JEE
Lakshya JEE (2026)
Q1 A generator produces a voltage that is given by
, where is in seconds. The
frequency and r.m.s. voltage are
(A) and
(B) and
(C) and
(D) and
Q2 Voltage and current in an ac circuit are given by
and
(A)Voltage leads the current by
(B)Current leads the voltage by
(C)Current leads the voltage by
(D)Voltage leads the current by
Q3 The voltage of an ac source varies with
timeaccording to the equation
where is in
seconds and is in volts. Then
(A)The peak voltage of the source is 100 volts
(B)The peak voltage of the source is 50 volts
(C)The peak voltage of the source is
volts
(D)The frequency of the source is
Q4 In a certain circuit current changes with time
according to . r.m.s. value of current
between to will be
(A)
(B)
(C)
(D)
Q5 The mean value of current for one complete
cycle of shown current supply is
(A)
(B)
(C)
(D)Zero
Q6 The r.m.s. voltage of the wave form shown is
(A)
(B)
(C)
(D)None of these
Q7 An alternating voltage is connected in series with
a resistance and an inductance If the
potential dropacross the resistance is and
across the inductance is , then the applied
voltage is
(A)
(B)
(C)
(D)
Q8 In an ac circuit, the reactance of the coil is
times its resistance, the phase difference
between the voltage across the coil to the
current through the coil will be
(A) (B)
(C) (D)
Q9
Physics
Alternating Current
Total Duration- 20 Min
DPP: 3
v
= 240sin120
t
t
60Hz 240V
19Hz 120V
19Hz 170V
754Hz 70V
V = 5sin
(
100
π
t −
)
π
6
I = 4sin
(
100
π
t +
)
π
6
30
∘
30
∘
60
∘
60
∘
V
= 100sin100
πt
cos100
πt
t
V
100/
2
–
√
50Hz
i
= 2
t
√
t
= 2
t
= 4s
3A
3 A
3
–
√
2 A
3
–
√
(2 − )A
2
–
√
2
l
0
π
3
l
0
4
l
0
2
10V
7V
6.37V
R L
200V
150V
350V
250V
500V
300V
3
–
√
π
/3
π
/2
π
/4
π
/6
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