crystal cheat sheet - Lecture Notes | MAT SCI 104, Study notes of Materials science

crystal cheat sheet Material Type: Notes; Professor: Gronsky; Class: Materials Characterization; Subject: Materials Science And Engineering; University: University of California - Berkeley;

Typology: Study notes

2011/2012

Uploaded on 02/12/2012

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dimer
Eo=A
-|V|=B
H = [A B;B A]
energy eigen values satisfy:
0 = (A-E)^2-B^2
solve for E:
will be + and -
ยฑ
%%
โˆ†E total = Erep - B
minimized when:
โˆ‚โˆ†E total /โˆ‚d=0
then, plug back in to โˆ†E total
to find at equilibrium
Lennard-Jones potential
energy/atom = 2ษ›โˆ‘'[(๐œŽ/a)ยนยฒ *A12- (๐œŽ/a)โถ *A6]
to minimize set dervative to 0
โˆ‚energy/โˆ‚atom = 2ษ›โˆ‘'[-12/a(๐œŽ/a)ยนยฒ *A12- 6/a(๐œŽ/a)โถ *A6]
12*A12*(๐œŽ/a)โถ = 6*A6
(๐œŽ/a)โถ = A6/2A12
a = ๐œŽ(2*A12/A6)^1/6
%%
to find total energy per atom
plug in values
Cohesive energy per atom:
Ecoh = -ษ›/2*A6^2/A12
Bulk Modui = Ecoh/[(# of atoms)*V^3]
Bfcc = (16ษ›/๐œŽ^3)(A6/sqrt(2))(A6/A12)^3/2
Bbcc = (8ษ›/๐œŽ^3)(A6/sqrt(2))(A6/A12)^3/2
Bm= (#ofatoms)*(4ษ›/๐œŽ^3)(A6/sqrt(2))(A6/A12)^3/2
Tensors
transformation rule:
%2nd---
๐œŽ'ij = aik ajl ๐œŽkl
strain = ษ›'ij =1/2(eij + eji)
aij = e'i * ej
Cijkl
11 = 1
22 = 2
33 = 3
23 or 32 = 4
13or 31 = 5
12 or 21 = 6
a matrix for:
primed to unprimed
%four-fold---
pf2

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dimer Eo=A -|V|=B H = [A B;B A] energy eigen values satisfy: 0 = (A-E)^2-B^ solve for E: will be + and - ยฑ %% โˆ†E total = Erep - B minimized when: โˆ‚โˆ†E total /โˆ‚d= then, plug back in to โˆ†E total to find at equilibrium Lennard-Jones potential energy/atom = 2 ษ›โˆ‘'[(๐œŽ/a)ยนยฒ A12- (๐œŽ/a)โถ A6] to minimize set dervative to 0 โˆ‚energy/โˆ‚atom = 2 ษ›โˆ‘'[-12/a(๐œŽ/a)ยนยฒ A12- 6/a(๐œŽ/a)โถ A6] 12A12(๐œŽ/a)โถ = 6A (๐œŽ/a)โถ = A6/2A a = ๐œŽ(2A12/A6)^1/ %% to find total energy per atom plug in values Cohesive energy per atom: Ecoh = -ษ›/2A6^2/A Bulk Modui = Ecoh/[(# of atoms)V^3] Bfcc = (16ษ›/๐œŽ^3)(A6/sqrt(2))(A6/A12)^3/ Bbcc = (8ษ›/๐œŽ^3)(A6/sqrt(2))(A6/A12)^3/ Bm= (#ofatoms)*(4ษ›/๐œŽ^3)(A6/sqrt(2))(A6/A12)^3/ Tensors transformation rule: %2nd--- ๐œŽ'ij = aik ajl ๐œŽkl strain = ษ›'ij =1/2(eij + eji) aij = e'i * ej Cijkl 11 = 1 22 = 2 33 = 3 23 or 32 = 4 13or 31 = 5 12 or 21 = 6 a matrix for: primed to unprimed %four-fold---

a 2= [0 1 0;-1 0 0;0 0 1] a 3= [-1 0 0;0 -1 0;0 0 1] a 4 = [0 -1 0;1 0 0;0 0 1] Quantum wavef(nLm) n==energy level L=0:n- m=-L:L Lhat^2 = angular momentum squared = hbar^2L(L+1)sighnew Lhatz = sigh(nlm = hbarmsighnew hamiltonian Hhat = That + Vhat That = kinetic energy Vhat = Potential energy %En = hbar^2pi^2/(2mass(e)Length^2)n = (coeff of waved)^2hbar(3rd index = m) = โˆ‘(nlm)|bnlm|^2hbarm = (coeff of waved)^2E(1st index = n) = โˆ‘(nlm)|bnlm|^2En <L^2> = (coeff of waved)^2hbar^2(L(1+L)) L = sec index = โˆ‘(nlm)|bnlm|^2hbar^2L(L+1) %if one dimensional nanowire En //where n = sub of wavef probability = (coeff of wavef)^ wavef--- SIG(x,to) = exp(-iEn*(t-to)/hbar) * sig n(x) ///where n = last time of measured subscript of E