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An in-depth explanation of the hall effect, a phenomenon where a magnetic field applied to a current-carrying material results in the build-up of an electric field across the material. The theory behind the hall effect, the experimental procedure, and the discussion of the results. Students will learn about the hall voltage, drift velocity, and the relationship between the current, magnetic field, and charge carrier density.
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Keele University Physics/Astrophysics Laboratory 79
1. Introduction
A magnetic field applied to a current carrying material exerts a force on the charge carriers. This leads to build up of an electric field EH (Figure 1) across the material (hence the build up of the potential difference between top and bottom face of the conductor), known as the Hall effect.
2. Theory
Figure 1: Hall Effect (From University Physics, Benson)
I – Current in x -direction; B – Magnetic field in y -direction ( i.e. perpendicular to the slab); vd – Drift velocity; W – Width of the conductor; t – Thickness of the conductor.
FB = q v x B (1)
Due to this force, there will be a net drift of the positive charges towards the top face of the conductor as shown in Figure 1. Assume that the electric field due to this drift is E H (EH = VH/W) and produces a force F E on the charge carriers in the opposite direction to F B and given by:
FE = q EH (2)
As the potential difference (VH) builds up, F E increases until F E ( q EH)= F B ( q vdB). Therefore, since the net force on the charge carrier is zero, this leads to the end of charge migration ( i.e. steady state).
At the steady state:
Keele University Physics/Astrophysics Laboratory 80
q E H = q vd B
EH = vdB
VH/W = vdB
VH = vdBW
It can be shown that the current (I) is given by:
I = nqA v d
A – Cross sectional area of the conductor; I – Current in x -direction; vd – Drift velocity; q – Charge/charge carrier n – Density of the charge carrier
vd = I/ n A q
VH = IBW /n A q
A = W t
VH = IBW /nq W t = IB /nqt
V H = RH IB/t (3) where RH=1/nq or RH=1/ne, q or e – charge on an electron 1.6 x 10-19^ C
3. Experimental Procedure
Set up the Hall Effect apparatus with silver between the pole pieces as shown in Figure 2.
Before performing a measurement with a constant current I the Hall voltage has to be compensated for B = 0 T.
Set the magnetic field B to a desired value with a constant current through the electromagnet.
Measure the Hall voltage UH as a function of the current I.
Remove the Hall Effect apparatus
Measure the magnetic flux density B
Plot a graph U H
against I. Determine the value of RH for silver and compare with the literature value.