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The study of Svante August Arrhenius on the temperature dependence of rate constants. data from a reaction between Ethoxide and Methyl iodide studied by Hecht and Conrad in 1889, and examines how the Arrhenius equation can be used to find the constants characteristic of the reaction. graphs and equations to explain the concepts.
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Temp.( oC) Rate (k) Temp. (K) 0 168 273 6 354 627 12 735 1008 18 1463 1736 24 3010 3283 30 6250 6523
y = 1E-12e 0.12x
Absolute Temperature (k)
Reaction rate (K)
In 1889 Arrhenius noted that the reaction rate (k) verses temperature data for many reactions fitted the equation below;
K = Ae -Ea/RT^ ……………………..equation 1.
Where A and Ea are constants characteristic of the reaction. A is the pre- exponential factor (based on the collision factor), Ea is the Arrhenius activation energy in KJ/mol, R is the gas constant and T is the absolute temperature in (K).
Taking logs of equation 1, K = Ae -Ea/RT
Gives; ln K = ln A –Ea/RT …………………………..equation 2. or Log 10 K = Log 10 A – Ea/2.303RT………………………..equation 3.
If the Arrhenius equation is obeyed, a plot of ln K versus 1/T should be a straight line with slope of –Ea/R, and a Y-intercept = ln A. Similarly a plot of Log 10 K verses 1/T would be a straight line with a slope of -Ea/2.303R, and the y-intercept would be Log 10 A. This would enable Ea and A of a reaction to be found. Equation 2 is easier to use, therefore using the given data the ln (k) and 1/T were calculated and the table below was obtained.
Temp.( oC) Temp. (K) 1/T ( oC) Rate (k) ln Rate (ln K) 0 273 0.003663 168 5. 6 279 0.00358423 354 5. 12 285 0.00350877 735 6. 18 291 0.00343643 1463 7. 24 297 0.003367 3010 8. 30 303 0.00330033 6250 8.
A graph of ln (k) verses I/T was plotted as show below: