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The ControlF Demystifying Hex Data (DHD) Exam is designed to build deep foundational understanding of hexadecimal data interpretation for digital forensics professionals. It covers number systems, byte and bit-level data representation, file signatures, data structures, endianness, and manual hex analysis techniques. Candidates learn how to interpret raw binary data to identify artifacts, reconstruct files, and validate forensic findings when automated tools are insufficient.
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Question 1. Which hexadecimal value represents the decimal number 255? A) 0xFA B) 0xFF C) 0x7F D) 0xC Answer: B Explanation: 0xFF in hexadecimal equals 15×16 + 15 = 255 in decimal. Question 2. In a little‑endian system, how is the 32‑bit value 0x12345678 stored in memory (lowest address first)? A) 12 34 56 78 B) 78 56 34 12 C) 34 12 78 56 D) 56 78 12 34 Answer: B Explanation: Little‑endian stores the least‑significant byte first, so the order is 78 56 34 12. Question 3. A nibble consists of how many bits? A) 2 B) 4 C) 8 D) 16 Answer: B Explanation: A nibble is half a byte, i.e., 4 bits. Question 4. Which binary pattern corresponds to the ASCII character ‘A’?
Answer: A Explanation: ASCII ‘A’ has decimal 65, which is 01000001 in binary. Question 5. What does the Byte Order Mark (BOM) 0xEF 0xBB 0xBF indicate? A) UTF‑16LE encoding B) UTF‑8 encoding C) UTF‑32BE encoding D) No encoding, just a null terminator Answer: B Explanation: The sequence EF BB BF is the UTF‑8 BOM, used to signal UTF‑8 text. Question 6. Which of the following is a valid UTF‑16LE byte order for the character ‘Ω’ (U+03A9)? A) 0x03 0xA B) 0xA9 0x C) 0x00 0x03 0xA9 0x D) 0xA9 0x00 0x03 0x Answer: B Explanation: UTF‑16LE stores the low‑order byte first, so U+03A9 becomes A9 03. Question 7. The base64 string “SGVsbG8=” decodes to which ASCII text? A) Hello
C) application/zip D) text/plain Answer: C Explanation: “PK\x03\x04” is the ZIP file signature; MIME type is application/zip. Question 11. When carving a PDF from raw data, which sequence marks the end of the file? A) 0x00 0x00 0x00 0x B) %%EOF C)