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Feb 1 2010 Material Type: Notes; Class: Multivariable Calculus Engrs; Subject: Mathematics; University: Cornell University; Term: Spring 2010;
Typology: Study notes
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I (^) We learned about the cross product of two vectors and the
triple scalar product and its relation to volume (and flux).
The triple scalar product (~u ร ~v ) ยท w~ =
I (^) We learned about the cross product of two vectors and the
triple scalar product and its relation to volume (and flux).
The triple scalar product (~u ร ~v ) ยท w~ =
I
w 1
u 2 u 3
v 2 v 3
โ w 2
u 1 u 3
v 1 v 3
u 1 u 2
v 1 v 2
u 1 u 2 u 3
v 1 v 2 v 3
w 1 w 2 w 3
I (^) It is helpful to know some properties of determinants when
computing cross products or triple scalar products. If the
matrix B was obtained from A by interchanging two rows,
then detA = โdetB. If B was obtained from A by multiplying
a row of A by a scalar, ฮฑ, then detB = ฮฑdetA.
I (^) Definition A vector equation for the line L through
P 0 (x 0 , y 0 , z 0 ) parallel to ~v is
~r (t) =< x 0 , y 0 , z 0 > +t~v , โโ < t < โ.
I (^) True or False: Once you are given a point on a line and a
direction vector, there is exactly one parametrization for the
line in space through that point and in that direction.
I (^) False. ~r 1 (t) =< 0 , 2 , 1 > +t < 1 , 1 , 1 > and
r ~ 2 (t) =< 1 , 3 , 2 > +t < โ 2 , โ 2 , โ 2 > are two different
parametrizations for the same line in space. How can you tell?
I (^) True or False: Once you are given a point on a line and a
direction vector, there is exactly one parametrization for the
line in space through that point and in that direction.
I (^) False. ~r 1 (t) =< 0 , 2 , 1 > +t < 1 , 1 , 1 > and
r ~ 2 (t) =< 1 , 3 , 2 > +t < โ 2 , โ 2 , โ 2 > are two different
parametrizations for the same line in space. How can you tell?
I (^) The vector from (0, 2 , 1) to (1, 3 , 2) is parallel to < 1 , 1 , 1 >
and to < โ 2 , โ 2 , โ 2 >. So these points are on each of the
lines. They must be the same line.
I (^) True or False: The equations
x = sin t, y = 3 โ 2 sin t, z = 1 + sin t, โโ < t < โ
parametrizes the same point set as the equations
x = s, y = 3 โ 2 s, z = 1 + s , โโ < s < โ.
I (^) True or False: The equations
x = sin t, y = 3 โ 2 sin t, z = 1 + sin t, โโ < t < โ
parametrizes the same point set as the equations
x = s, y = 3 โ 2 s, z = 1 + s , โโ < s < โ.
I (^) False. If we let s = sin t we see that these equations describe
some of the same points in space. However, for all
โโ < t < โ, โ 1 โค sin t โค 1. As a result
x = sin t, y = 3 โ 2 sin t, z = 1 + sin t, traces out the line
segment between (โ 1 , 5 , 0) and (1, 1 , 2) over and over. In
contrast x = t
3 , y = 3 โ 2 t
3 , z = 1 + t
3 , โโ < t < โ does
parametrize the same line as x = s, y = 3 โ 2 s, z = 1 + s ,
โโ < s < โ.
I (^) How can you tell whether two lines intersect?
I (^) Answer: Use different names for the parameters (say s and t)
and see whether there are any solutions to the system
x 1 (t) = x 2 (s), y 1 (t) = y 2 (s), and z 1 (t) = z 2 (s).
I (^) How can you tell whether two lines intersect?
I (^) Answer: Use different names for the parameters (say s and t)
and see whether there are any solutions to the system
x 1 (t) = x 2 (s), y 1 (t) = y 2 (s), and z 1 (t) = z 2 (s).
I (^) How can you tell if two lines go through the same point at the
same โtimeโ?
I (^) First a very familiar way, the โequation of a lineโ
f (x) = y = 3x + 7
y
x
y=3x+
(0,7)
I (^) By rewriting y = 3x + 7 as 3(x โ 0) + (โ1)(y โ 7) = 0 we see
that a point (x, y ) is on the line iff
< x โ 0 , y โ 7 > ยท < 3 , โ 1 >= 0.
<3,โ1>
y
x
(0,7)
(x,y)
(x,y)
<xโ0,yโ7>
<xโ0,yโ7> <โ3,1>
I (^) We can compute the direction vector and write a vector
equation of the line through the two points:
r (t) =< 1 , 10 > +t < 1 , 3 >=< 1 + t, 10 + 3t >
<1,10>
y
x
t=
t=2 <1,10>+2<1,3>
t=โ (^4) <1,10>โ4<1,3>
I (^) The vector equation gives us the parametric equations
x = 1 + t, and y = 10 + 3t.
I. Using a point and a normal vector
I (^) Given a point, P(1, 2 , 3) and a normal vector, ~n =< 7 , 2 , 4 >,
a point (x, y , z) is on the plane that contains P and is
perpendicular to ~n iff < x โ 1 , y โ 2 , z โ 3 > ยท < 7 , 2 , 4 >= 0,
or
7 x + 2y + 4z โ 23 = 0
<7,2,4>
X Y
Z
(3,1,0) (^) (1,8,0)
(1,2,3)