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Use dimensional analysis (the “factor-label” method) to solve the following problems. Show all steps needed to convert from starting units to ending units.
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miles 1 mile
km
lb
16 oz 1 lb
gal
4 qts 1 gal
Name: Answer Key Period Date
Use dimensional analysis (the “factor-label” method) to solve the following problems. Show all steps needed to convert from starting units to ending units. Indicate all relationships needed before setting up and solving the problem. Use any of the following relationships if needed:
1 mile = 1760 yds 16 oz = 1 lb 1 L = 1.06 qts 1 day = 24 hours 1 yd = 3 ft 2000 lbs = 1 ton 4 qts = 1 gal 1 hour = 60 mins 1 ft = 12 in 1 oz = 28.35 g 32 oz = 1 qt 1 min = 60 secs 1 mile = 1.61 km 1 kg = 2.2 lbs 1 qt = 2 pts
1 (school) year!^
7 hrs 1 day
= 1260 hrs 1 (school) year
Turn over!
1.61 km
1 oz
1.06 qt
180 days
m
m
1000 mg
m
1 kg
1000 g
cm
1 km
Mg
1 m 100 cm 1 m
Instructions:
Complete the following metric equalities. 1 kg = 1000 g 1 km = 1000 m
100 cm = 1 m 1000 mL = 1 L
1000 mm = 1 m 1000 mg = 1 g
1000 ms = 1 s 1 Mg = 10 6 g 1 kL = 1000 L
Convert the measurements below as indicated. You can use scientific notation for very large or small numbers.
40 mL 1 L = 0.040 L (^1 )
7870 mL to L 7870 mL 1 L = 7.87 L (^1 )
5400 L to kL 12) 6.42 m to mm 5400 L (^) 1 kL 6.42 m (^) 1000 mm = 5.4 kL (^)! = 6420 mm (^1) 1000 L 1 1
85 g to kg
1 kg
1850 cm to m 1 m ! = 0.085 kg! = 1.85 m 1 1000 g 1 100 cm
52 mg to g 14) 11.4 km to m
1 g 1
=0.052 g (^)! 1000 m 1
= 11,400 m
6300 m 1 km^ = 6.3 km 3 m^! 1000 mm= 3000 mm (^1 1000 1 )
!
1000 g =2500 g 1
10 6 g ! = 2.5^!^10 7 g (^1 )
!! = 740 mm 1
544 mL 1 L = 0.544 L (^1 1000) 18) 835 mg to kg*
(^1) 1000 mg
1000 g
= 8.35! 10 kg
(^1) 1 L
425 cm ! 1 m 1 = 4.25^ m 100
mL
85 g
52 mg
2.50 kg
18,600 g
mL
mL
1850 cm
11.4 km
25 Mg
74 cm