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DATE A ‘ \. dy 2 2 + Sy ax t3 ax Solvhon : : . betus-y-2, $3. Then du . dy. 2 dy = du + 2 dx dk 4x dk The Arfferental eqvd hou Yow becomes . du + A= 3 +) : . du (2 dx ; : dx Separate fhe variables and igke the wteqval of both sides dv. dx . (dy 2. fay gy. y +c Lo I. aCy-aat3)"2 = x $C h . il, PWeowere - A(y- 3x 4d) -x = 0 3. Caty-l) de 4 Cu-n- 5) dy = 0 Solution = Twsh, Fuod the whersechon pont of Cty- and _(y-x- 5) OQ: \ On:~\ B= I az | Ci: -\ Ce: -S Re BC, - Baty ys Gai - arCa N. Ob2-G2 By OB, - 428, [5-2 y= 3 ke GNESI OMG!) y= CDECN-CVCS1 —_[ satesect_at 2,3) yd) - CVG) aya) - Cow 4 | : Left xz y-2 and uzvt3 then dx= de and dyz dv 2 EL G-ay t3d-1 dav 4 Lt) (v-a)-s5 J dy = 0 Ps Wty) dv t Way) dy = 0, Zz