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An examination paper for the module technological mathematics 312 in the bachelor of engineering in civil engineering program at institute of technology carlow. Instructions for the examination, four question prompts, and data for use in solving the problems. The questions cover topics such as forward and linear interpolation, least squares method, inverse and laplace transforms, line integrals, and double and triple integrals.
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Semester 2 Examinations 2009/
Module Code: MATH 7021
School: Building & Civil Engineering
Programme Title: Bachelor of Engineering in Civil Engineering – Year
Programme Code: CCIVL-7-Y
External Examiner(s): Internal Examiner(s): Dr.P.RobinsonMr. T. O Leary
Instructions: Select any four questions. These questions carry equal marks.
Duration: 2 Hours Sitting: Autumn 2010
Requirements for this examination:
Note to Candidates: correct examination paper. Please check the Programme Title and the Module Title to ensure that you have received the If in doubt please contact an Invigilator.
(i) (^) s (^2) - 4s6s 8 (ii) (^) s (^2) - 6s^12 13 (9 marks)
(b) By using Laplace Transformations solve the differential equations (i) ddt^2 x 2 4x10et x(0)x(0) 0
(ii) ddt^2 x 2 4 dxdt 4x10et x(0)x(0) 0 (16 marks)
(a) By using the Least Squares method fit a parabola to the set of points (-2,2), (-1,1), (0,2), (1,0), (2,4) (9 marks) (b) By using Gaussian Elimination with partial pivoting solve the set of simultaneous equations (I) below. All calculations should be correct to two places of decimal. or By using Gaussian Elimination without partial pivoting solve the set of simultaneous equations (II) below
z
y
x 5 10 6
1 2 3 1 x 6 2 7 7 3 y 0 3 9 8 6 z 0 4 5 3 7 w 0
(8 marks)
(c) Consider the set of simultaneous equations 10x+y= x+10y= The solution of this set of equations is close to x=0.1, y=0.2. Use two iteration of Jacobis Method and two iterations of the Gauss Siedel Method to find correct to two places of decimal further approximations to the solution of this set of equations. (8 marks)
f(x) a=constant n f (x) lnx^ x^ nx^ n^1 x
eax a eax cosx^ sinx^ -sinxcosx uv dx vdu dx u dv v
u v^2 dx
udv dx v du
INTEGRALS
xn xn+1 (^) if n - n+1 x
1 lnx eax^1 sinx a-cosx^ a^ eax cosx sinx INTERPOLATION (^1 20 0 2 1 0 ) 0 1 0 2 1 0 1 2 2 0 2 1 f(x) = (x - x )(x - x ) f(x ) + (x - x )(x - x )^ f(x ) + (x - x )(x - x ) f(x ) (x - x )(x - x ) (x - x )(x - x ) (x - x )(x - x ) f(x 0 rh)f(x 0 )rf 0 r(r2!-1)^2 f 0 ...
y (x 0 rh) (^1) h^ ^ y 0 2r-12! ^2 y 0 f (x^0 rh)h^1 ^ rf 0 (2r2!-1)^2 f 0 ...