Connectedness and Continuous Functions in Metric Spaces, Essays (high school) of Mathematics

Theorems about continuous functions in the context of connectedness and compactness in metric spaces. The author covers the preservation of connectedness and compactness by continuous functions, the relationship between path-connectedness and connectedness, and the uniform continuity of continuous functions on compact sets. The document also includes proofs and corollaries related to these topics.

Typology: Essays (high school)

2011/2012

Uploaded on 04/06/2012

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Connectedness Continued
Adrian Down 16779577
August 9, 2005
1 Last Time
Wanted to generalize theorems about continuous functions to general metric
spaces. Had to generalize closed intervals, which is compactness. From last
time, Ecompact and fcontinuous f(E) is compact. Also, Econnected
and fcontinuous f(E) is connected. Continuous functions preserve con-
nectedness and compactness.
Recall: 1) Eis connected if Eis not disconnected. Eis disconnected if
open sets U1, U2such that
U1U2=
EU1U2
EU16=
EU26=
2) Uopen in S2and f:S1S2is continuous, then f1(U) is open in S1.
Also, Eclosed in S2, f 1(E) is closed in S1,f1(E) = S1r(f1(S2rE)).
3) ESis path-connected if x, y E, a path from xto yin E, i.e.
γ: [a, b]S,γcontinuous, γ(a) = x, γ(b) = y, γ (t)E, a tb.
Notes: i) γ[a, b] is compact in Sand connected.
ii) If a path from xto yand a path from yto z, then a path from x
to z.
Let γ1[a, b]S,γ1(a) = x, γ1(b) = y,γ2[b, d]S, γ2(c) = y, γ2(d) = z.
γ2can always be arranged to go from bby change of variables. Now let
γ: [a, b]S, γt=(γ1(t)atb
γ2(t)btd
Theorem: Eis path connected Eis connected.
1
pf3

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Connectedness Continued

Adrian Down 16779577

August 9, 2005

1 Last Time

Wanted to generalize theorems about continuous functions to general metric spaces. Had to generalize closed intervals, which is compactness. From last time, E compact and f continuous ⇒ f (E) is compact. Also, E connected and f continuous ⇒ f (E) is connected. Continuous functions preserve con- nectedness and compactness. Recall: 1) E is connected if E is not disconnected. E is disconnected if ∃ open sets U 1 , U 2 such that

U 1 ∩ U 2 = ∅ E ⊆ U 1 ∪ U 2 E ∩ U 1 6 = ∅ E ∩ U 2 6 = ∅

  1. U open in S 2 and f : S 1 → S 2 is continuous, then f −^1 (U ) is open in S 1. Also, E closed in S 2 , f −^1 (E) is closed in S 1 , f −^1 (E) = S 1 r (f −^1 (S 2 r E)).
  2. E ⊆ S is path-connected if ∀x, y ∈ E, ∃ a path from x to y in E, i.e. γ : [a, b] → S, γ continuous, γ(a) = x, γ(b) = y, γ(t) ∈ E, a ≤ t ≤ b. Notes: i) γ[a, b] is compact in S and connected. ii) If ∃ a path from x to y and a path from y to z, then ∃ a path from x to z. Let γ 1 [a, b] → S, γ 1 (a) = x, γ 1 (b) = y, γ 2 [b, d] → S, γ 2 (c) = y, γ 2 (d) = z. γ 2 can always be arranged to go from b by change of variables. Now let

γ : [a, b] → S, γt =

γ 1 (t) a ≤ t ≤ b γ 2 (t) b ≤ t ≤ d Theorem: E is path connected ⇒ E is connected.

2 Proofs from last lecture

Theorem: if E ⊆ S is compact and f : S 1 → S 2 is continuous, then f is uniformly continuous on E. Note: another way that compact sets are like closed intervals. Recall the analogous theorem from R. Going to use the idea of a generalized Bolzano- Weirstrass theorem and open covers.

Proof. Let  > 0 be given. f is continuous ⇒ ∀s ∈ E, ∃δs > 0 that satisfies the definition of continuity, Bδs (s) ⊆ f −^1 (B  2 (f (s)). Let Us = Bδs (s), ∀s ∈ E. Then (Us)s∈E is an open cover (it is a collected of open balls, and for any x ∈ E, x ∈ Bδx (x) ⇒

Us ⊃ E). E compact ∃ a finite subcover, call it U 1 ,... , Un, i.e. Bδ 1 (s 1 ),... , Bδn (sn). Let δ = 12 min{δ 1 ,... , δn} > 0. If s, t ∈ E with d(s, t) < δ, then their distance is less then ever δi, so s ∈ Bδi (si) for some i. d(s, t) < 12 δi ⇒ t ∈ Bδi (si) by the triangle inequality. Idea is that we made an open ball around each point in E. Then we took a finite number of those that cover all of E. Let δ be less than half of the smallest radius Now we’re almost done. d 2 (f (s), f (si)) <  2 and d(f (st), f (si)) < 2  ⇒ d 2 (f (s), f (t)) < . Thus f is uniformly continuous.

Important for generalizing things like integration. Also useful for other properties of uniformly continuous functions, as follows. Corollary: 1) if f is uniformly convergent on E and (sn) is a Cauchy sequence in E then (f (sn)) is Cauchy. Proof: Left to you. Emulate the proof from R

  1. if f is uniformly continuous on E ⊆ S, then f extends continuously to E¯ (i.e. ∃ F˜ : E¯ → S 2 such that f˜ is continuous and f˜ (x) = f (x), ∀x ∈ E assuming that S 2 is complete. Theorem: 1) if E ⊆ R is connected, then E is an interval
  2. any interval I ⊆ R is connected. Proof: x, y ∈ I ⇒ [x, y] ∈ I. Let γ : [x, y] → R,, γ(t) = t ⇒ γ is a path from x to y in I. So I is path-connected ⇒ I is connected. For a more “hands on” proof, se Ross for a proof by contradiction. End result is... Corollary: E is connected ⊆ R ⇔ E is an interval. Always true that path-connected ⇒ connected. Theorem: if E ⊆ Rk^ is open and connected, then E is path-connected.