Solutions to Electromagnetics Workshop: Divergence and Divergence Theorem - Prof. David Ja, Study notes of Electrical and Electronics Engineering

Solutions to problems related to the divergence and divergence theorem in electromagnetics. The problems involve finding expressions for vector fields, charge densities, fluxes, and verifying the divergence theorem.

Typology: Study notes

2013/2014

Uploaded on 06/24/2014

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Electromagnetics Workshop Solutions
Divergence and Divergence Theorem
Problem 1:
Vector field E is characterized by the following properties:
a) E points along
ˆ
r
.
b) The magnitude of E is a function of only the distance from the origin.
c) E vanishes at the origin.
d)
6, E
everywhere.
Find an expression for E that satisfies these properties.
Solution:
ˆ
f rE r
2 2
2 2
1 1 6
r
r E r f r
r r
r r

E
2 2 2 2
6 6r f r r r f r r dr
r
2 3
2r f r r C
2
2C
f r r r
Since E vanishes at the origin
0C
ˆ
2rE r
[V/m]
pf3
pf4
pf5

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Divergence and Divergence Theorem

Problem 1:

Vector field E is characterized by the following properties:

a) E points along r ˆ.

b) The magnitude of E is a function of only the distance from the origin.

c) E vanishes at the origin.

d)

 E 6,

everywhere.

Find an expression for E that satisfies these properties.

Solution:

 

Ef r r

 

   

2 2

2 2

r

r E r f r

r r r r

E

   

 

2 2 2 2

r f r 6 r r f r 6 r dr

r

 

2 3

r f r  2 rC

 

2

C

f r r

r

Since E vanishes at the origin  C  0

 

f r  2 r

E  2 r r

[V/m]

Divergence and Divergence Theorem

Problem 2:

a) The electric field in a free space region is given by

2 3

E  3 yz x  4 y z yz y z [V/m].

What is the charge density in the region, if any?

b) Use a volume integral to find the total charge in the unit cube with one corner at the

origin, one at (1,0,0), another at (0,1,0) and another at (0,0,1).

c) Check your result in part (b) by using a flux integral to compute the charge in the cube.

Solution:

a)  

2

0

V V

 D     yzz y 

 

2 3

0

8 3 C/m

V

  yzz y  

b)  

1 1 1 1

2 2

0 0

0 0 0 0

Qyz z y dxdydzz z dz

 

 

0

C

Q

c)  

1 1 1 1

0 0

0 0 0 0

4z C

Q dSdxdz y dxdy

  

D n

Divergence and Divergence Theorem

Problem 4:

a) Show that the volume charge density corresponding to

2 2

10sin cos

z

  

D      z

is

independent of

and

z.

b) Verify the divergence theorem for D with the cylindrical volume shown below.

x

y

z

a

2

h

2

h

Solution:

a)  

z

V

D

D

D

z

 D

   

2 2

10 sin cos

V

z

z

    

    

2

2

10sin 10

cos

V

3

C/m.

V

b)

/2 2

/2 0 0

h a

V

h

RHS dV d d dz ah

  

 D

side top bottom

LHS   dS   dS   dS

  

D n D n D n

/2 2 2

2 2

/2 0 0 0 /

10sin 2 cos

h a

h a z h

z

LHS d dz d d

 

  

  

LHS  10  ah  10  ah  20  ah

Thus, LHSRHS.

Divergence and Divergence Theorem

Problem 5:

A static electric field in free space is given by

 

   

2 2

ˆ ˆ

Er ˆ 2 r   r sin    r sin  cos

.

Find the volume charge density that produced this electric field.

Solution:

 

v 0

  D   E

In spherical coordinates, we have

 

 

2

2

sin

sin sin

r

E

E r E E

r r r r

where

2

r

Er

E r sin

2

E r sin cos

Hence, we have

 

0

8 2 cos sin [ ]

v

  r    r

3

C / m .