MATH 2210: Double Integrals using Polar Coordinates - Solutions to Problems 29 and 31 - Pr, Assignments of Mathematics

The solutions to problem 29 and 31 from the math 2210 course on double integrals using polar coordinates. Problem 29 involves calculating the volume of a pool given its equation of the bottom and the region of integration as a circle. Problem 31 deals with the combination of three integrals forming the region of integration. The equations and the steps to solve each problem.

Typology: Assignments

Pre 2010

Uploaded on 07/30/2009

koofers-user-hpb
koofers-user-hpb 🇺🇸

9 documents

1 / 2

Toggle sidebar

This page cannot be seen from the preview

Don't miss anything!

bg1
MATH 2210 12.4 Double Integrals using Polar Coordinates
Solutions to selected homework problems
Problem 29: Let the top of the pool lie in the xy plane and let the shallow end correspond
to x = -20 and the deep end be x = 20. The slope of the bottom of the pool is
8
1
40
5
so the equation of the bottom is
2
9
8
1 xz
and the region of integration is the circle
222
20 yx
. Using polar coordinates, the volume is given by
3
2
0
2
0
2
0
20
0
20
0
23
2
0
20
0
2
0
20
0
ft1800
900sin
3
1000
900cos
3
1000
4
9
cos
24
1
2
9
cos
8
1
2
9
8
1
0
d
drr
ddrrr
xzddrrzV
pf2

Partial preview of the text

Download MATH 2210: Double Integrals using Polar Coordinates - Solutions to Problems 29 and 31 - Pr and more Assignments Mathematics in PDF only on Docsity!

MATH 2210 12.4 Double Integrals using Polar Coordinates

Solutions to selected homework problems

Problem 29: Let the top of the pool lie in the xy plane and let the shallow end correspond

to x = -20 and the deep end be x = 20. The slope of the bottom of the pool is

so the equation of the bottom is

z  x  and the region of integration is the circle

2 2 2

x  y  20. Using polar coordinates, the volume is given by

3

2

0

2

0

2

0

20

0

20

0

3 2

2

0

20

0

2

0

20

0

1800 ft

sin 900

3

cos 900

3

cos

24

cos

8

 

 

 

 

d

r r d

r rdr d

V zrdrd z x

sin

2

sin cos

cos sin

2

1

4

4

0

2

2

1

4 3

0

4

0

2

1

2

2

4

0

2

1 0

1

2

(^1 )

2

2

 

       

r

d r dr

xydy dx xydydx xydydx r r rdr d

x x x

x

Problem 31: The three integrals combine to form the region

So we have