Eigenvalues and Eigenvectors: Finding the Largest Eigenvalue using the Power Method, Slides of Mathematical Methods for Numerical Analysis and Optimization

The concept of eigenvalues and eigenvectors, and how to find the largest eigenvalue and its corresponding eigenvector using the power method. It includes an example calculation and a discussion on the applicability of the power method for real and distinct eigenvalues.

Typology: Slides

2011/2012

Uploaded on 08/05/2012

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Download Eigenvalues and Eigenvectors: Finding the Largest Eigenvalue using the Power Method and more Slides Mathematical Methods for Numerical Analysis and Optimization in PDF only on Docsity!

Let [

A ] be an

n x n

square matrix.

Suppose, there exists a scalarand a vectorsuch that

1 2 (^

T ) n

X^

x^ x

x

^

[^

](^

)^

(^

)

A^

X^

X 

(^

)^

(^

)

ax^

ax

d^

e^

a e

dx

 2

2

(sin 2

)

(sin

)

d^

ax^

a^

ax

dx^

 

This represents a set of

n

homogeneous equationspossessing non-trivialsolution, provided

0

A^

I  ^

This determinant, onexpansion, gives an n-thdegree polynomial which iscalled characteristicpolynomial of [

A ], which has

n

roots. Corresponding to eachroot, we can solve theseequations in principle, anddetermine a vector calledeigenvector.

Power MethodPower MethodJacobi’s MethodJacobi’s Method

Note!We shall consideronly real and real-symmetric matricesand discuss powerand Jacobi’s methods

To compute the largest eigenvalue and the correspondingeigenvector of the systemwhere [

A ] is a real, symmetric or un-symmetric matrix, thepower method is widely usedin practice.

[^ ](

)^

(^ ) A^ X

X  

ProcedureStep 1: Choose the initial vectorsuch that the largest element isunity.Step 2: The normalized vectoris pre-multiplied by the matrix[ A ].

(0) v docsity.com

At this point, the result looks likeHere,

is the desired largest eigen value and

is the ( corresponding eigenvector. )^

(^ 1)

(^ )

[^ ] k^

k^

k k

u^

A v

q v  ^

q^ k

(^ ) k v

ExampleFind the eigen value of largestmodulus, and the associatedeigenvector of the matrix bypower method

2 3

2 [^ ]^

4 3

5 3 2

9 A

^

 ^

  ^

 ^

 ^

Now we normalize theresultant vector to get

1 2 (1)^

(1) 6

1 7 14

1

u^

q v ^  ^  ^

 ^  ^  ^ 

The second iteration gives,

39 1 2

7

(2)^

(1)^

6

67 7

(^717114) (2) 2

2 3

[^ ]^

u^

A v

^ q v

^ 

^

^

^ 

^ 

^

^

 ^

^ 

^

 ^ ^

^ 

^

^

 ^ ^

^ 

^

^

^

^

^

^