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(Inverse function) If y = f(x) has a non-zero derivative at x and the inverse function x = f. -1. (y) is continuous at corresponding point y, then x = f.
Typology: Summaries
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dx
dv
dx
du (u v) dx
d ± = ±
dx
du (cu) c dx
dx
du v dx
dv (uv) u dx
d = +
dx
dv wu dx
du vw dx
dw (uvw) uv dx
d = + +
v
dx
dv u dx
du v
v
u
dx
d
6. (Chain rule) If y = f(u) is differentiable on u = g(x) and u = g(x) is differentiable
on point x, then the composite function y = f(g(x)) is differentiable and
dx
du
du
dy
dx
7. (Chain rule)
dx
dw
dw
du
du
dy
dx
8. (Inverse function) If y = f(x) has a non-zero derivative at x and the inverse function
x = f
dx
dy
dy
9. (Parametric equation) For the equation , f(t) and g(t) are differentiable
and f’(t) ≠ 0, then
y g(t )
x f(t)
dt
dx
dt
dy
dx
dy =.
10. (Parametric equation)
(^33)
2
2
2
2
2
2
(x')
x'y'' x''y'
dt
dx
dt
dy
dt
d x
dt
d y
dt
dx
dx
dx
n n 1 x nx dx
2 x
x dx
2 x
x
dx
d =−
n n 1 x
n
x
dx
d =− +
n n 1
n
n x
x dx
d
−
x x e e dx
18. a a lna dx
19. x x ( 1 lnx) dx
d (^) x x = +
x
lnx dx
xlna
log x dx
d a =
x
loge x
logx dx
d = ≈
23. sinx cosx dx
24. cosx sinx dx
d =−
25. tanx sec x dx
26. secx secxtanx dx
27. cotx csc x dx
d (^2) = −
28. cscx cscxcotx dx
d =−
2
1
1 x
sin x dx
d
−
2
1
1 x
cos x dx
d
−
1
1 x
tan x dx
d
−
x x 1
sec x dx
d
2
1
−
−
1
1 x
cot x dx
d
−
x x 1
csc x dx
d
2
1
−
−
35. sinhx coshx dx
36. coshx sinhx dx
37. tanhx sechx dx
38. cothx csch x dx
d (^2) = −
39. sechx sechxtanhx dx
d =−
40. cschx cschxcothx dx
d =−
2
1 2
1 x
lnx 1 x dx
d sinh x dx
d
−
x 1
1 lnx x 1 dx
d cosh x dx
d 2
1 2 > −
= + − =±
−
43. (^) , x 1 1 x
1 x
1 x ln 2
dx
d tanh x dx
d 2
1 < −
−
44. , x 1 x 1
1
x 1
x 1 ln 2
1
dx
d coth x dx
d 2
1 > −
=−
−
=
−
45. (^) , x 1 x 1 x
sech x dx
d
2
1 < −
−
x x 1
csch x dx
d
2
1
−
47. ln(sinhx) cothx dx
d = , ln(coshx) tanhx dx