EGR271 lab 5 Thevenin, Lab Reports of Electrical Engineering

EGR271 lab 5 Thevenin circuit analysis.

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2023/2024

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Loudoun Campus
MSTB division
EGR271: Circuits I Laboratory
Lab #5
Superposition Technique
Thevenin / Norton Theorems
Submit this completed worksheet as a pdf to Canvas/Assignment!
By completing this worksheet, you certify that you will neither give nor receive unauthorized aid.
Note: Always include the units for all of your measurements / calculations!
This lab experiment will familiarize students with Thevenin / Norton theorems.
1. Superposition Technique
Handy Analysis:
pf3
pf4
pf5

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Loudoun Campus MSTB division

EGR271: Circuits I Laboratory

Lab # 5 Superposition Technique Thevenin / Norton Theorems Submit this completed worksheet as a pdf to Canvas/Assignment! By completing this worksheet, you certify that you will neither give nor receive unauthorized aid. Note: Always include the units for all of your measurements / calculations! This lab experiment will familiarize students with Thevenin / Norton theorems.

1. Superposition Technique - Handy Analysis:

a. For the circuit above, use superposition technique to find the voltage labeled 𝑣𝑥 in the circuit below. Isolating voltage source 1: Solving for I1: Req = 3 + 1 + (1/5 + ½)^- 1 Req = 38/7 or 5.43 Ohm I = v1/req I = 4/(38/7) = 1 4/19 or 0.7 3 7 A Voltage R2 = 0.747 * 1 = 0.7 3 7 V Isolating voltage source 2: Solving for i2: Req = 2 + (1/5 + (1/4)^- 1 Req = 38/9 or 4.22 Ohm I = v2/req I = 4/(38/9) = 18/19 or 0.947 A Voltage R2 = 5/(5+4) * A Voltage R2 = 0.526 * - 1 = - 0.526V Isolating current source 1: Using nodal to find voltage on nodes surrounding R2: Node 1 (left of R2): 2 = (v1)/3 + (v1-v2) 2= v1(4/3) – v Node 2(right of R2): 0 = (v2-v1) + (v2)/5 + (v2)/ 0 = - 10v1 + 17v After matrix calculation: V1 = 2.68 4 & V2= 1.5 79 Therefore voltage through R2 = v1-v Voltage R2 = 1.1 05 V Vx = V1 + V2 + V Vx = 0.7 37 – 0.526 + 1.1 05 Vx = 1.316 V

b. Verify your handy work? Yes.

  1. Thevenin / Norton Theorem.
    • Handy Analysis a. For the circuit above, Employ Thevenin / Norton’s theorem to reduce the network connected to 𝑅𝐿 to only two components. Finding R total: Rt = ((1/r1 + r2) + (1/r 3 ) + (1/r4)^- 1 Rt = 800 Ohm Finding I total: Ia = i1(r2/r1+r2) Ib = V1/r Ia = 0.175 A Ib = 0.0025 A Itotal = iA+iB It = 0.1775 A

b. Calculate the downward directed current flowing through 𝑅𝐿 if it is a 3 .3 k Ω

resistor. I(rl) = It *(Rt/Rl + rt) I(rl) = 0.1775 * (800/ 4100 ) I(rl) = 0.03463 A or 34.63 mA

Your assignment: 1 - Make sure that you saved your MultiSim design as Lab# 5 _Your Name and must be shown in your screenshot as a signature. 2 - Make sure that your Lab# 5 doc file will be like this doc with your Full Name & your Student ID then upload a pdf version of your doc file into Canvas- Assignments-Lab# 5 before the due date/time. Each 24 hours delay is subject to 20% grade penalty. Submission after 48hours delay is not accepted.