Differential Equations Summary: A Flowchart Approach, Slides of Differential Equations

We give a summary of our results about differential equations in the form of a flow chart. We will assume that first order differential equations are either ...

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2022/2023

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Differential Equations Summary
We give a summary of our results about differential equations in the form of a flow chart. We will
assume that first order differential equations are either linear or separable and that second order
differential equations are homogeneous and linear with constant coefficients.
Given:
Differential Equation
First or
Second
Order?
Linear?
Put in Standard Form:
d2y
dx2+pdy
dx +qy = 0
Solve Auxiliary Eq:
m2+pm +q= 0
Put in Standard Form:
dy
dx +p(x)y=q(x)
Put in the Form:
dy
dx =h(x)g(y)
Set Integrating Factor:
µ=eRp(x)dx
General Solution:
y(x) = 1
µ(x)Zµ(x)q(x)dx
Rewrite as:
1
g(y)dy =h(x)dx
Integrate both sides:
Z1
g(y)dy =Zh(x)dx
Let G, H be
antiderivatives
for 1/g, h, respec-
tively
General Solution
(solve for yif possible):
G(y) = H(x) + C
Type of
Roots?
General Solution:
y(x) = c1em1x+c2em2x
General Solution:
y(x) = c1emx +c2xemx
General Solution:
y(x) = eax[c1cos(bx)+c2sin(bx)]
1st order
2nd order
yes
no
distinct real
roots m1, m2
double root m
complex roots a±bi

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Differential Equations Summary

We give a summary of our results about differential equations in the form of a flow chart. We will assume that first order differential equations are either linear or separable and that second order differential equations are homogeneous and linear with constant coefficients.

Given: Differential Equation

First or Second Order?

Linear?

Put in Standard Form: d^2 y dx^2

  • p

dy dx

  • qy = 0

Solve Auxiliary Eq: m^2 + pm + q = 0

Put in Standard Form: dy dx

  • p(x)y = q(x)

Put in the Form: dy dx

= h(x)g(y)

Set Integrating Factor: μ = e

R p(x) dx

General Solution:

y(x) =

μ(x)

μ(x)q(x) dx

Rewrite as: 1 g(y)

dy = h(x) dx

Integrate both sides: ∫ 1 g(y)

dy =

h(x) dx

Let G, H be antiderivatives for 1 /g, h, respec- tively

General Solution (solve for y if possible): G(y) = H(x) + C

Type of Roots?

General Solution: y(x) = c 1 em^1 x^ + c 2 em^2 x

General Solution: y(x) = c 1 emx^ + c 2 xemx

General Solution: y(x) = eax[c 1 cos(bx)+c 2 sin(bx)]

1st order

2nd order

yes

no

distinct real roots m 1 , m 2

double root m

complex roots a ± bi