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Oxford Cambridge and RSA Examinations
OCR (Oxford Cambridge and RSA) is a leading UK awarding body, providing a wide range of qualifications to meet the needs of candidates of all ages and abilities. OCR qualifications include AS/A Levels, Diplomas, GCSEs, Cambridge Nationals, Cambridge Technicals, Functional Skills, Key Skills, Entry Level qualifications, NVQs and vocational qualifications in areas such as IT, business, languages, teaching/training, administration and secretarial skills.
It is also responsible for developing new specifications to meet national requirements and the needs of students and teachers. OCR is a not-for-profit organisation; any surplus made is invested back into the establishment to help towards the development of qualifications and support, which keep pace with the changing needs of today’s society.
This mark scheme is published as an aid to teachers and students, to indicate the requirements of the examination. It shows the basis on which marks were awarded by examiners. It does not indicate the details of the discussions which took place at an examiners’ meeting before marking commenced.
All examiners are instructed that alternative correct answers and unexpected approaches in candidates’ scripts must be given marks that fairly reflect the relevant knowledge and skills demonstrated.
Mark schemes should be read in conjunction with the published question papers and the report on the examination.
© OCR 201 9
H032/02 Mark Scheme June 2019
Abbreviations, annotations and conventions used in the detailed Mark Scheme (to include abbreviations and subject-specific conventions). Annotation Meaning
DO NOT ALLOW Answers which are not worthy of credit
IGNORE Statements which are irrelevant
ALLOW Answers that can be accepted
( ) Words which are not essential to gain credit
Underlined words must be present in answer to score a mark
ECF Error carried forward
AW Alternative wording
ORA Or reverse argument
H032/02 Mark Scheme June 2019
Subject-specific Marking Instructions
Your first task as an Examiner is to become thoroughly familiar with the material on which the examination depends. This material includes:
You should ensure that you have copies of these materials.
You should ensure also that you are familiar with the administrative procedures related to the marking process. These are set out in the OCR booklet Instructions for Examiners. If you are examining for the first time, please read carefully Appendix 5 Introduction to Script Marking: Notes for New Examiners.
Please ask for help or guidance whenever you need it. Your first point of contact is your Team Leader.
H032/02 Mark Scheme June 2019
Question Answer Marks
element Guidance 1 (b) Bonding and structure
electrons
Metallic bonding diagram Regular arrangement of labelled + ions
scattering of labelled electrons between other species
Properties linked to explanation metallic bond or attraction between the electrons and the positive ions/cations
bonds are strong/require a lot of energy to break AND high melting point
Delocalised electrons move AND good conductivity
Diagram must have at least two rows and a minimum of two ions per row (allow Sr +^ or Sr 2+)
ALLOW for labels: + ions, positive ions, cations
ALLOW e–^ OR e as label for electron
DO NOT ALLOW intermolecular forces
ALLOW mobile electrons
(c) (i) Sr + 2H 2 O → Sr(OH) 2 + H 2 1 AO2.6 ALLOW correct multiples including fractions IGNORE state symbols
H032/02 Mark Scheme June 2019
Question Answer Marks
element Guidance (c) (ii) Two points () from With calcium:
1. less vigorous fizzing/bubbling/effervescence 2. dissolves more slowly/slower reaction 3. solution has a lower pH/less alkaline 4. precipitate forms/less soluble
IGNORE gives out less/more heat, less reactive, less gas
1 (d) (i) FIRST CHECK THE ANSWER ON ANSWER LINE 3 If answer = 5.8 award 3 marks
n (SrCl 2 ) =
= 0.0102……. (mol)
Calculator: 0.
n (H 2 O) =
= 0.0594……… (mol) Calculator:^ 0. 18
x = SrCl 2 : H 2 O =
0.0594….. (^) ALLOW ECF from n (SrCl 2 ) and/or n (H 2 O)
0.0102…… AO3.2 Answer must be to^ TWO^ significant figures = 5.8 ALLOW 2 marks for 5.83 (answer must be to 2 SF)
H032/02 Mark Scheme June 2019
Question Answer Marks (^) elementAO Guidance 2 (a) Please refer to the marking instructions on page 4 of this 6 AO2.8 (^) Indicative scientific points may include:
Calculation: n =
× 0.4000 = 0.1(000) (mol) 1000
M (Mg(NO 3 ) 2 •6H 2 O) = 256. Mass = 0.1000 × 256.3 = 25.63 g
OR M (Mg(NO 3 ) 2 ) = 148. Mass = 14.83 g
ALLOW small slip/rounding errors such as errors on M r (e.g. use of 24 instead of 24.3 for Mg A r )
Preparation steps (apparatus and method):
IGNORE removing the water of crystallisation
Fine detail:
mark scheme for guidance on how to mark this question. ×
Level 3 (5–6 marks) Calculates the correct mass of Mg(NO 3 ) 2 •6H 2 O or Mg(NO 3 ) 2. AND Explains the preparation steps, with most fine detail.
There is a well-developed line of reasoning which is clear and logically structured. The information presented is relevant and substantiated.
Level 2 (3–4 marks) Attempts a calculation which is partly correct. AND Outlines the preparation steps, with some fine detail.
There is a line of reasoning presented with some structure. The information presented is relevant and supported by some evidence.
Level 1 (1–2 marks) Attempts the calculation but makes little progress or
makes errors. OR Briefly outlines the preparation steps, which may be incomplete
There is an attempt at a logical structure with a line of reasoning. The information is in the most part relevant.
0 marks No response or no response worthy of credit.
H032/02 Mark Scheme June 2019
Question Answer Marks (^) elementAO Guidance 2 (b) FIRST CHECK THE ANSWER ON ANSWER LINE 3 AO2. If answer = 38.5 cm^3 award 3 marks ---------------------------------------------------------------------------
n (Mg(NO 3 ) 2 ) =
= 0.0337 .......... (mol) Calculator : 0.
n (HNO 3 ) = 2 × 0.0337 …….. = 0.0674 .............(mol) ALLOW ECF^ from^ n (Mg(NO^3 )^2 ) Calculator : 0. volume = 0.0674…….. ×
= 38.5 (cm^3 ) 1.75 ALLOW ECF^ from^ n (HNO^3 ) 3 SF required (c)
Element oxidised : Oxygen/O Change from: –2 to 0
Element reduced : Nitrogen/N: Change form + 5 to +4
MAX 1 mark if no ‘+’ sign for oxidation number
ALLOW 2–
ALLOW 5+ AND 4+
ALLOW O 2 for oxygen
ALLOW 1 mark for all oxidation numbers correct, but oxidised and reduced the wrong way around
IGNORE numbers around equation i.e. treat as rough working
Total 11
H032/02 Mark Scheme June 2019
3 (a) (iii) (^) C–I bond is weaker (than C–Br bond) OR C–I bond has a lower bond enthalpy (than C–Br bond)
Carbon – halogen bond breaks
2 AO3.2 For 2 marks, ALLOW C–I is broken more easily (than C–Br) as the bond is weaker
There must be a comparison between C–Br and C–I bonds
(b) (i) (^) Molecular mass (^1) AO1.1 IGNORE ‘relative’ IGNORE ‘molecular ion’ alone, answer must relate to mass
ALLOW M r / molar mass
(ii)
Y : CH 3 CH 2 CH 2 CH 2 CH 2
Z : CH 3 CH 2 CH 2 +^
If positive charge is missing but the structures of Y AND Z are correct, award one mark
ALLOW any combination of skeletal OR structural OR displayed formula as long as unambiguous
(c) (i)
1 AO1.1 ALLOW any combination of skeletal OR structural OR displayed formula as long as unambiguous
(ii) Similarity Both have a peak at ( m / z = ) 198 (X) OR 71 (Y) OR 29
Difference 2-iodo-2-methylbutane has no peak at ( m / z =) 43 (Z)
ALLOW same molecular ion peak / M r
IGNORE statements where no specific ion peak is suggested e.g. “different ion peaks” Total 12
H032/02 Mark Scheme June 2019
Question Answer Marks (^) elementAO Guidance
4 (a) FIRST CHECK THE ANSWER ON ANSWER LINE If answer = 60 cm 3 award 3 marks --------------------------------------------------------------------------- n (HCl) =
× 0.100 = 5.00 × 10–3^ (mol) 1000
n (H ) =
= 2.50 × 10–3^ (mol) 2 2
Volume = 2.5(0) × 10–3^ × 24.0 × 1000 = 60(.0) cm^3
ALLOW 120 cm^3 for 2 marks (no ÷ 2) ALLOW 240 cm^3 for 2 marks (× 2 not ÷ 2)
IGNORE absence of trailing zeroes, e.g. for 0.100, ALLOW 0.
ALLOW ECF from n (HCl)
ALLOW ECF from n (HCl) and/or n (H 2 )
(b) (i) Use of graph paper linear numerical scale chosen for x axis AND Time / s added as label AND ALL points plotted correctly
ALLOW Time (s) OR Time in s ALLOW seconds OR sec OR secs
Tolerance ± 1 small square
Point at 0,0 NOT required ALLOW up to 3 plotting errors
(ii) Anomaly point at 80 s circled
ALLOW one more anomalous point NOT on the curve drawn in (iii)
(iii) Line smooth curve using all points EXCEPT point at 80 s
(c) Initial slope is steeper AND curve levels off at an earlier time
Same volume of gas produced (58 cm^3 )
Tolerance ± 1 small square
H032/02 Mark Scheme June 2019
Question Answer Marks AO element
Guidance
5 (a) (i) Product with H 2 H H H H H H
ALLOW any combination of skeletal OR structural OR displayed formula as long as unambiguous
H C C C C C C H ALLOW^ part molecular formulae but not full
Product with HCl
H H H H H H
H H H H Cl H (^)
Product with Br (^2)
H H H H H H
H H H H Br Br (^)
(ii) Nickel/Ni 1 AO1.2 ALLOW Pt OR Pd OR Rh
(iii) (orange to) colourless OR bromine is decolourised
1 AO1.2 ALLOW ‘it decolourises / turns colourless’ IGNORE colour change
H032/02 Mark Scheme June 2019
Question Answer Marks AO element
Guidance
5 (b) (i) Please refer to the marking instructions on page 4 of this (^6) Indicative scientific points may include: Calcul ation from moles n (hex-1-ene) = 4.20 = 0.0500 (mol)
n (hexan-1-ol) needed = 0.0500 × 100 = 0.0800 (mol)
mass needed = 0.0800 × 102 = 8.16 g (^) OR volume 8.16 = 9.95 cm 3
CHECK for extent of errors by ECF. Calculation from mass Theoretical mass hex-1-ene = 4.20 × 100 = 6.72 g
Theoretical n (hex-1-ene) = 6.72 = 0.0800 (mol) 84 Mass of hexan-1-ol = 102 × 0.0800 = 8.16 g ALLOW small slip/rounding errors such as errors on M r (e.g. use of 83 instead of 84 for hex-1-ene M r )
Purification Use of a separating funnel to separate organic and aqueous layers Drying with an anhydrous salt Distillation
Fine detail Collection of upper layer (less dense from separating funnel) Example of drying agent, e.g. MgSO 4 , CaC l 2 Collection of fraction distilling at 63ºC (boiling point of hex-1-ene) Incorrect purification method NOT creditworthy
Examples of partly correct calculations Mass = 5.1 g from 0.0500 × 102 % yield omitted Mass = 3.1875 g from 0.0500 × 62.5^ × 102 % yield inverted 100
mark scheme for guidance on how to mark this question. AO2. × Level 3 (5–6 marks) Calculates the correct mass of hexan-1-ol. AND Explains the purification steps, with most fine detail.
There is a well-developed line of reasoning which is clear and logically structured. The information presented is relevant and substantiated.
Level 2 (3–4 marks) Attempts a calculation of the mass of hexan- 1 - ol which is partly correct. OR Outlines the purification steps, with some fine detail.
There is a line of reasoning presented with some structure. The information presented is relevant and supported by some evidence.
Level 1 (1–2 marks) Attempts the calculation but makes little progress. OR Briefly outlines the purification steps, which may be incomplete.
There is an attempt at a logical structure with a line of reasoning. The information is in the most part relevant.
0 marks No response or no response worthy of credit.
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