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In an ELASTIC collision, energy is conserved (KEbefore = KEafter or Ki = Kf). In an INELASTIC collision, energy is NOT conserved. (Ki > Kf). Example: A 1 kg ...
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In an ELASTIC collision, energy is conserved (KEbefore = KEafter or Ki = Kf).
In an INELASTIC collision, energy is NOT conserved. (Ki > Kf).
Example: A 1 kg block which is sliding at 10 m/s across a frictionless surface suddenly collides with a stationary 2 kg block. They stick together and they move towards an inclined plane of angle 37 o. How far up the incline will they move? Was the collision elastic or inelastic?
Example: A 10 kg pendulum bob is hanging at rest at the end of a 4 meter long rope. A 500 gram ball is thrown horizontally at the pendulum bob with a speed of 5.0000 m/s. It strikes the pendulum bob, and them bounces straight backward at a speed of 4.5238 m/s. What angle will the pendulum bob swing through? Was the collision elastic or inelastic?
Conservation of Momentum:
Conservation of Energy:
1 2
m 1 v 1 i 2
1 2
m 2 v 2 i 2
1 2
m 1 v 1 f 2
1 2
m 2 v 2 f 2
Put the two equations together (carefully and with many steps ) and you get the following equations.
v 1 f
m 1 m 2 m 1 m 2
v 1 i ^
2 m 2 m 1 m 2
v 2 i
v 2 f
2 m 1 m 1 m 2
v 1 i ^
m 1 m 2 m 1 m 2
v 2 i
With these equations, we can find BOTH velocities of the balls after the collision by just
Special Case: If v2i = 0, then what happens when …..
a) m 1 (^) m 2 ___________________________________________________
b) m 1 (^) m 2 ___________________________________________________
c) m 1 (^) m 2 ___________________________________________________
d) m 1 (^) m 2 ___________________________________________________
e) m 1 (^) m 2 ___________________________________________________
v 1 i v 1 f
m 1 m 2 m 1 m 2
v2i
v2f