Current Electricity on General Physics | PHYS 212, Study notes of Physics

Material Type: Notes; Class: General Physics: Electricity and Magnetism; Subject: Physics; University: Penn State - Main Campus; Term: Unknown 1989;

Typology: Study notes

Pre 2010

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Chapter 26 CURRENT
Chapter 26 CURRENT
ELECTRICITY
ELECTRICITY
Electric Current (I)
Electric Current (I)
rate of positive charge passing through a
rate of positive charge passing through a
surface
surface I=
I=dQ/dt
dQ/dt
units
units Coulomb/Second = Ampere
Coulomb/Second = Ampere (C/s = A)
(C/s = A)
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Chapter 26 CURRENT

Chapter 26 CURRENT

ELECTRICITY

ELECTRICITY

Electric Current (I)

Electric Current (I)

rate of positive charge passing through a rate of positive charge passing through a

surface surface

I=

I=dQ/dt

dQ/dt

units units Coulomb/Second = Ampere

Coulomb/Second = Ampere (C/s = A)

(C/s = A)

Current Flow of Charge

Atomic Model for current Atomic Model for current

x

A

ne

Q

Δ

=

Δ

n = number of charges/ n = number of charges/vol

vol

e = magnitude of charge e = magnitude of charge

A

t

x

ne

t

Q

Δ

Δ

=

Δ

Δ

take limit as take limit as

t t goes to 0

goes to 0

A

d

t

dx

ne

d

t

dQ

=

A

nev

I

d

=

d

nev

A

I

J

d

v

ne

J

r

r

=

Current Density

Current Density

Current per area

Current per area

vector quantity

vector quantity

J

r

relation to current via dot product

relation to current via dot product

A

J

I

r

r

Ohm Ohm

’ ’

s Law s Law

Vector field equation

Vector field equation

E

J

r

r

Conductivity and Conductivity and resistivity

resistivity

E

J

r

r

σ

=

Ohm Ohm’

’s Law vector form

s Law vector form

σ

ρ

Resistance and Resistance and resistivity

resistivity

L A E L A J

)

(

1

r

r

r

r

=

ρ

Scalar Equation

L

V

A

I

=

A

L

I

V

=

IR

V

=

Resistance Resistance

A

R

l

ρ

=

Units:

Units: Ohm = Volt / Ampere

Ohm = Volt / Ampere (

(

Ω Ω

= V / A

= V / A)

)

Sample problem 26 Sample problem 26

4 4

Find resistance ofrectangular block ofiron……

Temperature Dependence of Resistance Temperature Dependence of Resistance

Define temp coefficient of Define temp coefficient of resistivity

resistivity

dT

d

ρ

ρ

α

1

=

If If

α α

is small and constant is small and constant

(

)

[

]

o

o

T

T

=

α

ρ

ρ

1

Units of Units of

α α

is is (

o o

C)
C)

1

Low temperature behavior of Low temperature behavior of

resistance

resistance

Superconductivity

Superconductivity

Semiconductor

Semiconductor

Electric Power Electric Power

dt

d

P

W

=

(

)

dt

qV

d

P

=

dt

dq

V

P

=

VI

P

=

Units: Units: watt = amp

watt = amp

×
×

volt volt

Substituting Substituting

Ohm Ohm’

’s Law

s Law

yields: yields:

R

I

P

2

=

R

V

P

2

=