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This is the Exam of Multivariable Calculus and its key important points are: Critical Point, Saddle Point, Local Minimum, Local Maximum, Total DiErential, Linearization, Standard Linear Approximation, Tangent Plane, Surface, Function
Typology: Exams
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(1) there are no critical points. (2) f has a saddle point at the critical point (− 2 , 0). (3) f has a local minimum at the critical point (0, 0). (4) f has a local maximum at the critical point (− 2 , 0).
(1) 1. 02 (2) 1. 03 (3) 1. 05 (4) 1. 07
f (x, y, z) = 2x^2 y + z^4 y^2
increases fastest in the direction of the vector
(1) i + k (2) i + j + k (3) 4i (4) j − k
0
y/ 2
ex 2 dx dy
is (1) e^9 − 1 (2) e^36 − 1 (3) 5e^9 − 1 (4) e^18 − 1
(1)
∫ (^) π
0
∫ (^) 1+sin θ
1
r dr dθ
∫ (^) π
0
1+sin θ
r dr dθ
−π
1+sin θ
r dr dθ
∫ (^2) π
π
∫ (^) 1+sin θ
1
r dr dθ
0
0
0
z dx dy dz
0
0
x+y
z dz dx dy
0
∫ (^1) −y
0
x+y
z dz dx dy
0
∫ (^1) −y
0
∫ (^1) −x−y
0
z dz dx dy
∫ (^2) π
0
0
∫ √ 16 −r 2
r/√ 3
r dz dr dθ.
When re-expressed in spherical coordinates, this volume equals
∫ (^2) π
0
∫ (^) π/ 3
0
0
ρ^2 sin φ dρ dφ dθ
∫ (^2) π
0
∫ (^) π/ 3
0
∫ (^4) / cos φ
0
ρ^2 sin φ dρ dφ dθ
∫ (^2) π
0
∫ (^) π/ 6
0
0
ρ^2 sin φ dρ dφ dθ
∫ (^2) π
0
∫ (^) π/ 6
0
√3 cos φ^ ρ
(^2) sin φ dρ dφ dθ
an+ an
= 3. Then
the open interval of convergence for the power series
∑^ ∞
n=
an 2 n^
xn
is (1) (− 6 , 6) (2) (−
(1) (x − π 2
(x − π 2
(x − π 2
(x − π 2
(x − π 2
π 2
π 2
π 2
x^2 +
x^4
k=
ak has partial sums sn =
∑^ n
k=
ak satisfying sn = 3 +
2 n^
Then
(1) the series
k=
ak diverges because (^) nlim→∞ sn = 3.
(2) the series
k=
ak converges to 4 because
n=
2 n^
(3) the series
k=
ak diverges because lim k→∞ ak 6 = 0.
(4) the series
k=
ak converges to 3 because (^) nlim→∞ sn = 3.