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This assignment wa given by Prof. Bhuvanesh Sankuratri at Baddi University of Emerging Sciences and Technologies for Digital Signal Processing course. Its main points are: CT, DT, Systems, Linear, Time, Invariant, LTI, Inputs, Invertible, Differential, Equations
Typology: Exercises
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ii) (^) y t ( ) tx t ( 10)
iii) (^) ( ) 0 t< ( ) ( 5) t 0
y t x t x t
° ® °¯ ^ ^ t
iv) y ( t ) x ( ) d 2 x ( t )
o
o
t
t
v) 3 5 3 () 2 2 () 1
2 2
2 3
3 4
4 xt dt
d x yt dt
dy dt
d y dt
d y dt
d y
ii) [ ] [ ] 2 | []|
2
2
y k xm x k
k
m k
iii) y [ k ] 2 x [ k ] iv) y [ k ] 5 y [ k 1 ] 9 y [ k 2 ] 5 y [ k 3 ] y [ k 4 ] 2 x [ k ] 4 x [ k 1 ] 2 x [ k 2 ]
iv) 3 ()
xt dt
dx t
y ( t )
t
y ( t )
t
Figure P3: CT output y ( t ) for problem 3.
i) 4 x [ k − 1 ] ii) 0. 5 x [ k − 2 ]+ 0. 5 x [ k + 2 ] iii) x [ k + 1 ]− 2 x [ k ]+ x [ k − 1 ] iv) x [ − k ] y [ k ]
k
y [ k ]
k
Figure P4: DT output y [ k ] for problem 4.
i) y ( t )= 3 x ( t + 2 )
t yt x tdt 0
iii) y ( t )= x ( t ) iv) y ( t )=cos( 2 π t )
i) y [ k ]= ( k + 1 ) x [ k + 2 ]
=
k
m
yk xm 0
iii) y [ k ]= x [ k + 2 ]+ 2 x [ k + 1 ]− 6 x [ k ]+ 2 x [ k − 1 ]+ x [ k − 2 ] iv) y [ k ]+ 2 y [ k − 1 ]+ y [ k − 1 ]= x [ k ]
i) y t &&( ) + 4 y t & ( ) + 8 y t ( ) = x t & ( ) + x t ( ) with x t ( ) = e −^4 tu t ( ), y (0) = 0, and y &(0) =0. ii) (^) y t &&( ) (^) + 6 y t & (^) ( ) + 4 y t ( ) = x t & (^) ( ) + x t ( ) with x t ( ) = cos(6 ) ( ), t u t y (0) = 2, and y &(0) =0. iii) y t &&( ) + 4 y t ( ) = 5 ( ) x t with x t ( ) = 4 te − tu t ( ), y (0) = − 2, and y &(0) =0. iv) &&&& y t ( )^ + 2 && y t ( )^ + y t ( ) = x t ( ) with x t ( ) = 2 ( ), u t y (0) = 0, and y &(0) =1.