an acid or a base. We can do this by determining if the reactant “gained” or “lost” H+. Look at these examples: Gained H+

HNO 3 + OH-^  NO 3 -^ +^ H 2 O

Lost H+

 Since acids lose (or donate) H+, then HNO 3 is the acid.  Since bases gain H+, then OH-^ is the base.

Lost H+

CH 3 NH 2 + H 2 O  CH 3 NH 3 +^ + OH-

Gained H+

 Since acids lose (or donate) H+, then H 2 O is the acid.  Since bases gain H+, then CH 3 NH 2 is the base.

  1. Notice only the ___reactants____ (reactants or products) get labeled as an acid or a base.
  2. Draw tie lines and label the tie lines with ( Lost H+^ or Gained H+) as in the examples above. Then record the acid and base in the space provided.

(a) H 2 SO 4 + NH 3  HSO 4 ^ + NH 4 ^ __H 2 SO 4 _(acid) _NH 3 __ (base)

(b) NH 3 + HBr  NH 4 +^ + Br-^ HBR__(acid) _NH 3 __ (base)

(c) HC 2 H 3 O 2 + H 2 O  H 3 O+^ + C 2 H 3 O 2 _HC 2 H 3 O 2 __(acid) H 2 O (base)

Key Skill: Predicting the conjugate without an equation.

Example problem 1:

What is the conjugate base of H 2 O?

Solution:

When we draw tie lines, the conjugate base is always attached to an acid. (Check page 3 to confirm this.) So if the problem wants us to find a conjugate base of H 2 O, then water must be an acid.

H 2 O ?

Acid conjugate Base

Since acids donate (give away) H (see page 2 to confirm this) then the conjugate base must have one less H than H 2 O. Answer: OH-

Example problem 2:

What is the conjugate acid of H 2 PO 4 -?

Solution:

If the problem wants us to find a conjugate acid of H 2 PO 4 - , then H 2 PO 4 -^ must be an base.

H 2 PO 4 -^ ?

Base conjugate Acid

Since bases accept H (see page 2 to confirm this) then the conjugate acid must have one more H than H 2 PO 4 -. Answer: H 3 PO 4

  1. Try the same logic on this problem:

What is the conjugate acid of NH 2 -?

NH 2 -^ ?

Base conjugate acid_

The answer is a conjugate acid according to the problem.

Is NH 2 -^ going to gain or lose an H to become the conjugate acid? Gain

What is the formula of the conjugate acid? __NH 3 __

  1. Try the same logic on this problem:

What is the conjugate base of HCO 3 -?

HCO 3 -^ ?

Acid conjugate base

The answer is a conjugate acid according to the problem.

Is HCO 3 -^ going to gain or lose an H to become the conjugate base? lose

What is the formula of the conjugate base? _CO 3 2-

Fill in the blank: is NH 2 -^ an a cid or base?

Fill in the blank: is HCO 3 -^ an a cid or base?